πŸ‡ΊπŸ‡Έ AMC 8 ⇄ switch contest
1998 AJHSME

Problem 4

Problem 4 · 1998 AJHSME Easy
Geometry & Measurement careful-counting
Figure for AJHSME 1998 Problem 4
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Answer: E — 5 triangles.
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Hint 1 of 2
Counting by eye gives a guess; counting by SIZE gives the answer. Sort triangles into 'single smallest pieces' first, then ones made of two pieces, then the whole outline.
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Hint 2 of 2
Work small-to-big in layers so you never miss or double-count: how many 1-piece triangles? how many 2-piece? then the full outline.
Show solution
Approach: count in size layers (smallest pieces, then combinations)
  1. Smallest pieces: the inner line cut the figure into 3 little triangles.
  2. Made of 2 pieces: the two right-hand little triangles share a side and join into 1 bigger triangle.
  3. Made of all the pieces: the whole outline is itself 1 triangle.
  4. Total: 3 + 1 + 1 = 5.
  5. Why this transfers: for any 'how many triangles' puzzle, count by size layer (1 piece, 2 pieces, 3 pieces, …) instead of randomly. The layered list is your guarantee against missing or repeating one.
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