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2023 AMC 8

Problem 23

Problem 23 · 2023 AMC 8 Hard
Counting & Probability careful-counting
Figure for AMC 8 2023 Problem 23
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Answer: C — 1/64.
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Hint 1 of 2
A diamond is built from four tiles meeting at one point — and any 2×2 diamond must use the center cell. So the center tile is already ‘there’; the question is whether its three neighbors line up.
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Hint 2 of 2
Once the center tile shows a gray corner, the three tiles touching that corner each need one specific orientation out of 4 to complete the diamond. Three independent 1-in-4 events — multiply.
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Approach: three neighbor tiles must each orient correctly
  1. Picture how a diamond forms: four gray triangles meet at a single point, and that point is always a corner of the center cell. So the center tile is automatically part of any diamond — whatever gray corner it happens to show is the corner the diamond grows from.
  2. To complete that diamond, the three tiles touching that gray corner must each be turned the right way. Each tile has 4 equally likely orientations, exactly 1 of which works, so each contributes probability 14 — independently.
  3. Multiply: 14 × 14 × 14 = 164. Why this is faster: instead of counting all 49 tilings, condition on the piece that's always involved (the center) and only the constraints that matter survive.
Another way — count favorable tilings (MAA):
  1. Total tilings: each of the 9 cells takes 1 of 4 tiles, so 49 in all.
  2. Favorable: a diamond's center can sit at any of the 4 corners of the middle cell (4 choices). Once chosen, the 4 tiles forming it are forced, but the other 5 cells are free: 45. So favorable = 4 × 45 = 46.
  3. Probability = 46 / 49 = 1/43 = 1/64.
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