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2011 Math Kangaroo

Problem 20

Problem 20 · 2011 Math Kangaroo Hard
Counting & Probability careful-countingcasework

You can place together the cards pictured to make different three‑digit numbers, for instance 989 or 986. How many different three‑digit numbers can you make with these cards?

Figure for Math Kangaroo 2011 Problem 20
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Answer: E — 12
Show hints
Hint 1 of 3
Two of the cards are the kind that show a 6 one way and a 9 when you turn them upside down; the 8 looks the same either way.
Still stuck? Show hint 2 →
Hint 2 of 3
First decide which of the three spots the 8 sits in, then fill the other two spots.
Still stuck? Show hint 3 →
Hint 3 of 3
For each place the 8 can go, the two leftover spots can each be a 6 or a 9.
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Approach: place the 8, then fill the other two spots with 6 or 9
  1. There are three cards: two flip-cards that each show a 6 or a 9, and one 8-card that looks the same whichever way up it is.
  2. Pick where the 8 goes: it can be the first, middle, or last digit — that is 3 choices.
  3. For each of those, the two remaining spots can each be a 6 or a 9, giving 4 numbers per choice: for example with 8 in front you get 866, 869, 896, 899.
  4. So the count is 3 groups of 4, which is 3 × 4 = 12 different numbers, answer E.
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