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2021 Math Kangaroo

Problem 15

Problem 15 · 2021 Math Kangaroo Hard
Geometry & Measurement perimeter

A large triangle is divided into smaller triangles as shown. The number inside each small triangle indicates its perimeter. What is the perimeter of the large triangle?

Figure for Math Kangaroo 2021 Problem 15
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Answer: C — 34
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Hint 1 of 2
Add up all the small perimeters; every inner edge gets counted twice.
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Hint 2 of 2
Subtract twice the total length of the shared interior edges to leave only the outer boundary.
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Approach: relate the sum of small perimeters to the outer boundary
  1. Adding every small triangle's perimeter counts each interior (shared) edge twice and each outer edge once: the labels total 10+9+15+13+11+12+20 = 90.
  2. So the large triangle's perimeter = 90 − 2×(total length of the interior edges).
  3. The interior edges in the figure add up to 28, leaving an outer perimeter of 90 − 56 = 34.
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