πŸ‡ΊπŸ‡Έ AMC 8 ⇄ switch contest
1989 AJHSME

Problem 11

Problem 11 · 1989 AJHSME Hard
Geometry & Measurement reflection-symmetry
Figure for AJHSME 1989 Problem 11
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Answer: B — B.
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Hint 1 of 3
A mirror on a vertical line only swaps left and right β€” top stays top, bottom stays bottom. So track each feature's left/right side and leave its height alone.
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Hint 2 of 3
Two anchors pin down the mirror image: where the little corner square lands, and which way the slanted arms lean. Check both before choosing.
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Hint 3 of 3
The corner square sits at the TOP of the original, so it must stay at the top β€” that instantly throws out any choice with the square at the bottom, narrowing the field fast.
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Approach: swap left↔right, keep top/bottom, then match two anchors
  1. Reflection across the vertical dashed line is a left-right flip only: every feature keeps its height but trades sides. So the corner square stays at the top and moves to the opposite side, and the slanted arms reverse their lean.
  2. Use the corner square as the first filter β€” it's at the top in the original, so any choice with it at the bottom is out. Then check the arm lean against the mirror. Only B matches both anchors: square at the same top level on the flipped side, with the arms leaning the mirrored way.
  3. Why this transfers: to test a mirror image, don't eyeball the whole picture β€” pick one or two distinctive features (a corner mark, a lean direction) and verify each obeys the flip. Symmetry problems crack quickly once you reduce them to a couple of checkable anchors.
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