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Fractions, Decimals & Percents — Three names for the same number.

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Showing the Grades 5–8 version. See the simpler Grades 1–4 version →

About this topic

Half off. Fifty percent off. One-half of the price. Same sticker, three labels. The store could print any of them and your wallet would not know the difference — because a fraction, a decimal, and a percent are three names for one number, a piece of a whole.

Watch one number wear all three costumes:

  • 1/2 = 0.5 = 50%
  • 3/4 = 0.75 = 75%
  • 1/5 = 0.2 = 20%
  • 1/8 = 0.125 = 12.5%

A kid who thinks in only one costume is always translating mid-problem. A kid who knows all three picks the easiest one for the question in front of them — and the easy half of every contest rewards exactly that. Know these few conversions cold and a lot of ‘hard’ problems turn into one line.

Nine moves ahead: (1) jump between the three forms fast, (2) read every percent as a multiplier, (3) see why stacked percents multiply instead of add, (4) rank fractions without dividing, (5) collapse a fraction-inside-a-fraction, (6) watch a long product or sum telescope, (7) chase a fraction-of-a-fraction story to the start, (8) average groups of different sizes, (9) tell ‘percent OF’ apart from ‘percent MORE THAN.’

CHAPTER 1

Three forms, one number

THEORY

A fraction like 3/5 means “3 out of 5 equal parts.” A decimal like 0.6 means “6 tenths.” A percent like 60% means “60 per hundred.”

They’re all the same number. Three costumes for one value. The kid who thinks in all three picks the easiest costume for each problem. Before any rules, look at the pictures — every rule below is a thing you can already SEE.

See it first: a fraction is a shaded part of a bar

Take a chocolate bar. Snap it into equal pieces. A fraction is “how many pieces you shade” over “how many equal pieces there are.” The bottom number tells you how many cuts; the top tells you how many you grabbed.

3/5 = three of five equal pieces12345shaded = 3total = 5shaded length ÷ whole length = 3/5
The bottom is how many EQUAL pieces the whole is cut into. The top is how many you shade. A fraction is a shaded length.

See it: equivalent fractions are the SAME shaded length

Here is the idea that unlocks everything else. Take the bar shaded to one-half. Now draw extra cut lines through it — you didn’t move any chocolate, you only chopped it finer. The shaded part is exactly as long as before, but now you can call it 2/4, or 3/6, or 50/100. Same length, more names.

1/2 = 2/4 = 3/6 — finer cuts, same shaded part1/22/43/6The shaded edge never moves — that is why the fractions are equal.

That picture is the rule everyone memorizes: multiply top and bottom by the same number and the fraction does not change. Multiplying by the same number means cutting every piece into the same number of smaller pieces — nothing was added or removed. Running it backward (dividing top and bottom by a shared factor) is gluing pieces back together: that is “simplifying.”

🎯 Try it
Cut a bar into thirds and shade two: that’s 2/3. Now cut every piece into 3 smaller pieces, so the bar has 9 pieces. How many small pieces are shaded?
Walkthrough: Each shaded third splits into 3 small pieces, so 2 shaded thirds become 2 × 3 = 6 shaded pieces out of 3 × 3 = 9. So 2/3 = 6/9 — same shaded length, finer cuts. 6 pieces are shaded.

See it: compare fractions by lining the bars up

Which is bigger, 2/3 or 3/5? Stack two equal-length bars, shade each, and look at which shaded edge sticks out farther. No arithmetic — your eyes do it.

Line them up: 2/3 vs 3/52/33/52/3 reaches farther right → 2/3 > 3/5

The bars make the “common denominator” trick feel obvious. To compare with numbers, give both bars the same number of pieces (a common bottom): 2/3 = 10/15 and 3/5 = 9/15. Now it’s 10 pieces vs 9 pieces — 2/3 wins, exactly as the picture showed.

See it: a decimal is a 10×10 grid

Take a square and cut it into a 10×10 grid — 100 little cells, the whole square is “1.” Now each column is one tenth (0.1) and each tiny cell is one hundredth (0.01). A decimal is how many cells you shade.

0.34 = 34 of the 100 cells shaded3 full columns (0.30) + 4 cells (0.04) = 0.34one column= 1 tenth= 0.1one cell= 1 hundredth= 0.01

Place value falls right out of the grid. The first decimal spot counts columns (tenths); the second counts single cells (hundredths). So 0.3 is three whole columns — 30 cells — which is why 0.3 = 0.30 = 30/100. Adding a zero on the end shades the same area, only counted in smaller cells.

🎯 Try it
On a 10×10 grid you shade 7 full columns, which reads as the decimal 0.7. How many of the 100 little cells are shaded?
Walkthrough: Each column is 10 cells, so 7 columns = 7 × 10 = 70 cells. That is 70/100 = 0.70 = 0.7 — 7 tenths and 70 hundredths are the same shaded area. 70 cells.

See it: a percent is the SAME grid — one bar, three labels

Here is the punchline of the whole chapter. The 10×10 grid has exactly 100 cells. So “percent” — which means per hundred — is exactly how many of those 100 cells are shaded. The decimal grid and the percent grid are the same drawing. That is why one shaded bar can wear all three labels at once.

One shaded bar, three names: 3/5 = 0.6 = 60%shadedFRACTION: 3 of 5 = 3/5DECIMAL: cut into 10ths → 6 of 10 = 0.6PERCENT: cut into 100ths → 60 of 100 = 60%Same shaded length. Finer cuts give you the decimal and the percent for free.

To turn any fraction into a percent, cut the bar into 100 pieces and count the shaded ones — that is exactly “scale the bottom to 100,” which you’ll use constantly below.

🎯 Try it
Shade 3 of 4 equal pieces of a bar. Cut every piece into 25 to make 100 little cells. How many cells are shaded? (That number is the percent.) Type it.
Walkthrough: Each of the 4 pieces becomes 25 cells, so 3 shaded pieces become 3 × 25 = 75 cells out of 100. So 3/4 = 75/100 = 0.75 = 75% — one bar, three labels.

See it: fraction × fraction is the OVERLAP in a unit square

“Of” means multiply — but why does 1/2 × 1/3 come out so small, only 1/6? Watch it in a square that stands for one whole.

First take 1/3 of the square: shade a vertical strip one-third wide. Now take 1/2 of that strip: cut it in half the other way and shade the lower half. The piece you shaded twice — the overlap — is the answer. Count the little boxes: the square split into 2 rows and 3 columns has 6 equal boxes, and the overlap is exactly 1 of them.

1/2 × 1/3 = the overlap = 1/61/3 wide1/2 tall1/62 rows × 3 columns = 6 equal boxes; the double-shaded box is 1 of 6.

The picture spells out the rule. The square is split into 2 × 3 = 6 equal boxes (rows times columns), and the overlap is only 1 box. That is exactly multiply the tops, multiply the bottoms: (1×1)/(2×3) = 1/6. Multiplying two fractions under 1 makes a smaller piece because you are taking a part of a part.

🎯 Try it
In a unit square, shade 2/3 of the width, then 3/4 of the height. The grid is 4 rows by 3 columns = 12 boxes. How many boxes does the overlap cover? (That over 12 is the product.) Type the number of overlap boxes.
Walkthrough: Width 2/3 covers 2 of 3 columns; height 3/4 covers 3 of 4 rows. The overlap is 2 × 3 = 6 boxes out of 3 × 4 = 12. So 2/3 × 3/4 = 6/12 = 1/2. The overlap is 6 boxes.

Pictured-intuition adapted from Competition Math for Middle School (AoPS).

A worked example with the bar picture

Peter’s family orders a 12-slice pizza. Peter eats one slice, and splits a second slice equally with his brother. What fraction of the pizza did Peter eat?

Draw the pizza as a bar of 12 equal slices. Peter’s full slice is 1 slice. The shared slice splits in two, so Peter gets half a slice more. Peter’s total shaded length is 1 + ½ = 1½ slices out of 12.

That is 1.5/12. Double top and bottom to clear the half: 3/24 = 1/8 (answer C). The bar kept the “out of 12” honest — no guessing.

12 slices; Peter eats 1 whole + half of one = 1.5 slices1.5 of 12 = 3/24 = 1/8 of the pizza
Same number, three costumesFRACTION3/5DECIMAL0.6PERCENT60%F ↔ Ddivide / 0.xF ↔ Pscale to /100D ↔ P×100 / ÷100All three vertices = the same number. Move freely between them.

The six conversions, spelled out

DirectionRuleWorked example
Fraction → DecimalDivide top by bottom3 ÷ 5 = 0.6
Decimal → FractionRead place value, simplify0.6 = 6/10 = 3/5
Decimal → PercentMultiply by 100 (move dot 2 right)0.6 → 60%
Percent → DecimalDivide by 100 (move dot 2 left)60% → 0.60
Fraction → PercentScale denom to 100, OR divide × 1003/5 = 60/100 = 60%
Percent → FractionPut over 100 then simplify60% = 60/100 = 3/5
A contest almost never hands you a number in the form you’d compute with. A one-second translation up front often turns a scary problem into an easy one.

THE MOVE — SCALE TO 100

When the bottom of a fraction divides 100 cleanly (2, 4, 5, 10, 20, 25, 50), don’t long-divide. Multiply top and bottom until the bottom is 100 — now the top is the percent and the decimal reads off for free. 2/25 → ×4 → 8/100 = 8% = 0.08.

🎯 Try it
Turn 7/20 into a percent. (Scale the bottom to 100 — don’t divide.) Type the number of percent.
Walkthrough: 20 × 5 = 100, so multiply top and bottom by 5: 7/20 = 35/100. That bottom-of-100 means the top is the percent: 35% (and the decimal is 0.35). No division.

Conversions to KNOW COLD

FractionDecimalPercent
1/20.550%
1/30.3 (0.333…)33⅓%
2/30.6 (0.666…)66⅔%
1/40.2525%
3/40.7575%
1/50.220%
2/50.440%
3/50.660%
4/50.880%
1/80.12512.5%
3/80.37537.5%
5/80.62562.5%
7/80.87587.5%
1/60.1616⅔%
1/90.111⅑%
1/990.01≈ 1.01%

Repeating decimals — use the bar

Some fractions never stop when you divide them out (1/3, 1/6, 1/9, 1/99 above). Instead of rounding to “0.333” or “0.667,” write a bar over the block that repeats forever: 1/3 = 0.3,  2/3 = 0.6,  1/6 = 0.16,  1/99 = 0.01.

The pattern. One repeating digit over 9 is that digit as a ninth: 0.1 = 1/9,  0.4 = 4/9. Two repeating digits go over 99: 0.27 = 27/99 — which is why 1/99 = 0.01.

The trick: turn a repeating decimal into a fraction

Name the decimal, multiply by 10 (or 100…) to slide it one whole period, then subtract so the repeating tail cancels.

Let x = 0.9 (that is 0.999…).
Then 10x = 9.9 (that is 9.999…).
Subtract: 10x − x = 9.999… − 0.999… = 9, so 9x = 9 and x = 1.
So 0.999… is exactly 1 — not “almost.”

Same move for any repeater. x = 0.3 → 10x = 3.3 → 9x = 3 → x = 3/9 = 1/3. For a two-digit period, multiply by 100: x = 0.01 → 100x = 1.01 → 99x = 1 → x = 1/99.

When only PART of the decimal repeats

Trickier cousins like 0.28 (that is 0.2888…) have a non-repeating digit out front and only the 8 looping. The shift trick still works — you only have to line up the tails so they truly match before subtracting.

Let x = 0.28 (= 0.2888…).
Multiply by 10 to slide one whole period: 10x = 2.8 (= 2.888…).
Subtract: 10x − x = 2.888… − 0.2888… = 2.6, so 9x = 2.6 and x = 2.6/9 = 26/90 = 13/45.

The watch-out. Do NOT write 10x − x = 0.8. The repeating 8-tails only cancel if the two numbers line up digit-for-digit past the decimal — 2.88 minus 0.28 leaves a clean 2.6, tails gone. Pick the power of 10 that lands the repeating block in the same spot in both numbers, then subtract.

🎯 Try it
Write 0.16 (that is 0.1666…) as a fraction in lowest terms, then type the SUM of its numerator and denominator. (Hint: 10x slides the period.)
Walkthrough: Let x = 0.16. Then 10x = 1.6 = 1.666…, and 10x − x = 1.666… − 0.1666… = 1.5. So 9x = 1.5 and x = 1.5/9 = 15/90 = 1/6. Numerator + denominator = 1 + 6 = 7. (And indeed 1/6 = 0.1666… ✓)

See it: WHY some fractions stop and some repeat forever

1/4 stops dead at 0.25. 1/3 goes 0.3333… forever. What decides it? Not the size of the fraction — it’s the prime factors hiding in the bottom. Here is the whole secret in one idea.

A decimal that stops is really a fraction over 10, or 100, or 1000 — 0.25 = 25/100. And every power of ten is built from only two primes: 2 and 5 (10 = 2·5, 100 = 2·2·5·5). So a fraction can be rewritten over a power of ten exactly when its bottom is built from only 2s and 5s. If any other prime (3, 7, 11…) is stuck in the bottom, no power of ten will ever fit, and the long division never closes — it repeats.

Look at the bottom’s prime factorsOnly 2s and 5s → STOPS1/2 = 0.51/4 = 0.25  (4 = 2·2)1/5 = 0.21/8 = 0.125 (8 = 2·2·2)3/20 = 0.15 (20 = 2·2·5)A 3, 7, 11… → REPEATS1/3 = 0.3333… (has a 3)1/6 = 0.1666… (6 = 2·3)1/7 = 0.142857…1/9 = 0.1111… (9 = 3·3)1/11 = 0.0909…

THE TEST — SIMPLIFY, THEN CHECK THE BOTTOM

Put the fraction in lowest terms. If the bottom’s only prime factors are 2 and 5, the decimal terminates. If any other prime survives, it repeats.

Watch out: simplify first. 3/6 looks like it has a 3 in the bottom, but it’s really 1/2 — it stops.

The long-division loop for a repeater

Why does 1/7 repeat with a block exactly 6 long? Do the long division and watch the remainders. Dividing by 7, every remainder is one of 1, 2, 3, 4, 5, 6 (a remainder of 0 would mean it stopped). There are only 6 of those. So within 6 steps a remainder must repeat — and the instant a remainder comes back, the whole string of digits after it comes back too. The decimal is trapped in a loop.

1/7: the remainders cycle 1→3→2→6→4→5→11326456 possibleremainders

That is the contest payoff: 1/7 = 0.142857, and the six sevenths are all the same six digits, only started at a different spot. The repeating block can never be longer than “denominator minus 1.”

Pictured-intuition adapted from Competition Math for Middle School (AoPS).

🎯 Try it
Does 7/56 give a terminating decimal? (Simplify first, then check the bottom’s primes.) Type 1 for terminates, 0 for repeats.
Walkthrough: Simplify: 7/56 = 1/8. And 8 = 2·2·2 — only 2s. So it terminates: 1/8 = 0.125. Answer: 1. (Don’t be fooled by the 7 and 56 — after simplifying, the bottom is pure 2s.)

Reading a shaded figure as a fraction

Contests love to draw a shape, shade part of it, and ask “what fraction is shaded?” (or “what percent?”). Your instinct is to measure areas with a ruler. Resist it. A fraction is parts out of equal parts — so the whole job is: cut the figure into pieces that are all the same size, then count.

THE MOVE

  1. Slice the whole figure into equal pieces (use the lines already drawn, or extend them).
  2. Count the shaded pieces — that’s the top.
  3. Count all the pieces — that’s the bottom.
  4. Shaded fraction = shaded ÷ total. Then convert to a percent if asked.

The trick is choosing equal pieces. A grid hands them to you. Lines through a circle’s center make equal pie slices. A square cut into a clean number of smaller squares gives you a counting unit.

Cut into equal pieces, then count8 equal slices, 4 shaded → 4/8 = 50%9 equal cells, 3 shaded → 3/9 = 1/3

Worked example. Three circles share a center, and four straight lines run through that center; every other wedge is shaded. What percent of the figure is shaded?

Don’t fight the three rings. The four lines through the center cut the whole picture into 8 equal pie slices. The shading alternates — one slice on, the next off, all the way around — so exactly 4 of the 8 slices are shaded.

That holds in every ring at once, so the fraction is the same for the whole figure: 4/8 = 1/2 = 50% (answer E). No areas, no ruler — count equal slices.

Never measure the shaded region. Cut the whole figure into equal pieces, count shaded over total. A fraction is parts out of equal parts.
THE TRICK

When the denominator divides 100 cleanly (4, 5, 10, 20, 25, 50, 100), scale to 100 instead of long-dividing.

Example. Convert 2/25 to a percent. Multiply top and bottom by 4: 2/25 = 8/100 = 0.08 = 8%. Done in 2 seconds. The slow way (long division: 2 ÷ 25) takes 30 seconds.

When the denominator is 2 or 10, you can read the decimal directly. When it's 8 or 16, scale to 1000.

WORKED EXAMPLE
PROBLEM · 1987 #2

2 ⁄ 25 =

A) .008 B) .08 C) .8 D) 1.25 E) 12.5

Convert 2/25 to a decimal.

Scale the denominator to 100: multiply top and bottom by 4.

2/25 = 8/100 = 0.08.

The slow approach is to do 2 ÷ 25 by long division. The fast approach: recognize that 25 × 4 = 100, and multiply both top and bottom by 4. Now the decimal is automatic.

Answer: B — .08.
RULE OF THUMB

Memorize the common conversions. When dividing by 4, 5, 20, 25, 50, scale the denominator to 100. When dividing by 2 or 10, read directly. Long division is the last resort.

MORE LIKE THIS
1989 · #2 210 + 4100 + 61000 =

210 + 4100 + 61000 =

Show answer
Answer: D — .246.
Show hints
Hint 1 of 3
Look at the denominators 10, 100, 1000 — those ARE the names of the decimal places. What do tenths, hundredths, thousandths look like written out?
Still stuck? Show hint 2 →
Hint 2 of 3
A fraction over a power of ten is already a decimal: the bottom tells you which column the top digit lives in.
Still stuck? Show hint 3 →
Hint 3 of 3
The digits 2, 4, 6 land in three different columns, so nothing collides — no adding needed.
Show solution
Approach: read each denominator as a decimal place
  1. The denominator names the column: /10 is the tenths place, /100 the hundredths, /1000 the thousandths. So 2/10 puts a 2 in the tenths column, 4/100 a 4 in the hundredths, 6/1000 a 6 in the thousandths.
  2. Because each digit sits in a separate column, you just write them in order: .246 — no carrying, no lining up.
  3. Trap to avoid: the off-answer .0246 comes from shoving all three digits one column too far right. Anchor on 2/10 = 0.2 (a 2 right after the point) and the rest follows.
2017 · #4 Which statement is correct?

Which statement is correct?

Show answer
Answer: B52 = 2.5
Show hints
Hint 1 of 2
Just compute each fraction as a decimal and see which equality is actually true.
Still stuck? Show hint 2 →
Hint 2 of 2
Only one of the five statements gives a correct value.
Show solution
Approach: check each division
  1. Test each: 4/1 = 4 (not 1.4), 5/2 = 2.5 (correct), 6/3 = 2 (not 3.6), 7/4 = 1.75, 8/5 = 1.6.
  2. Only 5/2 = 2.5 is right.
1997 · #3 Which of the following numbers is the largest?

Which of the following numbers is the largest?

Show answer
Answer: B — 0.979.
Show hints
Hint 1 of 2
Don't judge by how many digits a decimal has — 0.9709 is not bigger just because it's longer. Compare left to right, one place at a time.
Still stuck? Show hint 2 →
Hint 2 of 2
Decimals compare like a race: the first place where they differ decides the winner, and everything after that is irrelevant.
Show solution
Approach: left-to-right place comparison
  1. Tenths first: all five start 0.9…, a tie. Move right.
  2. Hundredths: 0.97, 0.979, 0.9709 all have a 7, but 0.907 has 0 and 0.9089 has 0 — those two are knocked out, even though 0.9089 has lots of digits.
  3. Thousandths decides the survivors: 0.979 has a 9 while 0.97 and 0.9709 have 0, so 0.979 wins.
  4. Why this transfers: extra trailing digits never make a decimal bigger — only an earlier place can. 0.97 = 0.9700, which already beats 0.9709? No: 0.9700 vs 0.9709 ties through hundredths, then 0 vs 0 in thousandths, then 0 vs 9 — so 0.9709 > 0.97. The first difference rules.
2024 · #2 What is the value of this expression in decimal form?4411 + 11044 + 441100

What is the value of this expression in decimal form?

4411 + 11044 + 441100
Show answer
Answer: C — 6.54.
Show hints
Hint 1 of 2
Before finding a common denominator, glance at each fraction alone — do any of them just collapse to a clean number?
Still stuck? Show hint 2 →
Hint 2 of 2
Each one simplifies on its own (every part hides a factor of 11). Turn each into a decimal, then add.
Show solution
Approach: simplify each fraction, then add
  1. Don't reach for a common denominator — each fraction simplifies to a clean decimal on its own, so just turn them one at a time. 4411 = 4.
  2. 11044 = 52 = 2.5 (cancel 22).
  3. 441100 = 4100 = 0.04 (cancel 11).
  4. Add: 4 + 2.5 + 0.04 = 6.54. Sanity check: answers near 6.5 should sit just above 6.5 once the tiny 0.04 is added — rules out 6.4 and 6.9.
Another way — pull out the shared 11 first (MAA):
  1. Every numerator and denominator carries a factor of 11. Spotting that turns 44, 110, 1100 into 4×11, 10×11, 100×11 — the 11's cancel before you divide.
  2. You're left with 41 + 104 + 4100 = 4 + 2.5 + 0.04 = 6.54.
1998 · #5 Which of the following numbers is largest?

Which of the following numbers is largest?

Show answer
Answer: B — 9.1234̄ (B).
Show hints
Hint 1 of 2
Don't read the overline bars as 'long' — read them as 'what comes next.' Every choice opens 9.1234…, so line them up and find the first place where one digit beats the others.
Still stuck? Show hint 2 →
Hint 2 of 2
To compare decimals, scan left to right and stop at the first column where they differ — the bigger digit there wins, no matter how many digits trail behind.
Show solution
Approach: line them up and find the first column that differs
  1. Write the bars out a few places: A 9.12344, B 9.12344̄ = 9.123444…, C 9.1234343…, D 9.1234234…, E 9.1234123…. All share 9.1234, so look at the 5th decimal place: it's 4 for A and B, but only 3, 2, 1 for C, D, E. The winner is A or B.
  2. A and B agree through 9.12344. At the next place A has nothing (it stopped) — that's a 0 — while B keeps going with another 4. So B pulls ahead: B is largest.
  3. Trap to remember: more digits does NOT mean bigger. A short number can beat a long one (0.9 > 0.12345). Compare position by position, left to right, and the first place that differs decides it.
2021 · #2 The figure shows three concentric circles with four lines passing through their common centre. What percentage of the figure is shaded?

The figure shows three concentric circles with four lines passing through their common centre. What percentage of the figure is shaded?

Figure for Math Kangaroo 2021 Problem 2
Show answer
Answer: E — 50%
Show hints
Hint 1 of 2
Four lines through the centre cut the picture into equal pie-slice sectors — count how many.
Still stuck? Show hint 2 →
Hint 2 of 2
Notice the shading repeats every other slice, so the same fraction is shaded in every ring.
Show solution
Approach: exploit the equal sectors and alternating shading
  1. The four lines through the common centre split the figure into 8 equal sectors.
  2. Going around, the sectors alternate shaded / unshaded, so exactly half of every ring is shaded.
  3. Half of the whole figure is shaded, which is 50%.
  4. So the answer is E.
CHAPTER 2

Mixed numbers — improper fractions in disguise

THEORY

Nobody at a bake sale asks for “seven-fourths of a pie.” They ask for “one and three-quarter pies.” Same amount, friendlier name. 7/4 is an improper fraction (top bigger than bottom); is a mixed number — a whole number sitting next to a leftover fraction. They are two costumes for one value, and a contest will hand you whichever is more annoying.

7/4 and 1¾ land on the SAME spot0127/4= 1¾one whole, then 3 of the next 4 quarter-steps

Improper → mixed: it is just division with a leftover

To rename 23/5, ask the plain division question: how many whole 5s fit in 23, and what is left over? 23 ÷ 5 = 4 remainder 3. The quotient 4 is the whole part; the leftover 3 stays on top over the same bottom 5. So 23/5 = 4⅗. The remainder can never reach the bottom number — if it did, that would be one more whole.

Mixed → improper: glue the whole back on

Going back, 4⅗ means 4 + ⅗. Write the 4 as fifths too: 4 = 20/5, so 4⅗ = 20/5 + 3/5 = 23/5. The shortcut everyone memorizes — (whole × bottom + top) over the bottom — is exactly that: (4×5 + 3)/5 = 23/5.

THE TWO MOVES

  • Improper → mixed: divide top by bottom. Quotient = whole part; remainder = new top (same bottom).
  • Mixed → improper: (whole × bottom + top) all over the bottom.
🎯 Try it
Write as an improper fraction. Type its numerator (the top number).
Walkthrough: whole × bottom + top: 5 × 4 = 20, then 20 + 3 = 23. So 5¾ = 23/4, and the numerator is 23. Check by dividing back: 23 ÷ 4 = 5 remainder 3 = 5¾ ✓.

Adding mixed numbers — watch the fraction part overflow

Add wholes to wholes and fractions to fractions, keeping the two stacks separate. The only twist: the fraction stack can pile up past 1, and then you regroup — trade the extra whole over to the whole stack.

Take 2⅔ + 1¾. Wholes: 2 + 1 = 3. Fractions: ⅔ + ¾ = 8/12 + 9/12 = 17/12 — that is more than a whole. Rename it: 17/12 = 1 and 5/12. Now carry that 1 over: 3 + 1 and 5/12 = 4 and 5/12.

Adding mixed numbers is just like carrying in ordinary addition — when the fraction column tops 1, carry a whole into the whole column.

Subtracting mixed numbers — borrowing a whole

Subtraction has the mirror twist. In 5¼ − 2¾ you cannot take ¾ from ¼ — the top fraction is too small. So borrow one whole and turn it into fourths, exactly like borrowing a ten in plain subtraction:

Borrow a whole: 5¼ = 4 + 1¼ = 4 and 5/45¼ — cannot do ¼ − ¾top fraction too smallborrow 1 whole = 4/44 and 5/4, minus 2¾(4 − 2) + (5/4 − 3/4)= 2 and 2/4 = 2½1 + ¼ becomes 4/4 + 1/4 = 5/4, so now the fraction subtraction works.

So 5¼ − 2¾ = 2½. (If borrowing feels slippery, the safe fallback is to flip BOTH numbers to improper fractions first: 21/4 − 11/4 = 10/4 = 2½ — same answer, no borrowing.)

Framing inspired by AoPS Prealgebra.

🎯 Try it
Compute 6⅕ − 3⅗. The answer is a mixed number of the form a and b/5 — type the WHOLE part a. (You will need to borrow.)
Walkthrough: Cannot do ⅕ − ⅗, so borrow: 6⅕ = 5 and 6/5. Then (5 and 6/5) − 3⅗ = (5 − 3) + (6/5 − 3/5) = 2 + 3/5 = 2⅗. The whole part is 2. (Improper check: 31/5 − 18/5 = 13/5 = 2⅗ ✓.)
THE TRICK

When mixed numbers fight you, flip them to improper fractions, do the arithmetic over a common bottom, then flip the answer back. No borrowing, no carrying — one clean lane.

And to estimate a pile of mixed numbers fast: each one is “a whole part plus a bit under 1,” so the sum is a little above the sum of the whole parts.

WORKED EXAMPLE
PROBLEM · 1995 #5

Find the smallest whole number that is larger than the sum 212 + 313 + 414 + 515.

A) 14 B) 15 C) 16 D) 17 E) 18

Find the smallest whole number larger than 2½ + 3⅓ + 4¼ + 5⅕.

Split into two stacks. Wholes: 2 + 3 + 4 + 5 = 14. Fractions: ½ + ⅓ + ¼ + ⅕. Over a common bottom of 60: 30/60 + 20/60 + 15/60 + 12/60 = 77/60, which is 1 and 17/60.

So the sum is 14 + 1 and 17/60 = 15 and 17/60 — a bit past 15 but nowhere near 16. The smallest whole number larger than it is 16 (answer C).

You never need the exact 17/60. The four fractions are each under 1, and four of them add to a touch over 1 — so the whole parts (14) plus “a little more than 1” lands between 15 and 16. The smallest whole number above that is 16. Estimating the fraction stack beats grinding the common denominator.

Answer: C — 16.
RULE OF THUMB

Add wholes to wholes, fractions to fractions. If the fraction stack tops 1, carry a whole over (addition) or borrow a whole down (subtraction). When in doubt, convert to improper fractions and the carrying/borrowing disappears.

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1992 · #2 Which of the following is not equal to 54?

Which of the following is not equal to 54?

Show answer
Answer: D — 1 1/5.
Show hints
Hint 1 of 3
5/4 is one whole plus a quarter. Which choices are secretly just a quarter dressed up — and which one hides a different-sized piece?
Still stuck? Show hint 2 →
Hint 2 of 3
When choices look different but might be equal, convert them all to ONE common form (a decimal, or a fraction over the same bottom number) so they line up for comparison.
Still stuck? Show hint 3 →
Hint 3 of 3
A bigger denominator means a smaller slice: 1/5 is less than 1/4, so don't be fooled into reading 1 1/5 as 1.25.
Show solution
Approach: rewrite every choice in one common form so the odd one out stands out
  1. 5/4 = 1 + 1/4 = 1.25. Now test each: 10/8 = 1.25 (just doubled top and bottom); 1 1/4 = 1.25; 1 3/12 = 1 + 1/4 = 1.25 (3/12 reduces to 1/4); 1 10/40 = 1 + 1/4 = 1.25 (10/40 reduces to 1/4).
  2. That leaves 1 1/5. Since 1/5 = 0.2, this is 1.2, NOT 1.25 — so 1 1/5 is the one not equal.
  3. Trap to remember: a fifth feels "close" to a quarter, but cutting something into 5 pieces gives smaller pieces than cutting into 4. The trickster choice swaps the denominator from 4 to 5 hoping you won't notice the slice shrank.
1998 · #3 38 + 7845=
38 + 7845=
Show answer
Answer: B — 25/16.
Show hints
Hint 1 of 2
A big fraction-over-a-fraction is just a division: (top) ÷ (bottom). Notice the two pieces on top already share the same denominator, so adding them is a freebie.
Still stuck? Show hint 2 →
Hint 2 of 2
Dividing by a fraction means flipping it and multiplying. Watch for the same fraction showing up twice.
Show solution
Approach: the bar means divide; flipping turns it into a square
  1. The top adds easily because the bottoms match: 3/8 + 7/8 = 10/8 = 5/4.
  2. The big bar means divide by 4/5, and dividing by a fraction means flip-and-multiply: (5/4) ÷ (4/5) = (5/4) × (5/4).
  3. That's the same fraction times itself: (5/4)² = 25/16.
  4. Why this transfers: a fraction stacked over a fraction is always a division in disguise — rewrite it as ÷, then flip the bottom. And a sanity check: 5/4 is a bit over 1, so its square should be a bit over 1; 25/16 ≈ 1.56 fits.
1995 · #3 Which of the following operations has the same effect on a number as multiplying by 34 and then dividing by 35?

Which of the following operations has the same effect on a number as multiplying by 34 and then dividing by 35?

Show answer
Answer: E — multiplying by 5/4.
Show hints
Hint 1 of 2
Dividing by a fraction is the same as multiplying by its flip. So 'divide by 3/5' can become 'multiply by 5/3' — now everything is multiplication.
Still stuck? Show hint 2 →
Hint 2 of 2
Two multiplications in a row are really just one. Combine them into a single multiplier and see which answer it matches.
Show solution
Approach: turn dividing into multiplying by the flip, then merge
  1. The insight: 'divide by 3/5' is the same as 'multiply by 5/3' (flip the divisor). Now both steps are multiplications, which combine cleanly.
  2. So the effect is × 34 × 53. The 3's cancel, leaving × 54 — i.e. multiplying by 5/4.
  3. Why this transfers: any string of ×'s and ÷'s by fractions collapses to one fraction — flip every divisor, then multiply across and cancel.
Another way — test with an easy number:
  1. Pick 12 (divisible by 4 and 3). Multiply by 3/4: 12 → 9. Divide by 3/5: 9 ÷ 3/5 = 9 × 5/3 = 15.
  2. So 12 became 15 — that's × 5/4 (since 12 × 5/4 = 15). Matches multiplying by 5/4.
CHAPTER 3

Percent is a multiplier

THEORY

A $40 lunch, 8% tax. Most kids do two steps: find 8% of 40 (that’s $3.20), then add it on ($43.20). Watch a faster kid do it in one: $40 × 1.08 = $43.20. Done. No side calculation, no adding.

The difference is one habit. Stop reading a percent as a thing you find and add. Read it as a number you multiply by.

Build the multiplier straight from the words:

Read the words → build the multiplierUP by p%× (1 + p/100)+8% tax× 1.08DOWN by p%× (1 − p/100)50% off× 0.5p% OF× (p/100)20% of it× 0.20

THE MOVE — PERCENT IS A MULTIPLIER

  • p% OF B is (p/100) × B.
  • Up by p% is (1 + p/100) × B.  +10% → ×1.10.
  • Down by p% is (1 − p/100) × B.  −25% → ×0.75.

Once every percent is a multiplier, percent ‘arithmetic’ turns into plain multiplication. A $180 coat at 50% off is $180 × 0.5 = $90 — no ‘find half, then subtract’ two-step.

🎯 Try it
A $70 jacket is marked up 20%. What’s the new price, in dollars? (Build the multiplier — one step.)
Walkthrough: Up 20% means × 1.20. So $70 × 1.20 = $84. (The slow way: 20% of 70 is $14, then $70 + $14 = $84. Same answer, two steps instead of one.)
THE TRICK

‘Save’ means the savings, not the new price — and the discount lands on the whole purchase, so multiply once at the end.

20% off a $12.50 order: the amount saved is $12.50 × 0.20 = $2.50. You don’t need the sale price at all when the question only asks how much you saved.

WORKED EXAMPLE
PROBLEM · 2005 #2

Karl bought five folders from Pay-A-Lot at a cost of $2.50 each. Pay-A-Lot had a 20%-off sale the following day. How much could Karl have saved on the purchase by waiting a day?

A) $1.00 B) $2.00 C) $2.50 D) $2.75 E) $5.00

Karl buys five folders at $2.50 each, so the order is 5 × $2.50 = $12.50. A day later it’s 20% off. How much could he have saved?

Saved means the discount itself. 20% off is the multiplier × 0.20 on the total:

$12.50 × 0.20 = $2.50 (answer C).

The instinct is to find the sale price first ($12.50 × 0.8 = $10) and then subtract ($12.50 − $10 = $2.50). That works, but it’s the long road. The question asks for the savings, and the savings is the percent-off times the total — one multiplication, no subtraction.

Answer: C — $2.50.
RULE OF THUMB

Every percent change is a multiplier. Build it straight from the words: up → 1+, down → 1−, ‘of’ → the bare fraction. Then multiply once.

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2003 · #5 If 20% of a number is 12, what is 30% of the same number?

If 20% of a number is 12, what is 30% of the same number?

Show answer
Answer: B — 18.
Show hints
Hint 1 of 2
The mystery number never has to be found — 30% and 20% of the SAME number are themselves in a fixed ratio.
Still stuck? Show hint 2 →
Hint 2 of 2
30% is 1.5 times as much as 20%, so the answer is 1.5 times the 12.
Show solution
Approach: scale the known percentage up directly
  1. Both percentages sit on the same number, so 30% relates to 20% the same way 30 relates to 20: it's 1.5 times as big.
  2. Whatever 20% is worth (12), 30% is 1.5 of that: 1.5 × 12 = 18.
  3. Why this is faster: a handier unit here is 10%, which is 12 ÷ 2 = 6. Then 30% = three of those tens = 6 × 3 = 18. Working in 10%-chunks skips finding the whole number entirely.
Another way — find the whole first:
  1. 20% of the number is 12, so the number is 12 ÷ 0.2 = 60.
  2. 30% of 60 = 0.3 × 60 = 18.
1992 · #4 During the softball season, Judy had 35 hits. Among her hits were 1 home run, 1 triple, and 5 doubles. The rest of her hits were...

During the softball season, Judy had 35 hits. Among her hits were 1 home run, 1 triple, and 5 doubles. The rest of her hits were singles. What percent of her hits were singles?

Show answer
Answer: E — 80%.
Show hints
Hint 1 of 3
The listed hits (home run, triple, doubles) are the FEW; singles are everything else. Is it easier to count the few and subtract, or count the many directly?
Still stuck? Show hint 2 →
Hint 2 of 3
When most of a group is one thing, count the small leftover pile and subtract from the total — the complement is the shortcut.
Still stuck? Show hint 3 →
Hint 3 of 3
Once you have the number of singles, "what percent" just means singles ÷ total.
Show solution
Approach: count the small pile (non-singles), subtract, then take the percent
  1. Only a few hits are named, so count those: 1 home run + 1 triple + 5 doubles = 7 non-singles. Everything else is a single: 35 − 7 = 28 singles.
  2. Percent of singles = 28 ÷ 35. Since 28/35 = 4/5, that's 80%.
  3. Why this transfers: when one category dominates, it's faster to count its complement (the leftovers) and subtract than to tally the big group directly — the same move shows up in probability ("at least one" problems) all the time.
  4. Sanity check: 7 non-singles is one-fifth of 35, so singles must be the other four-fifths — 80% — matching our answer.
2003 · #3 A burger at Ricky C's weighs 120 grams, of which 30 grams are filler. What percent of the burger is not filler?

A burger at Ricky C's weighs 120 grams, of which 30 grams are filler. What percent of the burger is not filler?

Show answer
Answer: D — 75%.
Show hints
Hint 1 of 2
"Percent that is NOT filler" means the non-filler part compared to the whole burger — find that part first.
Still stuck? Show hint 2 →
Hint 2 of 2
Percent of a whole = part ÷ whole, written out of 100.
Show solution
Approach: part over whole
  1. The question asks for the non-filler part, so peel it off first: 120 − 30 = 90 grams are not filler.
  2. Now compare that part to the whole burger: 90/120. This simplifies to 3/4 = 75%.
  3. Shortcut check: the filler is 30/120 = 1/4 = 25%, and the rest must make 100%, so 100% − 25% = 75% — same answer, faster. Finding one part and subtracting from 100% often beats computing the other part directly.
Another way — filler percent, then subtract from 100%:
  1. Filler is 30 of 120 grams = 30/120 = 1/4 = 25%.
  2. Everything else is 100% − 25% = 75%.
2013 · #2 A sign at the fish market says, "50% off, today only: half-pound packages for just $3 per package." What is the regular price for a full...

A sign at the fish market says, "50% off, today only: half-pound packages for just $3 per package." What is the regular price for a full pound of fish, in dollars? (Assume that there are no deals for bulk.)

Show answer
Answer: D — $12.
Show hints
Hint 1 of 2
Two separate doublings are hiding here: a half-pound is half of a pound (one doubling), and a 50%-off price is half of the regular price (another doubling). What happens if you double twice?
Still stuck? Show hint 2 →
Hint 2 of 2
"50% off" means the sale price is half the original, so to undo it you double. Always ask "what fraction of the original is this?" before reaching for the discount.
Show solution
Approach: double once for the full pound, double again to undo 50% off
  1. $3 buys half a pound, so a full pound at the sale price is 2 × $3 = $6.
  2. "50% off" means $6 is only half of the regular price, so regular = 2 × $6 = $12.
  3. Watch the trap: the two halvings (half-pound and half-price) tempt you to answer $6. Doubling twice — ×4 from the $3 — lands you at $12.
2005 · #11 The sales tax rate in Bergville is 6%. During a sale at the Bergville Coat Closet, the price of a coat is discounted 20% from its $90.00...

The sales tax rate in Bergville is 6%. During a sale at the Bergville Coat Closet, the price of a coat is discounted 20% from its $90.00 price. Two clerks, Jack and Jill, calculate the bill independently. Jack rings up $90.00 and adds 6% sales tax, then subtracts 20% from this total. Jill rings up $90.00, subtracts 20% of the price, then adds 6% of the discounted price for sales tax. What is Jack's total minus Jill's total?

Show answer
Answer: C — $0.
Show hints
Hint 1 of 2
Resist computing the two bills. Instead, write each as 90 times some multipliers — 'add 6%' is ×1.06, 'take 20% off' is ×0.80. Then just compare.
Still stuck? Show hint 2 →
Hint 2 of 2
Both clerks multiply by the same three numbers, only in a different order. What do you know about how order affects a product?
Show solution
Approach: see them as the same product reordered
  1. Translate each step into a multiplier: 'add 6% tax' is ×1.06, 'discount 20%' is ×0.80.
  2. Jack does 90 · 1.06 · 0.80; Jill does 90 · 0.80 · 1.06. Same three factors, swapped order.
  3. Multiplication doesn't care about order, so the totals are identical — the difference is $0.
  4. Why this transfers: stacked percentage changes are just multipliers, and multipliers commute. 'Discount then tax' always equals 'tax then discount' — recognizing this saves you from grinding out two dollar amounts (and from the ±$1.06 traps).
2016 · #6 At Anna’s school 45 teachers come to school by bike, and that is 60% of all the teachers. Only 12% of the teachers come to school by...

At Anna’s school 45 teachers come to school by bike, and that is 60% of all the teachers. Only 12% of the teachers come to school by car. How many teachers come to school by car?

Show answer
Answer: C — 9
Show hints
Hint 1 of 2
First find the total number of teachers from the 60% fact.
Still stuck? Show hint 2 →
Hint 2 of 2
Then take 12% of that total.
Show solution
Approach: find the whole, then a percent of it
  1. 45 teachers are 60% of all teachers, so the total is 45 ÷ 0.60 = 75 teachers.
  2. 12% of 75 is 0.12 × 75 = 9 teachers come by car.
CHAPTER 4

Compound percent — when +25% and −20% return to start

THEORY

A stock goes up 25% on Monday and down 25% on Tuesday. Back to even, right? Wrong — and that gap is the most famous percent trap in contest math.

Start with $100. Up 25% → $125. Now drop that by 25%: $125 × 0.75 = $93.75. You ended below where you started, down $6.25.

Here’s why your gut was wrong: the 25% down is taken off the bigger number ($125), so it’s worth more dollars than the 25% up was. Same percent, different base.

Up 25%, then down 25% — not a round trip$100start$125+25% (×1.25)$93.75−25% (×0.75)start line

The fix is to multiply the multipliers: 1.25 × 0.75 = 0.9375. The chain never adds.

COMPOUND PERCENT

+p% then +q% is ×(1+p/100)(1+q/100). Multiply the multipliers.

The result is never +(p+q)%, except when p=0 or q=0.

Two important special cases:

  • +25%, then −20%: ×1.25 × ×0.8 = ×1.00. Returns to start. Because 0.8 = 1/1.25.
  • +10% four times: ×(1.1)⁴ = ×1.4641 — about 46.4%, NOT 40%.

THE MOVE — STACK BY MULTIPLYING

String the percent changes into one multiplier and multiply them all at once. +25%, then −20% → 1.25 × 0.80 = 1.00. Whatever the chain, the answer is the product — never the sum.

🎯 Try it
A $1 price goes up 10%, then down 10%. The new price is what percent of the original? (Type the number.)
Walkthrough: Up 10% is ×1.10, down 10% is ×0.90. Stack them: 1.10 × 0.90 = 0.99 = 99%. Not 100% — the down-step hit the bigger number, so you end a hair low. (Try the same with 50% up/down: 1.5 × 0.5 = 0.75, only 75% left.)
THE TRICK

The instant you see two percent changes stacked, reach for one multiplier — never a sum. Up by p then down by q is (1 + p/100)(1 − q/100), one multiplication and done.

Quick reflex: +50% then −50% feels like a wash, but 1.5 × 0.5 = 0.75 — you keep only three-quarters. The bigger the swings, the more the ‘add them up’ guess overshoots.

WATCH OUT
Bogus solution

A $600 laptop is 20% off, and you also have a coupon for 30% off. So the price drops by 20% + 30% = 50%. Half of $600 is $300 — you pay $300.

Why it breaks: The two discounts hit different prices. The 20% comes off $600, but the 30% comes off the already-reduced price, not the original — so the percents don’t add.

The fix: Multiply the multipliers. 20% off is ×0.80; 30% off is ×0.70. Together 0.80 × 0.70 = 0.56, so you pay $600 × 0.56 = $336 — a 44% discount, not 50%. Step by step: $600 → $480 → $336.

Trap framing inspired by AoPS Prealgebra.

WORKED EXAMPLE
PROBLEM · 1988 #22

Tom's Hat Shoppe increased all original prices by 25%. Now the shoppe is having a sale where all prices are 20% off these increased prices. Which statement best describes the sale price of an item?

A) The sale price is 5% higher than the original price. B) The sale price is higher than the original price, but by less than 5%. C) The sale price is higher than the original price, but by more than 5%. D) The sale price is lower than the original price. E) The sale price is the same as the original price.

+25% is ×1.25. −20% off the new price is ×0.8. Combined multiplier:

1.25 × 0.8 = 1.00.

The sale price equals the original. The 25% up and 20% down exactly cancel because 0.8 = 1/1.25.

The pair (+25%, −20%) is one of the contest's favorite traps because the numbers look different (one is bigger). Once you see ×1.25 and ×0.8 as reciprocals, the answer is instant.

Answer: E — The sale price is the same as the original price.
RULE OF THUMB

+1/n turns into a ×(1 + 1/n). Its undo is ÷(1 + 1/n), which equals ×(1 − 1/(n+1)). So +1/n undoes with −1/(n+1). +25%=+1/4 undoes with −1/5 = −20%. Memorize this pattern.

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2009 · #8 The length of a rectangle is increased by 10% and the width is decreased by 10%. What percent of the old area is the new area?

The length of a rectangle is increased by 10% and the width is decreased by 10%. What percent of the old area is the new area?

Show answer
Answer: B — 99%.
Show hints
Hint 1 of 2
Tempting trap: "+10% then −10% cancels to 0." It doesn't — the 10% you take off is computed from the BIGGER length, so the drop slightly outweighs the gain.
Still stuck? Show hint 2 →
Hint 2 of 2
Turn each percent change into a multiplier (up 10% → ×1.1, down 10% → ×0.9) and just multiply them. Area = length × width, so the area's multiplier is the product.
Show solution
Approach: multiply the multipliers
  1. New area ÷ old area = 1.1 × 0.9 = 0.99 = 99%.
  2. Intuition for the 1% loss: 1.1 × 0.9 = (1 + 0.1)(1 − 0.1) = 1 − 0.1² = 1 − 0.01. The leftover is the square of the percent — tiny, and always a LOSS.
  3. You'll see it again: stacked percent changes always multiply, never add. "Raise then drop by the same %" always ends below where you started, by exactly (that %)².
2008 · #9 In 2005 Tycoon Tammy invested 100 dollars for two years. During the first year her investment suffered a 15% loss, but during the second...

In 2005 Tycoon Tammy invested 100 dollars for two years. During the first year her investment suffered a 15% loss, but during the second year the remaining investment showed a 20% gain. Over the two-year period, what was the change in Tammy's investment?

Show answer
Answer: D — 2% gain.
Show hints
Hint 1 of 2
The 20% gain is on the shrunken $85, not the original $100 — so −15% then +20% does NOT cancel to +5%.
Still stuck? Show hint 2 →
Hint 2 of 2
Turn each change into a multiplier (lose 15% = ×0.85, gain 20% = ×1.20) and multiply them in a row.
Show solution
Approach: chain the percentage multipliers
  1. Each year scales the money: a 15% loss is ×0.85, a 20% gain is ×1.20. Doing them in sequence means multiplying: 0.85 × 1.20 = 1.02.
  2. 1.02 means the money ended at 102% of the start — a 2% gain. The starting $100 never even matters.
  3. Why this transfers: percent changes compound (multiply), they never add — that's why the +20% can't undo the −15% to give +5%.
Another way — track the actual dollars:
  1. After year 1: 100 − 15% = $85. After year 2: 85 + 20% of 85 = 85 + 17 = $102.
  2. From $100 to $102 is a 2% gain.
1985 · #21 Mr. Green receives a 10% raise every year. His salary after four such raises has gone up by what percent?

Mr. Green receives a 10% raise every year. His salary after four such raises has gone up by what percent?

Show answer
Answer: E — more than 45%.
Show hints
Hint 1 of 2
A raise is a MULTIPLY, not an add. Each year the salary becomes 1.10 times the year before — so four raises means ×1.10 four times over, not +10% four times. Those give different answers.
Still stuck? Show hint 2 →
Hint 2 of 2
Because every raise also raises the previous raises, the total beats the naive 4 × 10% = 40%. The question is whether the extra 'raise-on-raise' pushes past 45% — so you only need a rough size, not the exact figure.
Show solution
Approach: compound the raises step by step
  1. Start at 1.00 and multiply by 1.10 each year: after year 1, 1.10; year 2, 1.21; year 3, 1.331; year 4, ≈ 1.4641.
  2. That's about a 46% increase — more than 45%, so the answer is more than 45%.
  3. Why it beats 40%: simply adding 10% four times ignores that later raises act on an already-bigger salary. After two years alone you're at 1.21 (a 21% gain, not 20%) — that extra 1% snowballs, landing you past 45% by year four. This 'interest on interest' is the heart of compounding.
Another way — eyeball without exact arithmetic:
  1. Two 10% raises multiply to 1.10 × 1.10 = 1.21. Four raises = (1.21)² = 1.21 × 1.21.
  2. 1.21 × 1.21 is clearly above 1.21 × 1.20 = 1.452, so the gain exceeds 45% — answer is more than 45% without ever finishing the multiplication.
2019 · #22 A store increased the original price of a shirt by a certain percent and then decreased the new price by the same amount. Given that the...

A store increased the original price of a shirt by a certain percent and then decreased the new price by the same amount. Given that the resulting price was 84% of the original price, by what percent was the price increased and decreased?

Show answer
Answer: E — 40%.
Show hints
Hint 1 of 2
Up then down by the same percent does NOT return to the start — the decrease acts on a bigger price. Write it as multipliers: ×(1+p) then ×(1−p), and let difference-of-squares simplify the product.
Still stuck? Show hint 2 →
Hint 2 of 2
(1+p)(1−p) = 1 − p2. Set that equal to 0.84 and the percent pops right out.
Show solution
Approach: the two changes multiply to 1 − p²
  1. Raising by p then lowering by p multiplies the price by (1 + p)(1 − p) = 1 − p2 — a difference of squares, neatly collapsing the two steps into one.
  2. Set 1 − p2 = 0.84, so p2 = 0.16 and p = 0.4 = 40%.
  3. Why this transfers: a percent up and the same percent down always leaves 1 − p2 — strictly less than the original, since the drop applies to a larger amount. Recognizing (1+p)(1−p) as a difference of squares is the shortcut.
2012 · #8 A shop advertises everything is "half price in today's sale." In addition, a coupon gives a 20% discount on sale prices. Using the...

A shop advertises everything is "half price in today's sale." In addition, a coupon gives a 20% discount on sale prices. Using the coupon, the price today represents what percentage off the original price?

Show answer
Answer: D — 60%.
Show hints
Hint 1 of 2
Don't add 50% + 20% — the 20% comes off the already-halved price, not the original. Track what survives each step, not what's taken off.
Still stuck? Show hint 2 →
Hint 2 of 2
This is chaining percentages by multiplying: a discount of d leaves the fraction (1 − d), and successive discounts multiply. Always work with the surviving fraction.
Show solution
Approach: multiply the surviving fractions, then subtract from 1
  1. Half price means you still pay 1/2 of the original. The 20%-off coupon then leaves 80% = 0.8 of that, so discounts chain by multiplying.
  2. What you actually pay: 0.5 × 0.8 = 0.4 of the original price.
  3. So the total discount is 1 − 0.4 = 60% — not the 70% you'd get by wrongly adding 50 + 20.
  4. Why multiply, not add: each percent acts on the price left after the previous one. Multiplying the "keep" fractions is the safe path for any stacked discount or tax.
2013 · #12 At the 2013 Winnebago County Fair a vendor is offering a "fair special" on sandals. If you buy one pair of sandals at the regular price...

At the 2013 Winnebago County Fair a vendor is offering a "fair special" on sandals. If you buy one pair of sandals at the regular price of $50, you get a second pair at a 40% discount, and a third pair at half the regular price. Javier took advantage of the "fair special" to buy three pairs of sandals. What percentage of the $150 regular price did he save?

Show answer
Answer: B — 30%.
Show hints
Hint 1 of 2
"Percent saved" always means dollars-saved compared to the full regular price ($150 for three pairs), not to what he ended up paying. So you only need the total dollars knocked off.
Still stuck? Show hint 2 →
Hint 2 of 2
Percent saved = (dollars saved) ÷ (original price). Find the savings in dollars first; the percentages 40% and 50% are just shortcuts to those dollar amounts.
Show solution
Approach: total dollars saved ÷ regular price
  1. Only the 2nd and 3rd pairs are discounted (the 1st is full price). Convert each discount to dollars: 40% of $50 = $20 saved, and half of $50 = $25 saved.
  2. Total saved = $20 + $25 = $45, against the regular three-pair price of $150.
  3. Percent saved = 45 ÷ 150 = 30%.
  4. Watch the trap: the discounts 40% and 50% average to 45%, but each applies to only one of three pairs — spreading the savings over the full $150 is what drops the answer to 30%.
2024 · #23 Fresh mushrooms consist of 80% water. In dried mushrooms, however, the water is only 20% of the mass. By what percentage does the mass...

Fresh mushrooms consist of 80% water. In dried mushrooms, however, the water is only 20% of the mass. By what percentage does the mass of a mushroom decrease during drying?

Show answer
Answer: C — 75
Show hints
Hint 1 of 2
The dry solid part of the mushroom never changes when water leaves; only water mass drops.
Still stuck? Show hint 2 →
Hint 2 of 2
Track the solid mass: it is 20% before and 80% after, so set up the new total from the fixed solid.
Show solution
Approach: hold the solid mass fixed and find the new total
  1. Take 100 g fresh: 80% water means 20 g of solid.
  2. Dried, water is 20% so solid is 80% of the new mass: 20 = 0.8 × new, giving new = 25 g.
  3. Mass drops from 100 g to 25 g, a decrease of 75%.
★ MINI-QUIZ

Percent basics — multipliers and compounds

Three problems on +p% = ×(1+p/100) and stacking percent changes.

2020 · #5 Three fourths of a pitcher is filled with pineapple juice. The pitcher is emptied by pouring an equal amount of juice into each of 5...

Three fourths of a pitcher is filled with pineapple juice. The pitcher is emptied by pouring an equal amount of juice into each of 5 cups. What percent of the total capacity of the pitcher did each cup receive?

Show answer
Answer: C — 15%.
Show hints
Hint 1 of 2
The question asks for a percent of the whole pitcher, not of the juice. So divide the 34 that's there among 5 cups — each share is still measured against the full pitcher.
Still stuck? Show hint 2 →
Hint 2 of 2
Each cup gets 34 ÷ 5 = 320 of the pitcher. To make a percent, rewrite it with denominator 100.
Show solution
Approach: split the fraction, then scale to /100
  1. Each cup gets 34 ÷ 5 = 320 of the whole pitcher (the “of the pitcher” never goes away).
  2. Percent means “out of 100,” so scale the denominator to 100: 320 = 15100 = 15%.
  3. Sanity check: 5 cups × 15% = 75%, exactly the 34 we poured. The shares add back to the whole.
Another way — percent first, then split:
  1. 34 of the pitcher is 75%.
  2. Five equal cups means each gets 75% ÷ 5 = 15%.
2016 · #6 At Anna’s school 45 teachers come to school by bike, and that is 60% of all the teachers. Only 12% of the teachers come to school by...

At Anna’s school 45 teachers come to school by bike, and that is 60% of all the teachers. Only 12% of the teachers come to school by car. How many teachers come to school by car?

Show answer
Answer: C — 9
Show hints
Hint 1 of 2
First find the total number of teachers from the 60% fact.
Still stuck? Show hint 2 →
Hint 2 of 2
Then take 12% of that total.
Show solution
Approach: find the whole, then a percent of it
  1. 45 teachers are 60% of all teachers, so the total is 45 ÷ 0.60 = 75 teachers.
  2. 12% of 75 is 0.12 × 75 = 9 teachers come by car.
2026 · #4 Brynn's savings decreased by 20% in July, then increased by 50% of the new amount in August. Brynn's savings are now what percent of the...

Brynn's savings decreased by 20% in July, then increased by 50% of the new amount in August. Brynn's savings are now what percent of the original amount?

Show answer
Answer: E — 120%.
Show hints
Hint 1 of 2
Careful — the answer isn't simply −20 + 50 = +30%. The 50% rise acts on the already-shrunk amount, so the two changes don't just add.
Still stuck? Show hint 2 →
Hint 2 of 2
Turn each change into a multiplier (×0.8, then ×1.5) and multiply them — that's how percent changes compound, and you never need the starting amount.
Show solution
Approach: turn each percent change into a multiplier
  1. A percent change is really a multiplier: down 20% leaves 80%, so × 0.8; up 50% means × 1.5. And changes chain by multiplying, so you never need a starting amount.
  2. 0.8 × 1.5 = 1.2, which is 120% of the original.
  3. Watch the trap: the answer is not −20% + 50% = +30%. Percents stack by multiplying, not adding, because the +50% applies to the shrunken amount, not the original.
Another way — plug in a friendly number:
  1. Pretend Brynn started with $100. July: down 20% leaves $80. August: up 50% of $80 adds $40, giving $120.
  2. $120 out of the original $100 is 120%. Picking 100 makes the percent fall right out.
CHAPTER 5

Comparing fractions without computing them

THEORY

Which is bigger, 4/9 or 17/35? Reach for a calculator and you’ve already lost the race. Both are a whisker under one-half — and a contest writes them that way on purpose, daring you to divide. You don’t have to. Three habits let you rank fractions by looking.

FRACTION-COMPARISON TRICKS

  • Compare to ½. A fraction a/b is bigger than ½ exactly when 2a > b. Test mentally.
  • Compare two fractions by cross-multiplying. a/b > c/d exactly when ad > bc (assuming b, d positive). No common denominator needed.
  • Compare to 1. Top bigger than bottom → fraction > 1; top smaller → < 1.

The number-line picture. Imagine a number line from 0 to 1, with ½ marked in the middle. Every fraction lives somewhere on this line. Comparing to ½ tells you which half it's in.

0½13/74/917/35100/201151/301

Four of these five fractions sit just below ½. Only 151/301 crosses over.

How to compare to ½ in your head. Double the top; if it's bigger than the bottom, the fraction beats ½.

  • Is 151/301 bigger than ½? Double 151 = 302. Compare to 301: 302 > 301, so YES, 151/301 > ½.
  • Is 100/201 bigger than ½? Double 100 = 200. Compare to 201: 200 < 201, so 100/201 < ½.

For five-way comparisons, use the landmark idea: compare each candidate to ½ first. Any below ½ is eliminated immediately if a candidate above ½ exists.

WHY cross-multiplying works (it is just a hidden common denominator)

The rule says a/b > c/d exactly when ad > bc. That can feel like a spell. It isn’t — it is the common-denominator method with the writing hidden.

To compare 3/5 and 4/7 the honest way, give both the same bottom, 5 × 7 = 35:

3/5 = (3×7)/35 = 21/35    and    4/7 = (4×5)/35 = 20/35.

Now both bottoms are 35, so the bigger fraction is just the bigger top: 21 vs 20. But look at where those tops came from — 3×7 and 4×5. Those are exactly the two cross-products! Cross-multiplying compares the numerators you would get over the common denominator bd — without writing the 35. Since 21 > 20, 3/5 > 4/7.

THE MOVE — CROSS, KEEPING SIDES STRAIGHT

Multiply each top by the OTHER fraction’s bottom, and keep each product on its own fraction’s side: a/b gets a×d, c/d gets c×b. Bigger product wins. (Works only when both bottoms are positive — a negative bottom flips the inequality.)

Framing inspired by AoPS Prealgebra.

🎯 Try it
Use cross-products to compare 5/8 and 3/5. Is 5/8 the larger? Type 1 for yes, 0 for no.
Walkthrough: Cross-multiply: 5/8 gets 5×5 = 25; 3/5 gets 3×8 = 24. Since 25 > 24, 5/8 > 3/5. (Common-denominator check: over 40, that is 25/40 vs 24/40.) Answer: 1.
🎯 Try it
Is 5/9 bigger than ½? Type 1 for yes, 0 for no.
Walkthrough: Double the top: 2 × 5 = 10. Compare to the bottom, 9. Since 10 > 9, the fraction clears ½, so 5/9 > ½. Answer: 1. (One doubling, one comparison — no division.)
THE TRICK

For a fraction a/b close to ½, look at 2a − b: positive means > ½, negative means < ½. Quick mental check.

WATCH OUT
Bogus solution

Which is bigger, 2/5 or 2/7? They have the same top, 2. The bottom of 2/7 is bigger, and bigger numbers win — so 2/7 is the larger fraction.

Why it breaks: A bigger bottom means you cut the whole into more pieces, so each piece is smaller. Sevenths are tinier than fifths, so two of them is less, not more.

The fix: With the same top, the fraction with the smaller bottom is bigger: 2/5 > 2/7. Picture two equal bars — cut one into 5, the other into 7, shade 2 of each: the fifths-bar sticks out farther.

Trap framing inspired by AoPS Prealgebra.

WORKED EXAMPLE
PROBLEM · 2019 #3

Which of the following is the correct order of the fractions 1511, 1915, and 1713, from least to greatest?

A) 1511 < 1713 < 1915 B) 1511 < 1915 < 1713 C) 1713 < 1915 < 1511 D) 1915 < 1511 < 1713 E) 1915 < 1713 < 1511

Order 15/11, 19/15, 17/13 from least to greatest.

Each top beats its bottom by exactly 4, so peel off the 1: 15/11 = 1 + 4/11,  19/15 = 1 + 4/15,  17/13 = 1 + 4/13.

Now you’re only ranking the leftovers 4/11, 4/15, 4/13 — same top of 4, so the one with the biggest bottom is smallest. Bottoms 11, 13, 15 give 4/15 < 4/13 < 4/11.

So 19/15 < 17/13 < 15/11 (answer E). No division, no common denominator.

The instinct is to slam all three onto a common denominator (11 × 13 × 15 — ugh). Resist it. When every fraction is ‘1 plus the same numerator over different bottoms,’ you only compare the bottoms: bigger bottom, smaller piece. The whole problem collapses to ordering 11, 13, 15.

Answer: E — 19/15 < 17/13 < 15/11.
RULE OF THUMB

Compare to a landmark first (½ or 1) to sieve. For fractions just over 1 with a shared numerator, rank the leftover above 1: bigger bottom means smaller fraction. Cross-multiply only the close calls; decimals last.

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1994 · #1 Which of the following is the largest?

Which of the following is the largest?

Show answer
Answer: D — 5/12.
Show hints
Hint 1 of 2
You can't compare fractions by eye when the bottoms are all different — first give them a shared yardstick.
Still stuck? Show hint 2 →
Hint 2 of 2
Rewrite every fraction over one common denominator (24 fits all of them). Once the bottoms match, the fraction with the biggest top wins.
Show solution
Approach: compare over a common denominator
  1. All five bottoms (3, 4, 8, 12, 24) divide 24, so 24 is the natural common yardstick. Rewrite each: 1/3 = 8/24, 1/4 = 6/24, 3/8 = 9/24, 5/12 = 10/24, 7/24 = 7/24.
  2. Now the bottoms all match, so just read off the biggest top: 10 wins, so 5/12 is largest.
  3. Why this works: a fraction's size is 'how many pieces' (top) of 'a fixed piece-size' (bottom). Only when the piece-size is the same can you compare by counting pieces. You'll reuse this every time you add, subtract, or order fractions.
Another way — compare each to a benchmark:
  1. Notice 1/3, 1/4, 7/24 are all below 1/3 ≈ 0.33, while 3/8 = 0.375 and 5/12 ≈ 0.417 are bigger.
  2. Between the two big ones, 5/12 > 3/8 (10/24 vs 9/24), so 5/12 is largest — no full common denominator needed if you only care about the top contenders.
1992 · #2 Which of the following is not equal to 54?

Which of the following is not equal to 54?

Show answer
Answer: D — 1 1/5.
Show hints
Hint 1 of 3
5/4 is one whole plus a quarter. Which choices are secretly just a quarter dressed up — and which one hides a different-sized piece?
Still stuck? Show hint 2 →
Hint 2 of 3
When choices look different but might be equal, convert them all to ONE common form (a decimal, or a fraction over the same bottom number) so they line up for comparison.
Still stuck? Show hint 3 →
Hint 3 of 3
A bigger denominator means a smaller slice: 1/5 is less than 1/4, so don't be fooled into reading 1 1/5 as 1.25.
Show solution
Approach: rewrite every choice in one common form so the odd one out stands out
  1. 5/4 = 1 + 1/4 = 1.25. Now test each: 10/8 = 1.25 (just doubled top and bottom); 1 1/4 = 1.25; 1 3/12 = 1 + 1/4 = 1.25 (3/12 reduces to 1/4); 1 10/40 = 1 + 1/4 = 1.25 (10/40 reduces to 1/4).
  2. That leaves 1 1/5. Since 1/5 = 0.2, this is 1.2, NOT 1.25 — so 1 1/5 is the one not equal.
  3. Trap to remember: a fifth feels "close" to a quarter, but cutting something into 5 pieces gives smaller pieces than cutting into 4. The trickster choice swaps the denominator from 4 to 5 hoping you won't notice the slice shrank.
1986 · #2 Which of the following numbers has the largest reciprocal?

Which of the following numbers has the largest reciprocal?

Show answer
Answer: A — 1⁄3.
Show hints
Hint 1 of 2
Picture cutting a pizza: dividing 1 into *more* pieces (a bigger number on the bottom) makes each piece *smaller*. So which number gives the biggest reciprocal?
Still stuck? Show hint 2 →
Hint 2 of 2
Reciprocal flips a number over 1, and flipping reverses the order: the smallest positive number has the largest reciprocal.
Show solution
Approach: flipping reverses size order
  1. The reciprocal of a positive number is 1 over it. Taking 1-over reverses the size order — the *smallest* number turns into the *largest* reciprocal. So you never have to compute a single reciprocal; just find the smallest number.
  2. The smallest of the choices is 1⁄3; its reciprocal is 3, larger than the reciprocals of 1, 5, and 1986 (which are all 1 or less).
  3. Why this transfers: whenever you flip a list of positive numbers, biggest and smallest swap places — handy for spotting the answer without arithmetic.
CHAPTER 6

Complex fractions — top first, bottom next, divide last

THEORY

Some problems look like a fraction that fell into a blender:

(1 − 1/3) ÷ (1 − 1/2)

That’s a complex fraction — fractions stacked inside fractions. Your eye wants to smash all four pieces under one giant common denominator at once. That’s where kids drop a sign or a factor. Don’t. Break it into THREE small, safe steps:

Simplify: (1 − 1/3) ÷ (1 − 1/2)Step 1: simplify the TOP1 − 1/3= 3/3 − 1/3= 2/3Step 2: simplify the BOTTOM1 − 1/2= 2/2 − 1/2= 1/2Now stack:2/31/2Step 3: divide (Keep, Change, Flip)2/3 ÷ 1/2start2/3 × 2/1flip the second fraction=4/3multiply across=1⅓Three small operations beat one big one. NEVER try to find a common denominator across all four pieces at once.

THE RECIPE

  1. Simplify the TOP to one fraction.
  2. Simplify the BOTTOM to one fraction.
  3. Divide: Keep the first, Change ÷ to ×, Flip the second. (“KCF.”)

What division even MEANS: “how many fit?”

Before the flip rule, ask what dividing by a fraction is really asking. 6 ÷ 2 asks “how many 2s fit in 6?” (three). In the same way, 6 ÷ ¾ asks “how many ¾-cups fit in 6 cups?” The pieces are small, so a lot of them fit — that is why the answer comes out bigger than 6.

How many ¾-cup scoops fill 6 cups?black lines = the 6 whole cups; teal dashes mark each ¾-cup scoop8 scoops fit → 6 ÷ ¾ = 8each scoop is ¾ of a cup, so 8 of them is 8 × ¾ = 6 cups ✓

Counting confirms it: eight ¾-cups is 8 × ¾ = 6 cups exactly. And the flip rule gives the same thing in one line: 6 ÷ ¾ = 6 × 4/3 = 24/3 = 8. The reciprocal isn’t a magic trick — it is literally counting how many pieces fit.

Framing inspired by AoPS Prealgebra.

🎯 Try it
A recipe needs ⅓-cup scoops of flour. How many scoops fill a 5-cup bag? (Ask “how many ⅓-cups fit in 5?”) Type the number.
Walkthrough: “How many ⅓-cups fit in 5?” is 5 ÷ ⅓ = 5 × 3 = 15. Check: 15 scoops of ⅓ cup is 15 × ⅓ = 5 cups. 15 scoops.

Why “flip the second” works

Dividing by 1/2 is the SAME as multiplying by 2. Because asking “how many halves fit?” doubles whatever you started with.

Division= Multiplication by flipped secondAnswer
5 ÷ 1/35 × 315
6 ÷ 2/36 × 3/29
(3/4) ÷ (2/5)(3/4) × (5/2)15/8
10 ÷ 1/410 × 440
The TRAP: dividing by a fraction makes the number BIGGER (when the divisor is < 1). Kids expect division to make things smaller.
🎯 Try it
Simplify (1 − 1/2) ÷ (1/16). (Top first, then KCF.) Type the number.
Walkthrough: Top: 1 − 1/2 = 1/2. Bottom is already 1/16. Keep-Change-Flip: (1/2) × (16/1) = 16/2 = 8. Dividing by 1/16 multiplied it 16-fold — the answer grew, as it should.
THE TRICK

Dividing by a fraction is multiplying by its flip (reciprocal). ÷ (1/n) = × n. So 5 ÷ (1/3) = 15, not 5/3.

Memorize the rule: Keep, Change, Flip (KCF). Keep the first fraction, change ÷ to ×, flip the second fraction. (3/4) ÷ (2/5) = (3/4) × (5/2) = 15/8.

WORKED EXAMPLE
PROBLEM · 1986 #6

2 ⁄ (1 − 2⁄3) =

A) −3 B) −4⁄3 C) 2⁄3 D) 2 E) 6

The expression is 2 ÷ (1 − 2/3).

Top is already one number: 2. Bottom: 1 − 2/3 = 1/3.

Divide using Keep-Change-Flip: 2 ÷ (1/3) = 2 × (3/1) = 6 (answer E).

The big trap is the bottom: 1 − 2/3 is 1/3, not 2/3 or 1/2. Once the bottom is a single fraction, dividing by 1/3 triples the top — so the answer (6) is bigger than the 2 you started with. Dividing by a number under 1 grows it.

Answer: E — 6.
RULE OF THUMB

Simplify top and bottom separately. Then KCF (Keep-Change-Flip) the bottom. Dividing by a number under 1 makes the result bigger — that’s the sanity check.

MORE LIKE THIS
1998 · #3 38 + 7845=
38 + 7845=
Show answer
Answer: B — 25/16.
Show hints
Hint 1 of 2
A big fraction-over-a-fraction is just a division: (top) ÷ (bottom). Notice the two pieces on top already share the same denominator, so adding them is a freebie.
Still stuck? Show hint 2 →
Hint 2 of 2
Dividing by a fraction means flipping it and multiplying. Watch for the same fraction showing up twice.
Show solution
Approach: the bar means divide; flipping turns it into a square
  1. The top adds easily because the bottoms match: 3/8 + 7/8 = 10/8 = 5/4.
  2. The big bar means divide by 4/5, and dividing by a fraction means flip-and-multiply: (5/4) ÷ (4/5) = (5/4) × (5/4).
  3. That's the same fraction times itself: (5/4)² = 25/16.
  4. Why this transfers: a fraction stacked over a fraction is always a division in disguise — rewrite it as ÷, then flip the bottom. And a sanity check: 5/4 is a bit over 1, so its square should be a bit over 1; 25/16 ≈ 1.56 fits.
1995 · #3 Which of the following operations has the same effect on a number as multiplying by 34 and then dividing by 35?

Which of the following operations has the same effect on a number as multiplying by 34 and then dividing by 35?

Show answer
Answer: E — multiplying by 5/4.
Show hints
Hint 1 of 2
Dividing by a fraction is the same as multiplying by its flip. So 'divide by 3/5' can become 'multiply by 5/3' — now everything is multiplication.
Still stuck? Show hint 2 →
Hint 2 of 2
Two multiplications in a row are really just one. Combine them into a single multiplier and see which answer it matches.
Show solution
Approach: turn dividing into multiplying by the flip, then merge
  1. The insight: 'divide by 3/5' is the same as 'multiply by 5/3' (flip the divisor). Now both steps are multiplications, which combine cleanly.
  2. So the effect is × 34 × 53. The 3's cancel, leaving × 54 — i.e. multiplying by 5/4.
  3. Why this transfers: any string of ×'s and ÷'s by fractions collapses to one fraction — flip every divisor, then multiply across and cancel.
Another way — test with an easy number:
  1. Pick 12 (divisible by 4 and 3). Multiply by 3/4: 12 → 9. Divide by 3/5: 9 ÷ 3/5 = 9 × 5/3 = 15.
  2. So 12 became 15 — that's × 5/4 (since 12 × 5/4 = 15). Matches multiplying by 5/4.
1996 · #4 What is the value of 2 + 4 + 6 + … + 343 + 6 + 9 + … + 51 ?

What is the value of 2 + 4 + 6 + … + 343 + 6 + 9 + … + 51 ?

Show answer
Answer: B — 2/3.
Show hints
Hint 1 of 2
Don't add anything yet. Look at the top: 2, 4, 6, … are all even — they're 2 times 1, 2, 3, …. The bottom 3, 6, 9, … are 3 times 1, 2, 3, …. The same list is hiding in both.
Still stuck? Show hint 2 →
Hint 2 of 2
Factor the common multiple out of each: top = 2 × (1 + 2 + … + 17), bottom = 3 × (same sum). When the same thing sits top and bottom, it cancels — so don't waste time computing it.
Show solution
Approach: factor out the shared sum so it cancels
  1. Each top term is 2 × something and each bottom term is 3 × something, with the same 'somethings' (1 through 17). So top = 2(1 + 2 + … + 17) and bottom = 3(1 + 2 + … + 17).
  2. The big bracket appears in both, so it cancels — leaving just 2/3. The actual value of 1 + … + 17 never mattered.
  3. Why this transfers: before grinding out a sum or product in a fraction, hunt for a common factor on top and bottom. Cancelling first turns scary arithmetic into a one-line answer.
CHAPTER 7

Multiplying fractions — telescoping products

THEORY

Picture a problem that asks you to multiply a hundred fractions in a row. Looks like a death march. It isn’t — if the fractions are built right, almost every number erases its neighbor and the whole line collapses to one tiny answer.

Start small. (2/3) × (3/4) × (4/5). The 3 on top of the second cancels the 3 on the bottom of the first; the 4 on top of the third cancels the 4 on the bottom of the second. All that survives is the very first top and the very last bottom: 2/5. Two cancellations, zero real multiplying. That domino effect is called telescoping.

TELESCOPING

When a chain of fractions has each numerator matching the previous denominator, all the middle terms cancel and you're left with first-top divided by last-bottom.

Classic case: the product (1 − 1/n) from n = 2 to N.

(1 − 1/2)(1 − 1/3)(1 − 1/4) ⋯ (1 − 1/N) = (1/2)(2/3)(3/4) ⋯ ((N−1)/N) = 1/N

Why? Look at consecutive factors: the 2 on top of 2/3 cancels the 2 on the bottom of 1/2. The 3 on top of 3/4 cancels the 3 on the bottom of 2/3. The 4 on top of 4/5 cancels the 4 on the bottom of 3/4. Each numerator (except the first) kills the denominator on its left, so everything in the middle cancels — leaving the very first numerator (1) over the very last denominator (N).

So a product of 1000 fractions of this kind collapses to a single fraction in one move.

Sums can telescope too

The same cancellation idea works when you’re adding fractions, not only multiplying them — you rewrite each fraction as a difference of two pieces first. Here’s the most useful identity:

SPLIT IDENTITY (the partial-fraction crack)

1 / (n · (n+1)) = 1/n − 1/(n+1)

Each fraction of the form “one over consecutive product” splits into a difference of two unit fractions.

Don’t take it on faith — compute a few:

  • 1/(1·2) = 1/2 — and 1/1 − 1/2 = 1/2 ✓
  • 1/(2·3) = 1/6 — and 1/2 − 1/3 = 1/6 ✓
  • 1/(3·4) = 1/12 — and 1/3 − 1/4 = 1/12 ✓

So a sum like 1/(1·2) + 1/(2·3) + 1/(3·4) + … + 1/(99·100) rewrites as:

(1/1 − 1/2) + (1/2 − 1/3) + (1/3 − 1/4) + … + (1/99 − 1/100).

Now look closely: every term in the middle cancels. The +1/2 cancels the −1/2, the +1/3 cancels the −1/3, and so on, all the way down. The only survivors are the very first piece (1/1 = 1) and the very last piece (−1/100).

Sum = 1 − 1/100 = 99/100.

Adding 99 fractions becomes a single subtraction. Whenever you see a sum that looks like “one over (consecutive product),” split each piece and let the cancellation do the work.

THE MOVE — LET IT TELESCOPE

Rewrite every factor (or term) so each piece matches its neighbor, then cancel down the line. In a product, only first-top over last-bottom survives. In a sum of split pieces, only the first and last survive.

🎯 Try it
Find (1 + 1/1)(1 + 1/2)(1 + 1/3). (Rewrite each factor, then cancel.) Type the number.
Walkthrough: Each 1 + 1/k = (k+1)/k, so it’s (2/1)(3/2)(4/3). The 2 cancels the 2, the 3 cancels the 3 — leaving first-bottom 1 under last-top 4: 4/1 = 4.
THE TRICK

Before multiplying any chain of fractions, write each as something/something and look for matches across. If the chain has structure like (k)/(k+1), it telescopes — only the very first top and very last bottom survive.

WATCH OUT
Bogus solution

What is 1/2 + 1/2? Add the tops, add the bottoms: (1+1)/(2+2) = 2/4 = 1/2. So two halves make a half.

Why it breaks: Two halves of a pizza is a whole pizza, not half — the answer must be 1. Adding bottoms changes the size of the pieces mid-problem, which you’re not allowed to do when adding.

The fix: To add, the bottoms must already match; then add only the tops: 1/2 + 1/2 = (1+1)/2 = 2/2 = 1. (You add tops-and-bottoms when you multiply — never when you add.)

Trap framing inspired by AoPS Prealgebra.

WORKED EXAMPLE
PROBLEM · 2018 #2

What is the value of the product

(1 + 11) · (1 + 12) · (1 + 13) · (1 + 14) · (1 + 15) · (1 + 16) ?
A) 76 B) 43 C) 72 D) 7 E) 8

The product is (1 + 1/1)(1 + 1/2)(1 + 1/3)(1 + 1/4)(1 + 1/5)(1 + 1/6).

Turn each factor into a single fraction (1 + 1/k = (k+1)/k):

(2/1)(3/2)(4/3)(5/4)(6/5)(7/6).

Now the dominoes fall: each top cancels the next bottom — 2 kills 2, 3 kills 3, all the way up. Only the first bottom (1) and the last top (7) remain:

= 7/1 = 7 (answer D).

The temptation is to multiply six fractions step by step and pray you don’t slip. Resist it. Rewrite each 1 + 1/k as (k+1)/k and the staircase cancels itself — the answer is last-top over first-bottom. Whether it’s 6 factors or 600, the move is identical.

Answer: D — 7.
RULE OF THUMB

In a product of fractions, cancel across before you multiply. If the chain has the (k)/(k+1) shape, only first-top and last-bottom remain.

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1992 · #25 One half of the water is poured out of a full container. Then one third of the remainder is poured out. Continue the process: one fourth...

One half of the water is poured out of a full container. Then one third of the remainder is poured out. Continue the process: one fourth of the remainder for the third pouring, one fifth of the remainder for the fourth pouring, and so on. After how many pourings does exactly one tenth of the original water remain?

Show answer
Answer: D — 9.
Show hints
Hint 1 of 3
Don't track how much you POUR OUT — track what STAYS. Pouring out 1/2 leaves 1/2; pouring out 1/3 of what's left leaves 2/3 of it; pouring out 1/4 leaves 3/4. What do you multiply to chain these?
Still stuck? Show hint 2 →
Hint 2 of 3
The amount remaining is a product of survival fractions: 1/2 × 2/3 × 3/4 × …. Before multiplying it all out, look for a pattern in how the tops and bottoms line up.
Still stuck? Show hint 3 →
Hint 3 of 3
Notice each numerator matches the previous denominator — so almost everything cancels in a chain (this ‘telescoping’ collapse leaves just the first top and last bottom).
Show solution
Approach: track what survives; the fractions telescope to a tiny result
  1. Each pouring removes a slice and leaves the rest: keep 1/2, then 2/3 of that, then 3/4, then 4/5, and so on. After k pourings the fraction left is 1/2 × 2/3 × 3/4 × … × k/(k+1).
  2. Watch the cancellation: the 2 on top of 2/3 cancels the 2 on the bottom of 1/2, the 3 on top of 3/4 cancels the 3 below it, and so on down the chain. Everything cancels except the very first top (1) and the very last bottom (k+1), leaving 1/(k+1).
  3. We want exactly 1/10 left, so 1/(k+1) = 1/10 means k+1 = 10, giving k = 9 pourings.
  4. Why this transfers: when a product's numerators reuse the previous denominators, it ‘telescopes’ — the middle all cancels and only the outermost top and bottom remain. Spotting this saves you from multiplying nine fractions by hand.
  5. Sanity check: after 1 pouring you have 1/2; the formula gives 1/(1+1) = 1/2. Good — and 1/10 is reached when the denominator hits 10, i.e. the 9th pouring.
2019 · #25 Elisabeth has 60 pralines. On Monday she eats 110 of them. Of the ones left she eats 19 on Tuesday, then on Wednesday 18 of those left...

Elisabeth has 60 pralines. On Monday she eats 110 of them. Of the ones left she eats 19 on Tuesday, then on Wednesday 18 of those left from the day before, on Thursday 17 of those left, and so on, until she eats one half of the pralines left over from the day before. How many pralines has she still got afterwards?

Show answer
Answer: E — 6
Show hints
Hint 1 of 2
Each day she removes a unit fraction of what is currently left.
Still stuck? Show hint 2 →
Hint 2 of 2
Track the running total day by day until the 'eat one half' step.
Show solution
Approach: apply each day's fraction in turn
  1. Start 60. Monday eat 1/10 → 54 left; Tuesday 1/9 → 48; Wednesday 1/8 → 42; Thursday 1/7 → 36.
  2. Continuing 1/6, 1/5, 1/4, 1/3, then 1/2 of what remains, the count drops to 30, 24, 18, 12, then 6.
  3. She has 6 pralines left.
★ MINI-QUIZ

Fraction arithmetic

Three fraction problems: a comparison, a fraction-operation, and a telescoping product. Resist long-multiplying.

1992 · #2 Which of the following is not equal to 54?

Which of the following is not equal to 54?

Show answer
Answer: D — 1 1/5.
Show hints
Hint 1 of 3
5/4 is one whole plus a quarter. Which choices are secretly just a quarter dressed up — and which one hides a different-sized piece?
Still stuck? Show hint 2 →
Hint 2 of 3
When choices look different but might be equal, convert them all to ONE common form (a decimal, or a fraction over the same bottom number) so they line up for comparison.
Still stuck? Show hint 3 →
Hint 3 of 3
A bigger denominator means a smaller slice: 1/5 is less than 1/4, so don't be fooled into reading 1 1/5 as 1.25.
Show solution
Approach: rewrite every choice in one common form so the odd one out stands out
  1. 5/4 = 1 + 1/4 = 1.25. Now test each: 10/8 = 1.25 (just doubled top and bottom); 1 1/4 = 1.25; 1 3/12 = 1 + 1/4 = 1.25 (3/12 reduces to 1/4); 1 10/40 = 1 + 1/4 = 1.25 (10/40 reduces to 1/4).
  2. That leaves 1 1/5. Since 1/5 = 0.2, this is 1.2, NOT 1.25 — so 1 1/5 is the one not equal.
  3. Trap to remember: a fifth feels "close" to a quarter, but cutting something into 5 pieces gives smaller pieces than cutting into 4. The trickster choice swaps the denominator from 4 to 5 hoping you won't notice the slice shrank.
1995 · #3 Which of the following operations has the same effect on a number as multiplying by 34 and then dividing by 35?

Which of the following operations has the same effect on a number as multiplying by 34 and then dividing by 35?

Show answer
Answer: E — multiplying by 5/4.
Show hints
Hint 1 of 2
Dividing by a fraction is the same as multiplying by its flip. So 'divide by 3/5' can become 'multiply by 5/3' — now everything is multiplication.
Still stuck? Show hint 2 →
Hint 2 of 2
Two multiplications in a row are really just one. Combine them into a single multiplier and see which answer it matches.
Show solution
Approach: turn dividing into multiplying by the flip, then merge
  1. The insight: 'divide by 3/5' is the same as 'multiply by 5/3' (flip the divisor). Now both steps are multiplications, which combine cleanly.
  2. So the effect is × 34 × 53. The 3's cancel, leaving × 54 — i.e. multiplying by 5/4.
  3. Why this transfers: any string of ×'s and ÷'s by fractions collapses to one fraction — flip every divisor, then multiply across and cancel.
Another way — test with an easy number:
  1. Pick 12 (divisible by 4 and 3). Multiply by 3/4: 12 → 9. Divide by 3/5: 9 ÷ 3/5 = 9 × 5/3 = 15.
  2. So 12 became 15 — that's × 5/4 (since 12 × 5/4 = 15). Matches multiplying by 5/4.
1992 · #25 One half of the water is poured out of a full container. Then one third of the remainder is poured out. Continue the process: one fourth...

One half of the water is poured out of a full container. Then one third of the remainder is poured out. Continue the process: one fourth of the remainder for the third pouring, one fifth of the remainder for the fourth pouring, and so on. After how many pourings does exactly one tenth of the original water remain?

Show answer
Answer: D — 9.
Show hints
Hint 1 of 3
Don't track how much you POUR OUT — track what STAYS. Pouring out 1/2 leaves 1/2; pouring out 1/3 of what's left leaves 2/3 of it; pouring out 1/4 leaves 3/4. What do you multiply to chain these?
Still stuck? Show hint 2 →
Hint 2 of 3
The amount remaining is a product of survival fractions: 1/2 × 2/3 × 3/4 × …. Before multiplying it all out, look for a pattern in how the tops and bottoms line up.
Still stuck? Show hint 3 →
Hint 3 of 3
Notice each numerator matches the previous denominator — so almost everything cancels in a chain (this ‘telescoping’ collapse leaves just the first top and last bottom).
Show solution
Approach: track what survives; the fractions telescope to a tiny result
  1. Each pouring removes a slice and leaves the rest: keep 1/2, then 2/3 of that, then 3/4, then 4/5, and so on. After k pourings the fraction left is 1/2 × 2/3 × 3/4 × … × k/(k+1).
  2. Watch the cancellation: the 2 on top of 2/3 cancels the 2 on the bottom of 1/2, the 3 on top of 3/4 cancels the 3 below it, and so on down the chain. Everything cancels except the very first top (1) and the very last bottom (k+1), leaving 1/(k+1).
  3. We want exactly 1/10 left, so 1/(k+1) = 1/10 means k+1 = 10, giving k = 9 pourings.
  4. Why this transfers: when a product's numerators reuse the previous denominators, it ‘telescopes’ — the middle all cancels and only the outermost top and bottom remain. Spotting this saves you from multiplying nine fractions by hand.
  5. Sanity check: after 1 pouring you have 1/2; the formula gives 1/(1+1) = 1/2. Good — and 1/10 is reached when the denominator hits 10, i.e. the 9th pouring.
CHAPTER 8

Fraction of an unknown — keep-fractions

THEORY

Half the people in a room left. One third of those still there got up to dance. Twelve weren’t dancing. How many were in the room to start?

The number you want is hiding behind a chain of fractions-of-fractions. The slow road is to guess a starting number and grind forward. The fast road: notice you never need the in-between counts at all — you can multiply the fractions straight through.

Keep-fractions: track the part you wantwhole room = N½ stayed½ left (gone)⅔ of stayers: NOT dancing⅓ dancing 

The shaded strip is the not-dancers: ½ of the room, then ⅔ of that. Multiply the two keep-fractions and you have them as one slice of the whole: (½)(⅔) = ⅓ of N. Set that equal to 12 and N pops out: (⅓)N = 12 → N = 36.

Two clean routes, same answer:

  • Forward (keep-fractions): at each step keep the fraction of the subgroup you care about, multiply them, then divide the final count by that product.
  • Backward: start from 12 and undo each step. Not-dancers are ⅔ of the stayers, so stayers = 12 ÷ ⅔ = 18. Stayers are half the room, so room = 18 × 2 = 36.

Pick whichever has fewer steps for the numbers in front of you.

THE MOVE — KEEP, DON’T DROP

For a ‘fraction of a fraction of…’ story, track the part you keep at each stage and multiply those fractions. You never need the in-between counts — the chain collapses to one multiplication.

🎯 Try it
A jar has some marbles. You give away ½, then ⅓ of what’s left. 10 marbles remain. How many did the jar start with?
Walkthrough: Keep ½, then keep ⅔ of that: (½)(⅔) = ⅓ of the start remains. So (⅓)N = 10 → N = 30. (Check forward: 30 → give ½ leaves 15 → give ⅓ of 15 = 5 leaves 10. ✓)
THE TRICK

‘Sells 25%’ means he keeps 75%. Track the keep-fraction, not the sell-fraction, and the stages chain by multiplying: × 3/4 each time.

WORKED EXAMPLE
PROBLEM · 1989 #21

Jack had a bag of 128 apples. He sold 25% of them to Jill. Next he sold 25% of those remaining to June. Of those apples still in his bag, he gave the shiniest one to his teacher. How many apples did Jack have then?

A) 7 B) 63 C) 65 D) 71 E) 111

Jack starts with 128 apples. He sells 25% to Jill, then 25% of what’s left to June, then gives away 1.

Each ‘sell 25%’ means keep 75%, so multiply by 3/4 each time — and 128 is friendly to quarters:

128 × 3/4 = 96, then 96 × 3/4 = 72.

Then he gives the shiniest one to his teacher: 72 − 1 = 71 (answer D).

The trap is computing how many he sold (32, then 24…) and subtracting twice — more steps, more slips. Track what survives instead. Keeping 75% twice is × 3/4 × 3/4, and because 128 is a power-of-two multiple of 4, every step lands on a whole number.

Answer: D — 71.
RULE OF THUMB

Multiply keep-fractions to track a subgroup through several stages, then use the final count to solve for the start. Track what survives, not what leaves.

MORE LIKE THIS
2012 · #4 Peter's family ordered a 12-slice pizza for dinner. Peter ate one slice and shared another slice equally with his brother Paul. What...

Peter's family ordered a 12-slice pizza for dinner. Peter ate one slice and shared another slice equally with his brother Paul. What fraction of the pizza did Peter eat?

Show answer
Answer: C — 1/8.
Show hints
Hint 1 of 2
The whole pizza is already cut into 12 equal slices — that's your natural unit. Count Peter's share in slices first, before turning it into a fraction of the pizza.
Still stuck? Show hint 2 →
Hint 2 of 2
"Shared equally" means he got half a slice, not a whole one. So count in halves: how many half-slices did he eat?
Show solution
Approach: count the share in slices, then over 12
  1. Peter ate 1 whole slice plus half of another — that's 1½ slices out of the 12.
  2. A clean way to avoid the ½: count in half-slices. Peter ate 3 half-slices, and the pizza holds 24 half-slices, so his share is 3/24 = 1/8.
  3. Sanity check: one slice alone is 1/12, and he ate a bit more than one slice, so the answer should be a little bigger than 1/12 — 1/8 is.
2004 · #16 Two 600 mL pitchers contain orange juice. One pitcher is 1/3 full and the other pitcher is 2/5 full. Water is added to fill each pitcher...

Two 600 mL pitchers contain orange juice. One pitcher is 1/3 full and the other pitcher is 2/5 full. Water is added to fill each pitcher completely, then both pitchers are poured into one large container. What fraction of the mixture in the large container is orange juice?

Show answer
Answer: C — 11/30.
Show hints
Hint 1 of 2
The water is a red herring — adding water tops each pitcher to 600 mL but adds zero juice. So just track two numbers: how much juice total, and how much liquid total. Fraction = juice ÷ everything.
Still stuck? Show hint 2 →
Hint 2 of 2
The principle is track the part that matters, ignore the filler: the answer is (amount of OJ) / (total volume). Don't average the fractions 1/3 and 2/5 — that's the trap, since both pitchers end up the same final size only by coincidence of being equal.
Show solution
Approach: total juice over total volume
  1. Juice in: pitcher 1 has 600 × 1/3 = 200 mL, pitcher 2 has 600 × 2/5 = 240 mL. Total juice = 440 mL.
  2. Total liquid: both pitchers are filled, so 600 + 600 = 1200 mL.
  3. Fraction juice = 440 / 1200 = 11/30.
  4. Quick check: the two juice fractions 1/3 (≈ 0.33) and 2/5 (= 0.40) should blend to something between them, and 11/30 ≈ 0.367 sits right in the middle — here a plain average works only because the pitchers are equal-sized.
Another way — average the concentrations (equal pitchers only):
  1. Because both pitchers hold the same 600 mL, the mixture's juice fraction is the plain average of the two: (1/3 + 2/5) / 2.
  2. 1/3 + 2/5 = 5/15 + 6/15 = 11/15; halve it: 11/30.
  3. Caution: this shortcut only works when the containers are equal in size — otherwise you must weight by volume.
2019 · #25 Elisabeth has 60 pralines. On Monday she eats 110 of them. Of the ones left she eats 19 on Tuesday, then on Wednesday 18 of those left...

Elisabeth has 60 pralines. On Monday she eats 110 of them. Of the ones left she eats 19 on Tuesday, then on Wednesday 18 of those left from the day before, on Thursday 17 of those left, and so on, until she eats one half of the pralines left over from the day before. How many pralines has she still got afterwards?

Show answer
Answer: E — 6
Show hints
Hint 1 of 2
Each day she removes a unit fraction of what is currently left.
Still stuck? Show hint 2 →
Hint 2 of 2
Track the running total day by day until the 'eat one half' step.
Show solution
Approach: apply each day's fraction in turn
  1. Start 60. Monday eat 1/10 → 54 left; Tuesday 1/9 → 48; Wednesday 1/8 → 42; Thursday 1/7 → 36.
  2. Continuing 1/6, 1/5, 1/4, 1/3, then 1/2 of what remains, the count drops to 30, 24, 18, 12, then 6.
  3. She has 6 pralines left.
2020 · #26 Lady Josephine bought a pack of beans. The beans come mixed with impurities such as pebbles and sand, and the label says these...

Lady Josephine bought a pack of beans. The beans come mixed with impurities such as pebbles and sand, and the label says these impurities make up 8% of the contents of the package. Lady Josephine removes part of these impurities, reducing them to 4% of the contents of the package. What fraction of the total amount of impurities was removed from the package?

Show answer
Answer: B2548
Show hints
Hint 1 of 2
Start with a 100 g pack: 8 g impurities, 92 g good beans; removing impurities does not change the good beans.
Still stuck? Show hint 2 →
Hint 2 of 2
After removal the impurities are 4% of the new, smaller pack — solve for how much impurity was taken out.
Show solution
Approach: keep the good beans fixed
  1. Take a 100 g pack: 8 g impurities and 92 g good beans. Removing x g of impurity leaves a pack of (100 − x) g.
  2. Now (8 − x) is 4% of (100 − x): 8 − x = 0.04(100 − x), giving 4 = 0.96x, so x = 25/6 g.
  3. The fraction of the original impurities removed is (25/6) ÷ 8 = 25/48.
  4. The answer is 25/48, choice B.
CHAPTER 9

Weighted averages — when group sizes differ

THEORY

Class A (20 kids) averages 80. Class B (30 kids) averages 70. Put them together — what’s the average now? Almost everyone says 75, splitting the difference. Wrong. The classes aren’t the same size, so they don’t pull equally.

Think of a see-saw with 80 on one end and 70 on the other. The balance point sits over the middle only if both sides have equal weight. Class B has more kids, so it’s the heavier end — the average slides toward 70.

Bigger group pulls the average its waybalance = 74avg 8020 kidsavg 7030 kidsheavier (more kids) → pivot slides toward it

Forget the see-saw arithmetic for a second — the real rule is simpler than any formula:

WEIGHTED AVERAGE

Combined average = (total of everything) ÷ (total count). For two groups: (nₐ·avgₐ + nₛ·avgₛ) / (nₐ + nₛ).

Here: (20·80 + 30·70) / (20+30) = (1600 + 2100)/50 = 3700/50 = 74. As predicted — below 75, leaning toward the bigger class’s 70.

The combined average always lands between the two group averages, nearer the larger group. Sanity checks: it can’t be under 70 or over 80, and it should sit closer to whichever group is bigger.

THE MOVE — TOTAL OVER COUNT

Never average the averages. Add up every value (group size × group average), divide by the total count. The result leans toward the bigger group — use that to sanity-check your answer.

🎯 Try it
A 10-question quiz averages 90. A 40-question quiz averages 75. Combined, what’s the average over all 50 questions? (Type the number.)
Walkthrough: Total points: 10×90 + 40×75 = 900 + 3000 = 3900. Over 50 questions: 3900/50 = 78. It sits near 75, because the 40-question quiz is the heavier group — not the halfway 82.5.
THE TRICK

Don’t average the percents — rebuild the totals. Turn each percent into a raw count (score = percent × how many), add up all the points, divide by all the problems.

WORKED EXAMPLE
PROBLEM · 2010 #9

Ryan got 80% of the problems correct on a 25-problem test, 90% on a 40-problem test, and 70% on a 10-problem test. What percent of all the problems did Ryan answer correctly?

A) 64 B) 75 C) 80 D) 84 E) 86

Ryan scores 80% on 25 problems, 90% on 40, and 70% on 10. His overall percent?

Averaging 80, 90, 70 gives 80 — but the tests are different sizes, so go back to raw points:

  • 80% of 25 = 20 correct
  • 90% of 40 = 36 correct
  • 70% of 10 = 7 correct

Total: 20 + 36 + 7 = 63 correct out of 25 + 40 + 10 = 75 problems. So 63/75 = 84% (answer D).

The trap is the plain average of 80, 90, 70 = 80. But the 40-problem test carries the most weight, and Ryan’s best score (90%) is on it — so the true number is pulled up above 80, to 84%. Counting actual points instead of averaging percents is what keeps the weights honest.

Answer: D — 84%.
RULE OF THUMB

Combined average = combined total ÷ combined count. The answer always lands between the two group averages, pulled toward the bigger group.

MORE LIKE THIS
2006 · #12 Antonette gets 70% on a 10-problem test, 80% on a 20-problem test and 90% on a 30-problem test. If the three tests are combined into one...

Antonette gets 70% on a 10-problem test, 80% on a 20-problem test and 90% on a 30-problem test. If the three tests are combined into one 60-problem test, which percent is closest to her overall score?

Show answer
Answer: D — 83%.
Show hints
Hint 1 of 2
You can NOT just average 70, 80, 90 — the tests have different sizes, so the bigger tests should count for more. Go back to actual problems right and wrong.
Still stuck? Show hint 2 →
Hint 2 of 2
A percentage is a fraction in disguise. Turn each percent into a count of correct problems, pool them, then form one big fraction: total right ÷ total problems. This is a weighted average.
Show solution
Approach: count actual correct problems, then one overall fraction
  1. Convert each percent to a count: 70% of 10 = 7, 80% of 20 = 16, 90% of 30 = 27.
  2. Pool them: 7 + 16 + 27 = 50 correct out of 60 total.
  3. 50 ÷ 60 ≈ 0.833 ⇒ closest to 83%.
  4. Why not 80%? The naive average of 70, 80, 90 is 80 — that's answer choice C, the trap. It would only be right if the tests were the same size. Because the 90% test is the biggest (30 problems), it pulls the real score above 80. Always weight by size.
2022 · #21 Steph scored 15 baskets out of 20 attempts in the first half of a game, and 10 baskets out of 10 attempts in the second half. Candace...

Steph scored 15 baskets out of 20 attempts in the first half of a game, and 10 baskets out of 10 attempts in the second half. Candace took 12 attempts in the first half and 18 attempts in the second. In each half, Steph scored a higher percentage of baskets than Candace. Surprisingly they ended with the same overall percentage of baskets scored. How many more baskets did Candace score in the second half than in the first?

Show answer
Answer: C — 9 more baskets.
Show hints
Hint 1 of 2
Both players took the same number of total attempts (30). If two people with equal attempts finish at the same overall percentage, what must be equal about their makes? That collapses the “surprising” clue into a hard number.
Still stuck? Show hint 2 →
Hint 2 of 2
Candace also made 25 baskets. Now her per-half percentages are each strictly below Steph's, which caps her first-half and second-half makes — and only one split of 25 fits both caps.
Show solution
Approach: equal attempts + equal overall % forces equal total makes; then squeeze the split
  1. Insight: turn the “surprising” tie into arithmetic. Both shot 30 total (Steph 20+10, Candace 12+18). Equal attempts and equal overall percentage means equal makes — Steph made 15 + 10 = 25, so Candace made 25 too.
  2. Let Candace's makes be f (of 12) and s (of 18), with f + s = 25. Beating-by-Steph in each half caps her: f/12 < 15/20 = ¾ forces f ≤ 8, and s/18 < 1 forces s ≤ 17.
  3. Those caps add to exactly 8 + 17 = 25, so the only split is f = 8, s = 17 — any less in one half can't be made up in the other.
  4. sf = 17 − 8 = 9.
  5. Why the caps pin it down: when two upper bounds sum to exactly the required total, each variable is pinned to its max — no slack to trade. (This is also the resolution of the classic “Simpson's paradox” setup: losing both halves yet tying overall.)
2013 · #8 Marie works out the average number of children per family in her village. Five families live in the village. Which of these values could...

Marie works out the average number of children per family in her village. Five families live in the village. Which of these values could she not get?

Show answer
Answer: C — 1.3
Show hints
Hint 1 of 2
The average is the total number of children divided by 5.
Still stuck? Show hint 2 →
Hint 2 of 2
So the average must be a whole number of fifths — a multiple of 0.2.
Show solution
Approach: average must be a multiple of 1/5
  1. With 5 families, the average equals (total children) ÷ 5.
  2. The total is a whole number, so the average must be a multiple of 0.2.
  3. 1.0, 1.2, 1.4, 2.0 are multiples of 0.2, but 1.3 is not.
  4. So she could not get 1.3.
CHAPTER 10

Percent OF vs percent INCREASE

THEORY

One of the most consistent mid-contest traps is mixing up “A is what percent OF B” with “A is what percent MORE THAN B.” Two different sentences, two different formulas, two different answers.

Pictures kill the confusion. Take A = 50 and B = 40 (so A is bigger):

A = 50,   B = 40Q1: “A is what PERCENT OF B?”Compare A directly to B as a fraction of B.B = 40A = 50⇒ A ÷ B = 50/40= 125%Q2: “A is what percent MORE THAN B?”Compare only the EXTRA (A − B) to B.B = 40 (baseline)+10only this counts⇒ 10 ÷ 40= 25%Both correct — they answer different questions. The trap is picking the wrong one.
Same A and B. 125% of and 25% more than are both correct — they answer different questions. The trap is picking the wrong one.

Phrase ↔ formula cheat-sheet

PhraseFormulaWith A=50, B=40
A is x% OF BA = (x/100) · B125% of 40 = 50 ✓
A is x% MORE than BA = (1 + x/100) · B25% more than 40 = 50 ✓
A is x% LESS than BA = (1 − x/100) · B(if A<B; e.g. 20% less than 50 = 40)
What percent IS A of B?= A/B × 10050/40 = 125%
What percent GREATER is A than B?= (A−B)/B × 10010/40 = 25%
The key word: “OF” means full ratio. “MORE/LESS” means the EXTRA over baseline.
🎯 Try it
A price rises from $40 to $50. What percent more than $40 is $50? (Type the number.)
Walkthrough: ‘More than’ uses only the extra: (50 − 40)/40 = 10/40 = 25%. (Watch the trap: $50 is 125% OF $40, but only 25% MORE than it. Same two prices, two different questions.)
THE TRICK

‘A is what percent of B?’ is A/B × 100. ‘A is what percent more than B?’ is (A − B)/B × 100. And ‘percent decrease’ compares the drop to the original, not the new number: (old − new)/old × 100. Always name which phrasing before you compute.

WATCH OUT
Bogus solution

A class has 30 girls and 20 boys. What percent of the class is girls? There are more girls than boys, so compare them: 30/20 = 150%. So 150% of the class is girls.

Why it breaks: A percent of the class can never top 100% — you can’t have more girls than there are people. The 150% answer divided by the wrong base (boys), not by the whole.

The fix: ‘Percent OF the class’ means out of everyone: the class is 30 + 20 = 50. So girls are 30/50 = 60%. The base after ‘of’ is the total, not the other group.

Trap framing inspired by AoPS Prealgebra.

WORKED EXAMPLE
PROBLEM · 2007 #6

The average cost of a long-distance call in the USA in 1985 was 41 cents per minute, and the average cost of a long-distance call in the USA in 2005 was 7 cents per minute. Find the approximate percent decrease in the cost per minute of a long-distance call.

A) 7 B) 17 C) 34 D) 41 E) 80

A call cost 41 cents/min in 1985 and 7 cents/min in 2005. Find the approximate percent decrease.

Decrease is the drop measured against the starting price:

Drop = 41 − 7 = 34 cents. Over the original 41: 34/41 ≈ 0.83 = about 83%, closest to 80% (answer E).

The trap is dividing by the wrong number. ‘Percent decrease’ always measures the change against where you started (41), never against where you ended (7). Dividing 34 by 7 would give a wild 486% — a red flag that you used the wrong base.

Answer: E — About 80%.
RULE OF THUMB

‘of’ = direct ratio A/B. ‘more/less than’ = the difference over the original. Two phrasings, two formulas, two answers.

MORE LIKE THIS
2003 · #3 A burger at Ricky C's weighs 120 grams, of which 30 grams are filler. What percent of the burger is not filler?

A burger at Ricky C's weighs 120 grams, of which 30 grams are filler. What percent of the burger is not filler?

Show answer
Answer: D — 75%.
Show hints
Hint 1 of 2
"Percent that is NOT filler" means the non-filler part compared to the whole burger — find that part first.
Still stuck? Show hint 2 →
Hint 2 of 2
Percent of a whole = part ÷ whole, written out of 100.
Show solution
Approach: part over whole
  1. The question asks for the non-filler part, so peel it off first: 120 − 30 = 90 grams are not filler.
  2. Now compare that part to the whole burger: 90/120. This simplifies to 3/4 = 75%.
  3. Shortcut check: the filler is 30/120 = 1/4 = 25%, and the rest must make 100%, so 100% − 25% = 75% — same answer, faster. Finding one part and subtracting from 100% often beats computing the other part directly.
Another way — filler percent, then subtract from 100%:
  1. Filler is 30 of 120 grams = 30/120 = 1/4 = 25%.
  2. Everything else is 100% − 25% = 75%.
2010 · #3 The graph shows the price of five gallons of gasoline during the first ten months of the year. By what percent is the highest price more...

The graph shows the price of five gallons of gasoline during the first ten months of the year. By what percent is the highest price more than the lowest price?

Figure for AMC 8 2010 Problem 3
Show answer
Answer: C — 70%.
Show hints
Hint 1 of 2
‘More than’ is the key phrase: you're comparing the gap to the starting amount, not to the bigger amount. The low price is the baseline (the 100%).
Still stuck? Show hint 2 →
Hint 2 of 2
Percent change always divides by where you started: (new − old) / old. The word after ‘than’ tells you the baseline.
Show solution
Approach: compare the gap to the baseline (the low)
  1. Read the tallest and shortest bars: highest = 17, lowest = 10. The gap is 17 − 10 = 7.
  2. ‘How much more than the low’ means measure that gap against the low: 7 / 10 = 0.7 = 70%.
  3. Watch out: a common trap is dividing by 17 (the high). Dividing by the wrong number is exactly why the wrong answers are on the list — always anchor to the amount named after ‘than.’
2026 · #4 Brynn's savings decreased by 20% in July, then increased by 50% of the new amount in August. Brynn's savings are now what percent of the...

Brynn's savings decreased by 20% in July, then increased by 50% of the new amount in August. Brynn's savings are now what percent of the original amount?

Show answer
Answer: E — 120%.
Show hints
Hint 1 of 2
Careful — the answer isn't simply −20 + 50 = +30%. The 50% rise acts on the already-shrunk amount, so the two changes don't just add.
Still stuck? Show hint 2 →
Hint 2 of 2
Turn each change into a multiplier (×0.8, then ×1.5) and multiply them — that's how percent changes compound, and you never need the starting amount.
Show solution
Approach: turn each percent change into a multiplier
  1. A percent change is really a multiplier: down 20% leaves 80%, so × 0.8; up 50% means × 1.5. And changes chain by multiplying, so you never need a starting amount.
  2. 0.8 × 1.5 = 1.2, which is 120% of the original.
  3. Watch the trap: the answer is not −20% + 50% = +30%. Percents stack by multiplying, not adding, because the +50% applies to the shrunken amount, not the original.
Another way — plug in a friendly number:
  1. Pretend Brynn started with $100. July: down 20% leaves $80. August: up 50% of $80 adds $40, giving $120.
  2. $120 out of the original $100 is 120%. Picking 100 makes the percent fall right out.
2024 · #23 Fresh mushrooms consist of 80% water. In dried mushrooms, however, the water is only 20% of the mass. By what percentage does the mass...

Fresh mushrooms consist of 80% water. In dried mushrooms, however, the water is only 20% of the mass. By what percentage does the mass of a mushroom decrease during drying?

Show answer
Answer: C — 75
Show hints
Hint 1 of 2
The dry solid part of the mushroom never changes when water leaves; only water mass drops.
Still stuck? Show hint 2 →
Hint 2 of 2
Track the solid mass: it is 20% before and 80% after, so set up the new total from the fixed solid.
Show solution
Approach: hold the solid mass fixed and find the new total
  1. Take 100 g fresh: 80% water means 20 g of solid.
  2. Dried, water is 20% so solid is 80% of the new mass: 20 = 0.8 × new, giving new = 25 g.
  3. Mass drops from 100 g to 25 g, a decrease of 75%.
⬢ FINAL TEST

Stretch test

Five harder FDP problems combining percent reasoning and fraction manipulation.

2019 · #22 A store increased the original price of a shirt by a certain percent and then decreased the new price by the same amount. Given that the...

A store increased the original price of a shirt by a certain percent and then decreased the new price by the same amount. Given that the resulting price was 84% of the original price, by what percent was the price increased and decreased?

Show answer
Answer: E — 40%.
Show hints
Hint 1 of 2
Up then down by the same percent does NOT return to the start — the decrease acts on a bigger price. Write it as multipliers: ×(1+p) then ×(1−p), and let difference-of-squares simplify the product.
Still stuck? Show hint 2 →
Hint 2 of 2
(1+p)(1−p) = 1 − p2. Set that equal to 0.84 and the percent pops right out.
Show solution
Approach: the two changes multiply to 1 − p²
  1. Raising by p then lowering by p multiplies the price by (1 + p)(1 − p) = 1 − p2 — a difference of squares, neatly collapsing the two steps into one.
  2. Set 1 − p2 = 0.84, so p2 = 0.16 and p = 0.4 = 40%.
  3. Why this transfers: a percent up and the same percent down always leaves 1 − p2 — strictly less than the original, since the drop applies to a larger amount. Recognizing (1+p)(1−p) as a difference of squares is the shortcut.
2024 · #23 Fresh mushrooms consist of 80% water. In dried mushrooms, however, the water is only 20% of the mass. By what percentage does the mass...

Fresh mushrooms consist of 80% water. In dried mushrooms, however, the water is only 20% of the mass. By what percentage does the mass of a mushroom decrease during drying?

Show answer
Answer: C — 75
Show hints
Hint 1 of 2
The dry solid part of the mushroom never changes when water leaves; only water mass drops.
Still stuck? Show hint 2 →
Hint 2 of 2
Track the solid mass: it is 20% before and 80% after, so set up the new total from the fixed solid.
Show solution
Approach: hold the solid mass fixed and find the new total
  1. Take 100 g fresh: 80% water means 20 g of solid.
  2. Dried, water is 20% so solid is 80% of the new mass: 20 = 0.8 × new, giving new = 25 g.
  3. Mass drops from 100 g to 25 g, a decrease of 75%.
2022 · #21 Steph scored 15 baskets out of 20 attempts in the first half of a game, and 10 baskets out of 10 attempts in the second half. Candace...

Steph scored 15 baskets out of 20 attempts in the first half of a game, and 10 baskets out of 10 attempts in the second half. Candace took 12 attempts in the first half and 18 attempts in the second. In each half, Steph scored a higher percentage of baskets than Candace. Surprisingly they ended with the same overall percentage of baskets scored. How many more baskets did Candace score in the second half than in the first?

Show answer
Answer: C — 9 more baskets.
Show hints
Hint 1 of 2
Both players took the same number of total attempts (30). If two people with equal attempts finish at the same overall percentage, what must be equal about their makes? That collapses the “surprising” clue into a hard number.
Still stuck? Show hint 2 →
Hint 2 of 2
Candace also made 25 baskets. Now her per-half percentages are each strictly below Steph's, which caps her first-half and second-half makes — and only one split of 25 fits both caps.
Show solution
Approach: equal attempts + equal overall % forces equal total makes; then squeeze the split
  1. Insight: turn the “surprising” tie into arithmetic. Both shot 30 total (Steph 20+10, Candace 12+18). Equal attempts and equal overall percentage means equal makes — Steph made 15 + 10 = 25, so Candace made 25 too.
  2. Let Candace's makes be f (of 12) and s (of 18), with f + s = 25. Beating-by-Steph in each half caps her: f/12 < 15/20 = ¾ forces f ≤ 8, and s/18 < 1 forces s ≤ 17.
  3. Those caps add to exactly 8 + 17 = 25, so the only split is f = 8, s = 17 — any less in one half can't be made up in the other.
  4. sf = 17 − 8 = 9.
  5. Why the caps pin it down: when two upper bounds sum to exactly the required total, each variable is pinned to its max — no slack to trade. (This is also the resolution of the classic “Simpson's paradox” setup: losing both halves yet tying overall.)
2020 · #26 Lady Josephine bought a pack of beans. The beans come mixed with impurities such as pebbles and sand, and the label says these...

Lady Josephine bought a pack of beans. The beans come mixed with impurities such as pebbles and sand, and the label says these impurities make up 8% of the contents of the package. Lady Josephine removes part of these impurities, reducing them to 4% of the contents of the package. What fraction of the total amount of impurities was removed from the package?

Show answer
Answer: B2548
Show hints
Hint 1 of 2
Start with a 100 g pack: 8 g impurities, 92 g good beans; removing impurities does not change the good beans.
Still stuck? Show hint 2 →
Hint 2 of 2
After removal the impurities are 4% of the new, smaller pack — solve for how much impurity was taken out.
Show solution
Approach: keep the good beans fixed
  1. Take a 100 g pack: 8 g impurities and 92 g good beans. Removing x g of impurity leaves a pack of (100 − x) g.
  2. Now (8 − x) is 4% of (100 − x): 8 − x = 0.04(100 − x), giving 4 = 0.96x, so x = 25/6 g.
  3. The fraction of the original impurities removed is (25/6) ÷ 8 = 25/48.
  4. The answer is 25/48, choice B.
1994 · #20 Let W, X, Y, and Z be four different digits selected from the set {1, 2, 3, 4, 5, 6, 7, 8, 9}.If the sum WX + YZ is to be as small as...

Let W, X, Y, and Z be four different digits selected from the set {1, 2, 3, 4, 5, 6, 7, 8, 9}.

If the sum WX + YZ is to be as small as possible, then WX + YZ must equal

Show answer
Answer: D — 25/72.
Show hints
Hint 1 of 2
A fraction shrinks when its top is small and its bottom is big. With four digits to place, send your two SMALLEST digits (1, 2) up top and your two LARGEST (8, 9) to the bottoms.
Still stuck? Show hint 2 →
Hint 2 of 2
That's not the whole answer — you still choose how to pair them. There are only two pairings of {1,2} over {8,9}, so test both. Watch out: the 'obvious' choice isn't the winner.
Show solution
Approach: smallest tops over largest bottoms, paired well
  1. Smallest tops, largest bottoms ⇒ numerators 1 and 2, denominators 8 and 9.
  2. Two ways to pair them, both over a common 72: (a) 1/9 + 2/8 = 8/72 + 18/72 = 26/72; (b) 1/8 + 2/9 = 9/72 + 16/72 = 25/72. Option (b) is smaller.
  3. So the minimum sum is 25/72.
  4. Why the better pairing puts the bigger numerator over the bigger denominator: the '2' does the most damage, so park it over the biggest bottom (9) to shrink its effect. Lesson — for these extremes, 'pick the right digits' is only half the job; how you MATCH them up is the tiebreaker, so always check the few pairings.
🚀 STRETCH

Stretch practice — beyond AMC 8

5 bonus problems on Fractions, Decimals & Percents. These are typed-answer (no multiple choice) and tilt harder — closer to early AMC 10. Try the ones that look fun.

Stretch · #1 On a real national test, more than half of junior-high students missed this question: What is 75% of 12? That is surprising, because the...
On a real national test, more than half of junior-high students missed this question: What is 75% of 12? That is surprising, because the numbers are so friendly! Show how to see the answer with a picture instead of just punching buttons. (Then try the deliberately unfriendly version: what is 74% of 13?)
75% of 12 = 99 of 12 shaded = 3/4 = 75%
Show answer
Answer: 9 (and 74% of 13 is about 9.6)
Show hints
Hint 1 of 4
The word 'percent' just means 'out of 100.' Is there a simple fraction that equals 75%?
Still stuck? Show hint 2 →
Hint 2 of 4
Draw 12 little squares. If you split them into 4 equal groups, how many squares are in each group?
Still stuck? Show hint 3 →
Hint 3 of 4
75% is the same as 3 out of every 4, which is the fraction \(\tfrac34\). Take \(\tfrac14\) of 12 first, then take 3 of those groups.
Show solution
Approach: See the percent as a friendly fraction and picture it
  1. The trick is to see 75% as the friendly fraction \(\tfrac34\), not to reach for a percent rule.
  2. Draw 12 squares in a 3-by-4 array and split them into 4 equal columns. Each column has 3 squares, so each column is \(\tfrac14\) of the whole.
  3. \(\tfrac14\) of 12 = 3 squares (one column), so \(\tfrac34\) of 12 = three columns = 3 + 3 + 3 = 9.
  4. So 75% of 12 = \(\tfrac34 \times 12 = 9\).
  5. The unfriendly twin 74% of 13 looks almost the same on paper, but 74% is not a clean fraction and 13 won't split into equal small groups, so there is no neat picture — you would just estimate \(0.74 \times 13 \approx 9.6\). The real lesson: grab the easy picture when the numbers are friendly.
Stretch · #2 Reading a fraction as a COUNT of equal pieces, \(\frac{2}{3}\) means '2 thirds.' Using that idea (the bottom is the unit, the top is how...
Reading a fraction as a COUNT of equal pieces, \(\frac{2}{3}\) means '2 thirds.' Using that idea (the bottom is the unit, the top is how many), what is \(\frac{2}{3}+\frac{5}{3}\)? Give your answer as a fraction.
Show answer
Answer: 7/3
Show hints
Hint 1 of 4
Think of '2 thirds' and '5 thirds' like '2 meters' and '5 meters.' When the unit (the bottom number) is the same, you just add how many you have.
Still stuck? Show hint 2 →
Hint 2 of 4
So add the tops and keep the bottom: \(2 + 5\) thirds.
Still stuck? Show hint 3 →
Hint 3 of 4
The fake rule 'add tops, add bottoms' would give \(\frac{1}{2}+\frac{1}{2}=\frac{2}{4}=\frac{1}{2}\), but two halves make a WHOLE — so that rule is wrong.
Show solution
Approach: Read the denominator as a fixed unit; add only the counts
  1. Why you never add the bottoms: the fake rule turns \(\frac{1}{2}+\frac{1}{2}\) into \(\frac{2}{4}=\frac{1}{2}\), but two halves make a whole \(= 1\). So 'add the bottoms' is false.
  2. Read the bottom as the NAME of the piece (the unit) and the top as HOW MANY. So \(\frac{2}{3}\) is '2 thirds' and \(\frac{5}{3}\) is '5 thirds.'
  3. With the same unit, adding is like \(2\text{ m} + 5\text{ m} = 7\text{ m}\): \(2\text{ thirds} + 5\text{ thirds} = 7\text{ thirds}\).
  4. So \(\frac{2}{3}+\frac{5}{3}=\frac{7}{3}\): add the tops, keep the bottom. Adding bottoms would secretly change the slice size mid-count.
Stretch · #7 Compute \(\dfrac{3}{17} + \dfrac{6}{13}\). First warm up with the easier sum \(\dfrac{1}{2} + \dfrac{1}{3}\), thinking of adding...
Compute \(\dfrac{3}{17} + \dfrac{6}{13}\). First warm up with the easier sum \(\dfrac{1}{2} + \dfrac{1}{3}\), thinking of adding fractions as combining amounts measured in the same unit. Give your answer as a fraction in lowest terms.
Show answer
Answer: 141/221
Show hints
Hint 1 of 4
If the numbers feel scary, do a smaller version first: how do you add \(\frac{1}{2} + \frac{1}{3}\)?
Still stuck? Show hint 2 →
Hint 2 of 4
You can only add when both pieces are measured in the SAME size. For halves and thirds, what size works? (Sixths!) Rewrite both over \(6\).
Still stuck? Show hint 3 →
Hint 3 of 4
For seventeenths and thirteenths, a size that works for both is \(17 \times 13 = 221\). Rewrite each fraction with denominator \(221\).
Show solution
Approach: Solve a simpler analogous problem, then use a common unit (denominator)
  1. Adding fractions just means combining 'so many of one size piece.' Warm-up: for \(\frac{1}{2} + \frac{1}{3}\) use sixths — \(\frac{1}{2} = \frac{3}{6}\) and \(\frac{1}{3} = \frac{2}{6}\), so the sum is \(\frac{5}{6}\).
  2. Same idea, bigger numbers. A common size for seventeenths and thirteenths is \(17 \times 13 = 221\). Then \(\frac{3}{17} = \frac{39}{221}\) and \(\frac{6}{13} = \frac{102}{221}\).
  3. Add the tops: \(\frac{39}{221} + \frac{102}{221} = \frac{141}{221}\).
  4. Since \(221 = 13 \times 17\) and \(141 = 3 \times 47\) share no common factor, \(\frac{141}{221}\) is already in lowest terms.
Stretch · #18 A store takes \(10\%\) off a price, and then takes another \(8\%\) off the new (already reduced) price. What single discount percentage...
A store takes \(10\%\) off a price, and then takes another \(8\%\) off the new (already reduced) price. What single discount percentage gives the same final price?
Show answer
Answer: 17.2 percent
Show hints
Hint 1 of 4
The starting price isn't given, so pick an easy one to work with — try \(100\) dollars. (The answer as a percent won't depend on the price.)
Still stuck? Show hint 2 →
Hint 2 of 4
Take \(10\%\) off \(100\) dollars first. What's the new price?
Still stuck? Show hint 3 →
Hint 3 of 4
Now take \(8\%\) off that new price — NOT off the original \(100\). Careful!
Show solution
Approach: Pick a convenient price (specification without loss of generality)
  1. Pick a convenient starting price of \(100\) dollars; the final percent off is the same no matter the price.
  2. After \(10\%\) off: \(100 - 10 = 90\). After \(8\%\) off the \(90\): \(8\%\) of \(90\) is \(7.20\), so \(90 - 7.20 = 82.80\).
  3. The price dropped from \(100\) to \(82.80\), a drop of \(17.20\) out of \(100\), which is \(17.2\%\).
  4. Note the two discounts of \(10\%\) and \(8\%\) do NOT add to \(18\%\): they give \(17.2\%\), because the second discount comes off a smaller amount.
Stretch · #23 The 'mediant' of two fractions adds the tops and adds the bottoms: \(\frac{a}{b} \oplus \frac{c}{d} = \frac{a+c}{b+d}\). (This is NOT...
The 'mediant' of two fractions adds the tops and adds the bottoms: \(\frac{a}{b} \oplus \frac{c}{d} = \frac{a+c}{b+d}\). (This is NOT how you add fractions, but the result always lands strictly between them.) What is the mediant of \(\frac{1}{3}\) and \(\frac{1}{2}\)? Give it as a fraction in lowest terms.
Show answer
Answer: 2/5
Show hints
Hint 1 of 4
Compute the mediant of \(\frac{1}{3}\) and \(\frac{1}{2}\) by adding tops and adding bottoms.
Still stuck? Show hint 2 →
Hint 2 of 4
Turn all three fractions into decimals (or a common denominator) and put them in order. Is the mediant in the middle?
Still stuck? Show hint 3 →
Hint 3 of 4
To see why it always works, compare \(\frac{a}{b}\) with \(\frac{a+c}{b+d}\) using cross-multiplication (the bigger fraction has the bigger cross-product).
Show solution
Approach: Compute the mediant, verify it lies between via cross-multiplication
  1. Add tops and bottoms: \(\frac{1 + 1}{3 + 2} = \frac{2}{5}\), already in lowest terms.
  2. Check the order as decimals: \(\frac{1}{3} \approx 0.333\), \(\frac{2}{5} = 0.4\), \(\frac{1}{2} = 0.5\). The mediant sits right between them.
  3. Why it always works: if \(\frac{a}{b} < \frac{c}{d}\) then \(ad < bc\). Comparing \(\frac{a}{b}\) with \(\frac{a+c}{b+d}\) by cross-multiplying gives \(a(b+d) < b(a+c)\), i.e. \(ab + ad < ab + bc\), i.e. \(ad < bc\) — exactly what we know.
  4. The same check shows the mediant is below \(\frac{c}{d}\), so the mediant of \(\frac{1}{3}\) and \(\frac{1}{2}\) is \(\frac{2}{5}\) and always lands strictly between.
APPENDIX

FDP quick-reference

Memorize these

CONVERSIONS TO MEMORIZE

  • 1/2 = 0.5 = 50%; 1/3 ≈ 0.333 = 33⅓%; 2/3 ≈ 0.667 = 66⅔%
  • 1/4 = 0.25 = 25%; 3/4 = 0.75 = 75%
  • 1/5 = 0.2 = 20%; 2/5 = 0.4 = 40%; 3/5 = 0.6 = 60%; 4/5 = 0.8 = 80%
  • 1/6 ≈ 0.167; 5/6 ≈ 0.833
  • 1/8 = 0.125 = 12.5%; 3/8 = 0.375; 5/8 = 0.625; 7/8 = 0.875
  • 1/9 ≈ 0.111; 1/11 ≈ 0.0909; 1/12 ≈ 0.0833
  • Scale to 100: if the bottom divides 100 (2,4,5,10,20,25,50), multiply top and bottom up to /100 — the top is then the percent (2/25 = 8/100 = 8% = 0.08). No long division.

FRACTION SKILLS

  • Mixed ↔ improper: improper → mixed = divide top by bottom (quotient = whole, remainder = new top, same bottom): 23/5 = 4⅗. Mixed → improper = (whole × bottom + top) over the bottom: 4⅗ = (4×5+3)/5 = 23/5.
  • Add/subtract mixed numbers: wholes with wholes, fractions with fractions; carry a whole when the fraction part tops 1, borrow a whole when it is too small. (Or flip both to improper and skip carrying.)
  • KCF for division: Keep, Change, Flip — keep the first, change ÷ to ×, flip the second. ÷(1/n) = ×n, so dividing by a number under 1 makes the result BIGGER.
  • Compare fractions: a/b vs c/d → cross-multiply, a×d vs c×b, bigger product wins (both bottoms positive). Compare to ½ by checking whether 2a > b.
  • Terminating vs repeating: simplify first; the decimal terminates exactly when the bottom's only primes are 2 and 5, else it repeats. A one-digit repeating block over 9, two digits over 99: 0.3̄ = 1/3, 0.2̄7̄ = 27/99.

TELESCOPING & PERCENT

  • Telescoping product: (1−1/2)(1−1/3)…(1−1/N) = 1/N.
  • Telescoping sum: 1/(n(n+1)) = 1/n − 1/(n+1).
  • Percent is a multiplier: up p% → ×(1+p/100); down p% → ×(1−p/100); p% OF → ×(p/100).
  • +25% then −20% returns to start (because 1.25 × 0.8 = 1).
  • +1/n undoes with −1/(n+1). +25% (=+1/4) undoes with −20% (=−1/5).
Common traps
  • Adding percents from successive applications. 50% off then 20% off ≠ 70% off (it's 60% off). Multiply the multipliers.
  • +25% then −25% returns to less than the start. +25% then −20% returns exactly (because ×1.25 × ×0.8 = 1).
  • Averaging two averages without weighting. Use total ÷ count, not (a+b)/2 when groups differ.
  • Confusing 'A is x% of B' with 'A is x% more than B'. The first is A = x%·B; the second is A = (1+x%)·B. 'Percent OF the whole' can never exceed 100% — divide by the total, not the other group.
  • Forgetting to KCF when dividing fractions. Dividing by a fraction is multiplying by the flipped fraction; the answer grows when you divide by something under 1.
  • Bigger bottom = bigger fraction. No — with the same top, more pieces means each is smaller: 2/7 < 2/5.
  • Subtracting mixed numbers without borrowing. 5¼ − 2¾ is not 3 (½). Borrow a whole (5¼ = 4 and 5/4) or flip both to improper first.
  • Mis-aligning a partly-repeating decimal. For 0.2̄8̄ = 0.2888…, line the repeating tails up before subtracting (10x − x), or the 8s won't cancel.
  • Adding tops and bottoms. 1/2 + 1/2 ≠ 2/4. Match bottoms first, add only the tops (that across-rule is for multiplying).
Warm-ups

Drill these:

  • What is 20% of 75? (15)
  • What is the result of $200 raised by 30%? ($260)
  • Price drops from $50 to $40, percent decrease? (20%)
  • Price rises from $40 to $50, percent increase? (25%)
  • Two consecutive 10% raises: net multiplier? (1.21, so 21% raise)
  • (1/2) ÷ (3/4) using KCF: (1/2)(4/3) = 4/6 = 2/3.
Want to climb higher? — telescoping, repeaters, and mixed-number speed
  • Two-apart split: 1 / (n · (n+2)) = ½[1/n − 1/(n+2)]. So 1/(1·3) + 1/(3·5) + 1/(5·7) + … telescopes too, now with a 1/2 out front.
  • Product telescoping with (1 + 1/k): (1 + 1/1)(1 + 1/2)(1 + 1/3) … (1 + 1/n) = (2/1)(3/2)(4/3) … ((n+1)/n) = n + 1. Each numerator kills the next denominator. The whole product collapses to n + 1.
  • The harmonic series. 1 + 1/2 + 1/3 + … does NOT telescope — it grows without bound (slowly). Don’t try.
  • Any repeating decimal → fraction. Let x equal the decimal, multiply by a power of 10 to slide one whole period, subtract: 0.3 → 10x−x = 3 → x = 1/3. For a partly-repeating decimal, slide so the loops line up before subtracting: 0.28 → 10x−x = 2.6 → x = 26/90 = 13/45.
  • Repeat-block length. For 1/d (in lowest terms, no factor of 2 or 5 in d), the repeating block has length at most d−1 — the remainders cycle: 1/7 = 0.142857, a block of 6.
  • Mixed-number arithmetic fast. For a single hard subtraction, flip both to improper over a common bottom (no borrowing). For a long sum, estimate: each mixed number is its whole part plus a bit under 1, so the total is a little above the sum of the whole parts — often enough to pick the smallest whole number above it.