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2019 AMC 8

Problem 10

Problem 10 · 2019 AMC 8 Medium
Arithmetic & Operations careful-counting
Figure for AMC 8 2019 Problem 10
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Answer: B — Mean +1, median +1.
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Hint 1 of 2
You don't need to recompute either statistic from scratch — just track the change. Only one number moved, so what does adding to it do to the average, and where does it land in the sorted order?
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Hint 2 of 2
Mean: a bump of +5 spread over 5 days raises the average by 5÷5 = 1. Median: re-sort and watch whether the bumped value jumps past the old middle value.
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Approach: measure the shift in each statistic, don't recompute
  1. Only Wednesday changes, 16 → 21, so the total goes up by 5. Mean of 5 days rises by 5÷5 = 1 — no need to add the whole column.
  2. For the median, sort instead of recomputing. Originally 12, 16, 20, 24, 26, median 20. Raising 16 to 21 slides that value rightward past 20: new order 12, 20, 21, 24, 26, median 21. Median rises by 1.
  3. So both increase by 1.
  4. Why this transfers: changing one data value shifts the mean by (change ÷ count), but the median only moves if the changed value crosses the old middle — always re-sort to check, since the median can stay put even when the mean jumps.
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