Problem 3 · 2021 Math Kangaroo
Easy
Arithmetic & Operations
order-of-operations
What is the value of \(\dfrac{20\cdot 21}{2+0+2+1}\)?
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Answer: D — 84
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Hint 1 of 2
Work out the bottom of the fraction first — it is just an addition.
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Hint 2 of 2
Then a single division finishes it.
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Approach: evaluate denominator, then divide
- The denominator is 2+0+2+1 = 5.
- The numerator is 20·21 = 420.
- 420 ÷ 5 = 84.
- So the answer is D.
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