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2026 AMC 8

Problem 11

Problem 11 · 2026 AMC 8 Medium
Geometry & Measurement arc-length
Figure for AMC 8 2026 Problem 11
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Answer: B — 6Ο€.
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Hint 1 of 2
The spiral isn't one weird curve — it's five separate quarter-circles, one per square. In a square of side s, the inscribed quarter-circle has radius s. What is a quarter of that circle's circumference?
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Hint 2 of 2
Each arc is ΒΌ × 2Ο€s = Ο€s/2 — the arc length is just proportional to the side. So factor out Ο€/2 and add the five sides.
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Approach: each square gives a quarter-circle; arc length scales with the side
  1. Break the spiral into its five pieces: in each square of side s, the inscribed quarter-circle has radius s, so its arc is one-fourth of the full circumference: ΒΌ × 2Ο€s = Ο€s/2.
  2. Every arc is just (Ο€/2) times its side, so factor that out and total the sides 1, 1, 2, 3, 5: total = (Ο€/2)(1 + 1 + 2 + 3 + 5) = (Ο€/2)(12) = 6Ο€.
  3. Why this transfers: when a curve is built from circular arcs, handle each arc as (its fraction of a turn) × (2Ο€ × its radius), then add — you never need to draw the whole curve, just account for each arc's radius and how much of a full turn it sweeps.
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