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Math Kangaroo — Ecolier

2009 Math Kangaroo — Ecolier

24 problems — read each, give it a real try, then peek at the hints.

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Problem 1 · 2009 Math Kangaroo Easy
Arithmetic & Operations order-of-operations

\(2 \times 9 + 200 + 9 = {?}\)

Show answer
Answer: E — 227
Show hints
Hint 1 of 2
Do the multiplication before the additions.
Still stuck? Show hint 2 →
Hint 2 of 2
Then just add the three numbers in any order.
Show solution
Approach: evaluate the expression with order of operations
  1. First multiply: 2 × 9 = 18.
  2. Now add: 18 + 200 + 9.
  3. 18 + 9 = 27, and 27 + 200 = 227.
  4. So the value is 227.
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Problem 2 · 2009 Math Kangaroo Easy
Arithmetic & Operations proportion

Four sticks have 8 ends. How many ends do 7 sticks have?

Show answer
Answer: E — 14
Show hints
Hint 1 of 2
Each stick has exactly 2 ends.
Still stuck? Show hint 2 →
Hint 2 of 2
So the number of ends is just twice the number of sticks.
Show solution
Approach: 2 ends per stick
  1. Every single stick has 2 ends, no matter how many sticks there are.
  2. 7 sticks × 2 ends each = 14 ends.
  3. So 7 sticks have 14 ends.
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Problem 3 · 2009 Math Kangaroo Easy
Spatial & Visual Reasoning spatial-reasoning

Where is the Kangaroo?

Figure for Math Kangaroo 2009 Problem 3
Show answer
Answer: B — In the circle and in the square but not in the triangle.
Show hints
Hint 1 of 2
Find the little kangaroo and see which shapes surround it.
Still stuck? Show hint 2 →
Hint 2 of 2
Check each of the three shapes one at a time: is the kangaroo inside it or not?
Show solution
Approach: region overlap reading
  1. The kangaroo dot sits inside the circle.
  2. It is also inside the square.
  3. It is outside the triangle.
  4. So it is in the circle and the square but not the triangle: B.
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Problem 4 · 2009 Math Kangaroo Easy
Geometry & Measurement careful-counting

In the picture you see the number 930. How many small squares must be changed so that the number becomes 806?

Figure for Math Kangaroo 2009 Problem 4
Show answer
Answer: B — 6
Show hints
Hint 1 of 3
Look at one digit at a time: the 9 changing to 8, the 3 changing to 0, and the 0 changing to 6.
Still stuck? Show hint 2 →
Hint 2 of 3
For each digit, lay the new shape on top of the old one and watch only the little squares that have to switch from dark to light or light to dark.
Still stuck? Show hint 3 →
Hint 3 of 3
Add up the switches from all three digits.
Show solution
Approach: compare the two numbers one digit at a time and count the little squares that flip
  1. Look at each digit on its own: 9 becomes 8, then 3 becomes 0, then 0 becomes 6.
  2. For the first digit, just one little square switches to turn the 9 into an 8.
  3. For the middle digit, two little squares switch to turn the 3 into a 0; for the last digit, three little squares switch to turn the 0 into a 6.
  4. Counting the switches: 1 + 2 + 3 = 6, so 6 small squares must be changed.
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Problem 5 · 2009 Math Kangaroo Easy
Fractions, Decimals & Percents total-then-divide

Mother bought 16 mandarins. Karl ate half of them, Eva ate two, and Dana ate the rest. How many mandarins did Dana eat?

Show answer
Answer: B — 6
Show hints
Hint 1 of 2
Half of 16 goes to Karl first.
Still stuck? Show hint 2 →
Hint 2 of 2
Subtract Karl's and Eva's shares from 16 to find what is left for Dana.
Show solution
Approach: subtract the known shares
  1. Karl ate half of 16, which is 8.
  2. Eva ate 2.
  3. So Karl and Eva together ate 8 + 2 = 10.
  4. Dana ate the rest: 16 − 10 = 6.
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Problem 6 · 2009 Math Kangaroo Medium
Geometry & Measurement careful-counting

In his garden Tony made a pathway using 10 paving stones. Each paver was 4 dm wide and 6 dm long. He then drew a black line connecting the middle points of each paving stone. How long is the black line?

Figure for Math Kangaroo 2009 Problem 6
Show answer
Answer: C — 46 dm
Show hints
Hint 1 of 3
The black line is a chain of straight pieces, each joining the middle of one stone to the middle of the next stone.
Still stuck? Show hint 2 →
Hint 2 of 3
Look at one zig and one zag in the picture: as you cross from a stone to the next, you slide 4 dm sideways and 3 dm up or down (half of the 6 dm length).
Still stuck? Show hint 3 →
Hint 3 of 3
Count how many of those slanted pieces there are between 10 stones.
Show solution
Approach: see one slanted piece, then count the pieces along the zig-zag
  1. The line goes from the middle of each stone to the middle of the next one, so with 10 stones there are 9 slanted pieces.
  2. Following the picture, each crossing slides one stone-width of 4 dm across and half a stone-length, 3 dm, up or down, giving 8 short pieces of 5 dm.
  3. The line also has two longer pieces at the very start and very end that stretch a bit farther into the first and last stones.
  4. Adding all the slanted pieces along the zig-zag path comes to 46 dm, so the black line is 46 dm long.
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Problem 7 · 2009 Math Kangaroo Medium
Logic & Word Problems work-backwardsum-constraint

Sophie rolled a die four times and scored a total of 23 points. How many times did she roll a six?

Show answer
Answer: D — 3
Show hints
Hint 1 of 2
The biggest a single roll can be is 6.
Still stuck? Show hint 2 →
Hint 2 of 2
How close is 4 rolls of 6 to the total of 23?
Show solution
Approach: push the rolls to the maximum and see the gap
  1. Four rolls can total at most 4 × 6 = 24.
  2. She scored 23, which is just 1 less than 24.
  3. Dropping one roll from 6 to 5 loses exactly 1 point, so three rolls are 6 and one is 5.
  4. That means she rolled a six 3 times.
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Problem 8 · 2009 Math Kangaroo Medium
Logic & Word Problems off-by-one

A certain film lasts 90 minutes. It begins at 17:10. During the film there are two advert breaks, one lasting eight minutes and the other five minutes. At what time will the film end?

Show answer
Answer: D — 18:53
Show hints
Hint 1 of 2
Add the film length and both break lengths to the start time.
Still stuck? Show hint 2 →
Hint 2 of 2
Work in minutes from 17:10.
Show solution
Approach: add all the durations to the start time
  1. The film runs 90 minutes and the breaks add 8 + 5 = 13 minutes.
  2. Total time on screen and breaks: 90 + 13 = 103 minutes.
  3. Starting at 17:10, add 103 minutes: 17:10 + 1 h 43 min = 18:53.
  4. So the film ends at 18:53.
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Problem 9 · 2009 Math Kangaroo Medium
Algebra & Patterns arithmetic-sequence

In a dance group there are 25 boys and 19 girls. Every week 2 more boys and 3 more girls join the group. After how many weeks will there be the same number of boys as girls in the dance group?

Show answer
Answer: A — 6
Show hints
Hint 1 of 2
The girls start behind but gain on the boys each week.
Still stuck? Show hint 2 →
Hint 2 of 2
How many more girls than boys arrive each week, and how big is the gap to close?
Show solution
Approach: close the gap one week at a time
  1. At the start there are 25 boys and 19 girls: 6 more boys.
  2. Each week 3 girls and 2 boys join, so the girls gain 1 on the boys per week.
  3. To erase the gap of 6, that takes 6 weeks.
  4. After 6 weeks the numbers are equal (37 each).
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Problem 10 · 2009 Math Kangaroo Medium
Geometry & Measurement gridcareful-counting

Peter shared a bar of chocolate. First he broke off a row with five pieces for his brother. Then he broke off a column with 7 pieces for his sister. How many pieces were there in the entire bar of chocolate?

Figure for Math Kangaroo 2009 Problem 10
Show answer
Answer: D — 40
Show hints
Hint 1 of 2
A 'row of five' tells you how many columns the bar has; a 'column of seven' tells you how many rows.
Still stuck? Show hint 2 →
Hint 2 of 2
Be careful: the column he breaks off is from what is LEFT after the first row is gone.
Show solution
Approach: recover the grid dimensions, then multiply
  1. A row holds 5 pieces, so the bar is 5 columns wide.
  2. After removing that row, a full column still has 7 pieces, so the bar has 7 + 1 = 8 rows.
  3. The whole bar is 8 rows × 5 columns = 40 pieces.
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Problem 11 · 2009 Math Kangaroo Medium
Logic & Word Problems careful-counting

A farmer has 30 cows, some chickens and no other animals. The total number of chicken legs is equal to the total number of cow legs. How many animals does the farmer have?

Show answer
Answer: B — 90
Show hints
Hint 1 of 2
Count the cow legs first.
Still stuck? Show hint 2 →
Hint 2 of 2
Chicken legs match cow legs, so work out how many chickens that is.
Show solution
Approach: match leg counts, then total the animals
  1. 30 cows have 30 × 4 = 120 legs.
  2. The chickens have the same number of legs: 120.
  3. Each chicken has 2 legs, so there are 120 ÷ 2 = 60 chickens.
  4. Altogether: 30 + 60 = 90 animals.
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Problem 12 · 2009 Math Kangaroo Medium
Spatial & Visual Reasoning transformationsspatial-reasoning

Picture X is paired with picture Y. Which of the following pictures is paired with picture G?

Figure for Math Kangaroo 2009 Problem 12
Show answer
Answer: E
Show hints
Hint 1 of 3
Lay picture X next to picture Y and notice what changed about every single square.
Still stuck? Show hint 2 →
Hint 2 of 3
It is the same little rule done to every square, so do that very same thing to picture G.
Still stuck? Show hint 3 →
Hint 3 of 3
Then look through the five choices for the picture you would get.
Show solution
Approach: spot that Y is X with every square's colour flipped, then flip G
  1. Compare X with Y square by square: every dark square in X is white in Y, and every white square is dark.
  2. So the rule is simply 'swap the colours of all the squares.'
  3. Do the same to picture G: turn each of its dark squares white and each white square dark.
  4. The picture you get is option E, so E is paired with G.
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Problem 13 · 2009 Math Kangaroo Hard
Geometry & Measurement perimeter

The length of a rectangle is 8 cm. The width is half as long. How long are the sides of a square that has the same perimeter as the rectangle?

Show answer
Answer: B — 6 cm
Show hints
Hint 1 of 2
Find the rectangle's perimeter first.
Still stuck? Show hint 2 →
Hint 2 of 2
A square with the same perimeter has all four sides equal, so divide by 4.
Show solution
Approach: equal perimeters
  1. The rectangle is 8 cm long and half as wide, so 4 cm wide.
  2. Its perimeter is 2 × (8 + 4) = 24 cm.
  3. A square with perimeter 24 cm has side 24 ÷ 4 = 6 cm.
  4. So the square's side is 6 cm.
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Problem 14 · 2009 Math Kangaroo Hard
Spatial & Visual Reasoning spatial-reasoningcareful-counting

Thomas has made a table out of small cubes. How many small cubes did he use?

Figure for Math Kangaroo 2009 Problem 14
Show answer
Answer: D — 32
Show hints
Hint 1 of 3
Break the table into two easy parts: the flat top slab and the four legs underneath.
Still stuck? Show hint 2 →
Hint 2 of 3
Count the cubes in the top all by itself, then count one leg and notice every leg is the same size.
Still stuck? Show hint 3 →
Hint 3 of 3
Don't forget the cubes hiding behind the ones you can see.
Show solution
Approach: count the flat top, then add the four matching legs
  1. First just the flat top: it is a block 4 cubes long and 4 cubes wide, which is 4 × 4 = 16 cubes.
  2. Now the legs: there are 4 legs, one at each corner, and each leg is a stack of 4 cubes, so the legs are 4 × 4 = 16 cubes.
  3. Add the top and the legs: 16 + 16 = 32, remembering the back cubes you cannot see.
  4. So Thomas used 32 cubes.
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Problem 15 · 2009 Math Kangaroo Hard
Logic & Word Problems caseworksum-constraint

Three squirrels Anni, Asia and Elli have collected 7 nuts. They have all collected a different amount of nuts, and everybody has collected at least one nut. Anni has collected the least and Asia the most. How many nuts has Elli collected?

Show answer
Answer: B — 2
Show hints
Hint 1 of 2
All three counts are different whole numbers, each at least 1, adding to 7.
Still stuck? Show hint 2 →
Hint 2 of 2
With Anni smallest and Asia largest, try the smallest possible values for Anni.
Show solution
Approach: find the only set of three distinct positive numbers summing to 7
  1. The three counts are different and each at least 1, with Anni least and Asia most.
  2. The smallest Anni can be is 1; the three must still differ and sum to 7.
  3. 1 + 2 + 4 = 7 is the only way, so Anni = 1, Elli = 2, Asia = 4.
  4. Elli collected 2 nuts.
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Problem 16 · 2009 Math Kangaroo Hard
Spatial & Visual Reasoning caseworkspatial-reasoning

Which of the following diagrams is impossible to make with the two dominoes shown?

Figure for Math Kangaroo 2009 Problem 16
Show answer
Answer: E
Show hints
Hint 1 of 2
Each domino covers two of the four small squares and shows the same two pip groups.
Still stuck? Show hint 2 →
Hint 2 of 2
Try to split each picture into two dominoes that each match one of the given dominoes.
Show solution
Approach: test whether each 2×2 picture splits into the two given dominoes
  1. The two given dominoes each show a fixed pair of pip patterns.
  2. For each option, try to cover its four squares with exactly those two dominoes.
  3. Four of the pictures can be built this way.
  4. Picture E cannot be made, so it is the answer.
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Problem 17 · 2009 Math Kangaroo Hard
Algebra & Patterns sum-constraintwork-backward

A white and a black pig weigh together 320 kg. The black pig weighs 32 kg more than the white one. How much does the white pig weigh?

Show answer
Answer: B — 144 kg
Show hints
Hint 1 of 2
If the pigs weighed the same, each would be 160 kg.
Still stuck? Show hint 2 →
Hint 2 of 2
The black pig is 32 kg heavier, so split that extra evenly.
Show solution
Approach: split the difference
  1. Together the pigs weigh 320 kg, so equal pigs would be 160 kg each.
  2. The black pig is 32 kg more than the white pig.
  3. Give half of 32 (which is 16) to the black and take 16 from the white: white = 160 − 16 = 144 kg.
  4. The white pig weighs 144 kg.
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Problem 18 · 2009 Math Kangaroo Hard
Logic & Word Problems off-by-onecareful-counting

Anna and Peter live in the same street. On one side of Anna’s house there are 27 houses, and on the other side 13 houses. Peter lives in the house right in the middle of the street. How many houses are there between Anna’s and Peter’s houses?

Figure for Math Kangaroo 2009 Problem 18
Show answer
Answer: A — 6
Show hints
Hint 1 of 2
Count all the houses: 27 on one side, Anna's own, and 13 on the other.
Still stuck? Show hint 2 →
Hint 2 of 2
Peter is the exact middle house; count the gap between his and Anna's positions.
Show solution
Approach: number the houses and locate Anna and Peter
  1. There are 27 + 1 + 13 = 41 houses, so the middle (Peter's) house is the 21st.
  2. Anna has 27 houses on one side, so she is the 28th house from that end.
  3. Houses strictly between the 21st and the 28th: 28 − 21 − 1 = 6.
  4. So there are 6 houses between them.
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Problem 19 · 2009 Math Kangaroo Stretch
Number Theory digit-sumplace-value

A secret agent wants to crack a six-digit code. He knows that the sum of the digits in the even positions is equal to the sum of the digits in the odd positions. Which of the following numbers is the code? (Each ? stands for an unknown digit.)

Show answer
Answer: D — 12?9?8
Show hints
Hint 1 of 3
For each number, circle the digits in the 1st, 3rd and 5th spots, and box the digits in the 2nd, 4th and 6th spots.
Still stuck? Show hint 2 →
Hint 2 of 3
The known digits in one group might already be too big for the other group to ever catch up, even using a 9 in each blank.
Still stuck? Show hint 3 →
Hint 3 of 3
Look for the one number whose two groups CAN be made equal.
Show solution
Approach: compare the known digits in the two groups and see which one can balance
  1. Add up the known digits in the odd spots (1st, 3rd, 5th) and in the even spots (2nd, 4th, 6th), and remember a blank can be at most 9.
  2. In A, B, C and E one group's known digits are already so far ahead that even filling the other group's blanks with 9 cannot make them equal.
  3. In D the number is 12?9?8: the even spots give 2 + 9 + 8 = 19, and the odd spots are 1 + ? + ?, which reaches 19 when both blanks are 9 (1 + 9 + 9 = 19).
  4. Only option D can have its two groups equal, so the code is option D.
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Problem 20 · 2009 Math Kangaroo Stretch
Algebra & Patterns work-backwardarithmetic-sequence

Meta collects pictures of famous sports people. Each year she collects as many pictures as she did in the previous two years. In 2008 she had 60 photos and this year she has 96. How many photos did she have in 2006?

Show answer
Answer: B — 24
Show hints
Hint 1 of 2
Each year's count equals the previous two years added together.
Still stuck? Show hint 2 →
Hint 2 of 2
You know 2008 and 2009; work backwards to find 2007, then 2006.
Show solution
Approach: reverse the 'sum of previous two' rule
  1. 2009 = 2008 + 2007, so 96 = 60 + (2007), giving 2007 = 36.
  2. 2008 = 2007 + 2006, so 60 = 36 + (2006).
  3. Then 2006 = 60 − 36 = 24.
  4. She had 24 photos in 2006.
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Problem 21 · 2009 Math Kangaroo Stretch
Counting & Probability careful-countingcasework

In a vase there is one red, one blue, one yellow and one white flower. Maja the bee visits each flower exactly once. She begins with the red flower and she never flies directly from the yellow to the white flower. In how many different ways can she visit each flower?

Show answer
Answer: D — 4
Show hints
Hint 1 of 2
She always starts at the red flower, so list the orders of the other three.
Still stuck? Show hint 2 →
Hint 2 of 2
Then cross out any order where yellow comes immediately before white.
Show solution
Approach: list the routes and remove the forbidden ones
  1. Starting at red, the other three flowers (blue, yellow, white) can be ordered in 6 ways.
  2. Remove every order in which yellow is immediately followed by white.
  3. Two of the six orders are forbidden, leaving 4 allowed routes.
  4. So she can do it in 4 ways.
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Problem 22 · 2009 Math Kangaroo Stretch
Logic & Word Problems work-backward

In a haunted house the house ghost suddenly disappears. At that moment in time all clocks show 6:15. However, there is also one strange clock in the house that showed the correct time before that event — starting from the disappearance it begins to count backwards. At 19:30 in real time the house ghost reappears. What time does the odd clock show at that moment?

Show answer
Answer: A — 17:00
Show hints
Hint 1 of 2
The vanishing happens at 6:15 in the evening, that is 18:15.
Still stuck? Show hint 2 →
Hint 2 of 2
Find how much real time passes, then subtract it because the odd clock runs backwards.
Show solution
Approach: run the time backwards by the elapsed amount
  1. When the ghost vanishes the clocks read 6:15 p.m. = 18:15.
  2. The ghost returns at 19:30, so 1 hour 15 minutes of real time pass.
  3. The odd clock counts backwards, so it shows 18:15 − 1:15 = 17:00.
  4. The odd clock shows 17:00.
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Problem 23 · 2009 Math Kangaroo Stretch
Spatial & Visual Reasoning spatial-reasoningtransformations

Sylvia draws shapes made of straight lines that are each 1 cm long. At the end of each line she turns a right angle, either left or right. At every turn she writes down a ♥ or a ♠, and the same symbol always means a turn in the same direction. Today her notes show ♥♠♠♠♥♥. Which of the following shapes could she have drawn today if A is her starting point?

Figure for Math Kangaroo 2009 Problem 23
Show answer
Answer: E
Show hints
Hint 1 of 3
Every symbol is a right-angle turn; one symbol always turns the same way and the other symbol always turns the other way.
Still stuck? Show hint 2 →
Hint 2 of 3
Notice the notes have three of the same symbol in a row (♠♠♠) in the middle, so the correct shape must make three same-direction turns in a row there.
Still stuck? Show hint 3 →
Hint 3 of 3
Start at A, walk 1 cm at a time, and turn the way each symbol tells you.
Show solution
Approach: match the ♥/♠ turn pattern by walking from the start point A
  1. Each line is 1 cm and each symbol is a right-angle turn, with one symbol always turning left and the other always turning right.
  2. The middle of the notes has three of the same symbol in a row (♠♠♠), which means three turns the same way in a row — that traces three sides of a little square.
  3. Starting at A and walking the path while turning as ♥♠♠♠♥♥ tells you, the path closes up in the shape of option E.
  4. Only shape E matches the whole sequence of turns.
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Problem 24 · 2009 Math Kangaroo Stretch
Logic & Word Problems caseworkwork-backward

In Funny-Foot-Land men and women wear the same sort of shoes. Each man has a left foot that is two sizes bigger than his right foot. Each woman has a left foot that is one size bigger than her right foot. However, shoes are only sold in pairs of the same size. To save money some friends decide to buy shoes together. After putting on their new shoes, two shoes are left over — one of size 36 and one of size 45. What is the minimum number of people in that group?

Show answer
Answer: A — 5
Show hints
Hint 1 of 2
Each person uses two different shoe sizes; shoes come only in same-size pairs.
Still stuck? Show hint 2 →
Hint 2 of 2
Think of going from size 36 up to size 45 in steps of 1 (a woman) or 2 (a man) — how few steps reach 45?
Show solution
Approach: link size 36 to size 45 with the fewest people
  1. A man uses sizes that differ by 2; a woman uses sizes that differ by 1.
  2. Because exactly the sizes 36 and 45 are each left with one spare shoe, the people must form a chain of shared sizes from 36 to 45.
  3. From 36 to 45 is a gap of 9; using mostly steps of 2, the fewest people needed is 5.
  4. So the minimum number of people is 5.
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