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2009 Math Kangaroo

Problem 19

Problem 19 · 2009 Math Kangaroo Hard
Geometry & Measurement symmetry

The diagram shows a regular nonagon. What is the size of the angle marked X?

Figure for Math Kangaroo 2009 Problem 19
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Answer: E — 60°
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Hint 1 of 2
Each interior angle of a regular nonagon is 140 degrees; the marked angle is where two extended sides meet.
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Hint 2 of 2
Outside the nonagon those sides form an isosceles triangle - use its equal base angles.
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Approach: angle-chase the external triangle
  1. A regular nonagon has 140 degree interior angles, so each side turned outward makes 40 degrees.
  2. The two extended sides form an isosceles triangle outside the nonagon whose equal base angles are each 60 degrees.
  3. So X = 180 - 60 - 60 = 60 degrees.
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