πŸ‡ΊπŸ‡Έ AMC 8 ⇄ switch contest
1989 AJHSME

Problem 23

Problem 23 · 1989 AJHSME Stretch
Geometry & Measurement surface-areaexposed-faces
Figure for AJHSME 1989 Problem 23
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Answer: C — 33.
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Hint 1 of 3
Painted area = number of EXPOSED unit faces (each 1 mΒ²). A face is unpainted only if it touches the ground or is pressed against a neighboring cube.
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Hint 2 of 3
Counting one cube at a time invites double-counting. Instead sweep the whole sculpture by viewing direction β€” top, then each side β€” and tally the faces you can actually see from each.
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Hint 3 of 3
The bottom faces sit on the ground (never painted), so the work is: all top-visible faces plus the exposed faces on the front, back, and two sides.
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Approach: tally exposed faces by viewing direction
  1. Only faces touching nothing get paint β€” faces on the ground or glued to a neighbor are skipped. So organize the count by direction instead of cube-by-cube, which avoids missing or repeating faces.
  2. Looking straight down, 10 cube-tops are uncovered β†’ 10. The front shows 6 exposed faces and the back another 6. The two side walls together expose 11 more.
  3. Total painted = 10 + 6 + 6 + 11 = 33 mΒ².
  4. Why this transfers: for any blocky solid, painted surface = total faces (cubes Γ— 6) minus the hidden ones (on the ground or shared between touching cubes). Counting by direction is just an organized way to do exactly that without losing track.
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