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2010 Math Kangaroo

Problem 7

Problem 7 · 2010 Math Kangaroo Medium
Geometry & Measurement symmetry

The triangle pictured is right-angled. M is the midpoint of the hypotenuse AB and ∠BCA = 90°. How big is ∠BMC?

Figure for Math Kangaroo 2010 Problem 7
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Answer: D — 120°
Show hints
Hint 1 of 2
The midpoint of a right triangle's hypotenuse is the same distance from all three vertices.
Still stuck? Show hint 2 →
Hint 2 of 2
That makes triangle BMC isosceles; use the marked angle.
Show solution
Approach: midpoint of hypotenuse = circumcentre
  1. Since M is the midpoint of the hypotenuse AB and the angle at C is 90°, MB = MC = MA.
  2. So triangle BMC is isosceles with MB = MC, giving equal base angles.
  3. With the angle at A = 60°, the angle at B = 30°, so ∠MBC = 30°.
  4. Then ∠BMC = 180° − 30° − 30° = 120°.
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