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2011 Math Kangaroo

Problem 20

Problem 20 · 2011 Math Kangaroo Stretch
Geometry & Measurement caseworksymmetry

In the triangle WXY, point Z lies on XY and point T lies on WZ, as shown. Connecting T with X creates a figure with nine interior angles. Of those 9 angles, what is the smallest possible number that could all be different sizes from one another?

Figure for Math Kangaroo 2011 Problem 20
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Answer: B — 3
Show hints
Hint 1 of 3
The drawing makes three small triangles, and each one's angles must add to 180°.
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Hint 2 of 3
Ask how FEW distinct sizes the nine angles could take while still obeying every triangle's angle sum and the straight-line angles at T and Z.
Still stuck? Show hint 3 →
Hint 3 of 3
Try to force as many angles equal as possible and see what minimum number of different sizes survives.
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Approach: minimise the number of distinct angle sizes under the triangle-sum constraints
  1. Segment TX cuts the figure into three triangles, and the marked angles also satisfy straight-angle relations along line WZ at T and along XY at Z.
  2. If we try to make all nine angles equal, the 180° sums clash, so they cannot all match; with care we can still force them down to just a few values.
  3. Choosing the shape cleverly collapses the nine angles into exactly three distinct sizes, and no arrangement does better.
  4. So the smallest possible number of different sizes is 3, choice (B).
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