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2012 Math Kangaroo

Problem 22

Problem 22 · 2012 Math Kangaroo Stretch
Logic & Word Problems work-backward

A goldsmith has 12 double-links of chain. Out of these he wants to make a single closed chain with 24 links. What is the minimum number of links that he must open (and close again)?

Figure for Math Kangaroo 2012 Problem 22
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Answer: A — 8
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Hint 1 of 2
Opening both links of one whole double-link frees two connectors.
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Hint 2 of 2
How many pieces must you sacrifice so the freed links join all the rest into one loop?
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Approach: sacrifice whole pieces to use their links as connectors
  1. There are 12 double-links (pieces). Opening both links of one piece gives two open links that can join other pieces, while using up that whole piece.
  2. If you open p whole pieces you get 2p connector links; the remaining 12 − p pieces need 12 − p joins to close into one loop.
  3. Require 2p ≥ 12 − p, i.e. 3p ≥ 12, so p ≥ 4; opening 4 pieces means opening 2 × 4 = 8 links (A).
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