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2021 Math Kangaroo

Problem 15

Problem 15 · 2021 Math Kangaroo Medium
Geometry & Measurement spatial-reasoning

Five identical right-angled triangles can be arranged so that their larger acute angles touch to form the star shown in the diagram. It is also possible to form a different star by arranging more of these triangles so that their smaller acute angles touch. How many triangles are needed to form the second star?

Figure for Math Kangaroo 2021 Problem 15
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Answer: D — 20
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Hint 1 of 2
Five large acute angles meeting at a point fill 360°, so each large acute angle is 72°.
Still stuck? Show hint 2 →
Hint 2 of 2
The small acute angle is 90° minus the large one; see how many fill a full turn.
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Approach: use the angles meeting at the star's centre
  1. For the first star, 5 equal larger acute angles surround the centre: 360° ÷ 5 = 72°.
  2. The triangle is right-angled, so the smaller acute angle is 90° − 72° = 18°.
  3. For the second star, smaller angles meet at the centre: 360° ÷ 18° = 20 triangles.
  4. So the answer is D.
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