Problem 11 · 2010 Math Kangaroo
Medium
Geometry & Measurement
areasquare-area
In the figure, ABCE is a square. CDE and BCF are equilateral triangles. The length of AB is 1. How long is FD?

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Answer: A — \(\sqrt{2}\)
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Hint 1 of 2
Place the unit square on coordinates and find where the two triangle tips D and F land.
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Hint 2 of 2
Then just measure the distance from D to F.
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Approach: coordinates for the two apex points
- Take the unit square A(0,0), B(1,0), C(1,1), E(0,1).
- The equilateral tips are D(1/2, 1+sqrt3/2) above EC and F(1-sqrt3/2, 1/2) left of BC.
- Then FD² = (sqrt3/2 - 1/2)² + (1/2 + sqrt3/2)² = 2, so FD = sqrt2.
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