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2010 Math Kangaroo

Problem 30

Problem 30 · 2010 Math Kangaroo Stretch
Geometry & Measurement spatial-reasoning

In the figure, \(\alpha = 7^\circ\). All the lines OA1, A1A2, A2A3, … are equally long. What is the maximum number of lines that can be drawn in this way if no two lines are allowed to intersect each other?

Figure for Math Kangaroo 2010 Problem 30
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Answer: D — 13
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Hint 1 of 2
Each equal segment makes an isosceles triangle, and the slope angle grows by 7° each step.
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Hint 2 of 2
The zigzag can continue only while that angle stays below 90°.
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Approach: track the growing angle
  1. With α = 7° and all segments equal, each new isosceles step increases the slope angle by 7°.
  2. The construction stays valid while the accumulated angle is under 90°: 7°×12 = 84° still works, but 7°×13 = 91° does not.
  3. Counting the segments that can still be drawn gives 13 lines.
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