Problem 5 · 1985 AJHSME
Easy
Fractions, Decimals & Percents
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Answer: C — 3⁄4.
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Hint 1 of 2
A fraction needs a top AND a bottom. The top is the satisfactory grades (A, B, C, D). The bottom is EVERY grade in the class — and the F bar still counts toward that total even though it isn't satisfactory.
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Hint 2 of 2
Read each bar's height off the axis, total them for the denominator, total just the satisfactory ones for the numerator, then simplify. The classic trap is leaving the F's out of the bottom.
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Approach: satisfactory ÷ total
- Read the bar heights: A = 5, B = 4, C = 3, D = 3, F = 5. Satisfactory (A+B+C+D) = 5 + 4 + 3 + 3 = 15.
- The whole class is the total of ALL bars including F: 15 + 5 = 20.
- Fraction = 15 ⁄ 20 = 3⁄4.
- Spot the trap: if you forget the 5 F's, you'd get 15⁄15 = 1, which isn't even an option — the unsatisfactory grades belong in the denominator, just not the numerator.
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