πŸ‡ΊπŸ‡Έ AMC 8 ⇄ switch contest
1997 AJHSME

Problem 10

Problem 10 · 1997 AJHSME Medium
Geometry & Measurement grid-counting
Figure for AJHSME 1997 Problem 10
Show answer
Answer: C — 7/12.
Show hints
Hint 1 of 2
The stripes are equal width, so impose a grid where one stripe = one cell wide. The figure spans 6 widths, so overlay a 6 Γ— 6 grid and the messy picture becomes pure counting.
Still stuck? Show hint 2 →
Hint 2 of 2
Turning a 'to scale' shaded-region picture into a unit grid converts area into countable squares β€” the standard move for these.
Show solution
Approach: overlay a unit grid and count cells
  1. Equal stripe widths let you tile the square with a 6 Γ— 6 grid (36 unit cells), so each black L-shaped stripe is a whole number of cells.
  2. Counting the three black L's from inside out gives 3, 7, and 11 cells β€” total 3 + 7 + 11 = 21 shaded.
  3. Shaded fraction = 21/36 = 7/12.
  4. Nice pattern: the black L's grow 3, 7, 11 β€” jumping by 4 each time, since each larger L wraps an extra cell along two arms. Spotting the +4 rhythm guards against a miscount.
  5. You'll see it again: 'drawn to scale, equal widths' is a hint to grid it; counting cells beats fighting with areas.
Mark: · log in to save