🇺🇸 AMC 8 ⇄ switch contest
1998 AJHSME

Problem 13

Problem 13 · 1998 AJHSME Hard
Geometry & Measurement area-ratiosymmetry
Figure for AJHSME 1998 Problem 13
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Answer: C — 1/8.
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Hint 1 of 2
Don't measure the tilted square directly — relate it to easy pieces of the BIG square. The lines from the top corners meet at the center, carving the square into four matching triangles.
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Hint 2 of 2
Focus on the bottom quarter-triangle. What fraction of THAT triangle does the shaded square fill? Then 'fraction of a quarter' gives the fraction of the whole.
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Approach: compare the shaded square to one quarter of the big square
  1. Lines run from the two top corners down to the center of the square, splitting it into four equal triangles (top, bottom, left, right) — each is one quarter of the whole.
  2. The shaded tilted square sits inside the bottom quarter-triangle and covers exactly half of it (the extra vertical line marks the split).
  3. So the shaded area = ½ of ¼ = 1/8 of the large square.
  4. Why this transfers: for a tilted shape inside a square 'drawn to scale,' chop the big square into equal slices you trust, then express the target as a fraction of one slice — far safer than guessing lengths off a diagonal.
Another way — coordinates (pin the corners):
  1. Put the big square on a grid with corners (0,0), (4,0), (4,4), (0,4) — area 16. The shaded square's corners land at the center (2,2), the base midpoint (2,0), and the two points (1,1) and (3,1) where the corner-lines cross.
  2. That tilted square has diagonals of length 2 (from (2,0) to (2,2)) and 2 (from (1,1) to (3,1)); a square's area is ½·(diagonal)·(diagonal) = ½·2·2 = 2.
  3. Ratio = 2/16 = 1/8, confirming the slice argument.
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