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2011 Math Kangaroo

Problem 8

Problem 8 · 2011 Math Kangaroo Medium
Geometry & Measurement transformationsspatial-reasoning

The two bold lines shown are rotations of each other. Which of the given points could be the centre of this rotation?

Figure for Math Kangaroo 2011 Problem 8
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Answer: CX and T
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Hint 1 of 3
A rotation centre must be the same distance from each endpoint of a segment as from the matching endpoint of its image.
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Hint 2 of 3
Equivalently, the centre lies on the perpendicular bisector of the segment joining each point to where it lands.
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Hint 3 of 3
Test each labelled grid point to see which send the vertical bold segment exactly onto the horizontal one.
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Approach: the centre lies on the perpendicular bisectors joining matched endpoints
  1. Under a rotation, each point of the first segment moves to a point of the second, and the centre is equally far from both.
  2. So the centre must lie on the perpendicular bisector of the line joining each endpoint to its image; the true centre lies on all of them at once.
  3. Checking the four marked points on the grid, both X and T sit on those bisectors and turn the vertical bold segment onto the horizontal one (by ±90°).
  4. So both X and T work, choice (C).
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