🇺🇸 AMC 8 ⇄ switch contest
2007 AMC 8

Problem 23

Problem 23 · 2007 AMC 8 Hard
Geometry & Measurement subtract-from-whole

What is the area of the shaded pinwheel shown in the 5 × 5 grid?

Figure for AMC 8 2007 Problem 23
Show answer
Answer: B — 6.
Show hints
Hint 1 of 2
The shaded pinwheel has slanted, awkward edges — but the unshaded leftovers are tidy squares and triangles. Measure what's easy and subtract from the whole 5×5.
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Hint 2 of 2
Complementary area: when the region you want is jagged, find the area of its simple complement and subtract from the total.
Show solution
Approach: whole grid minus the easy unshaded pieces
  1. Total grid area = 52 = 25.
  2. The unshaded part is 4 corner unit squares (4 · 1 = 4) plus 4 congruent triangles, each with base 3 and height 5/2.
  3. Those triangles total 4 · (1/2)(3)(5/2) = 15. Unshaded = 4 + 15 = 19.
  4. Shaded pinwheel = 25 − 19 = 6.
  5. Reusable move: never wrestle a slanted shape directly — subtracting the clean complement from a bounding rectangle is almost always faster and less error-prone.
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