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2011 Math Kangaroo

Problem 15

Problem 15 · 2011 Math Kangaroo Stretch
Geometry & Measurement area-decomposition

A marble of radius 15 is rolled into a cone-shaped hole. It fits in perfectly. From the side the cone looks like an equilateral triangle. How deep is the hole?

Figure for Math Kangaroo 2011 Problem 15
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Answer: C — 45
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Hint 1 of 2
From the side the cone is an equilateral triangle and the marble is its inscribed circle.
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Hint 2 of 2
For an equilateral triangle the inradius is one third of the height.
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Approach: use the equilateral triangle's inradius
  1. Side-on, the marble is the circle inscribed in an equilateral triangle, with radius 15.
  2. In an equilateral triangle the inradius equals one third of the height.
  3. So the height (the hole's depth) = 3 × 15 = 45.
  4. The hole is 45 deep, choice (C).
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