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1985 AJHSME

Problem 11

Problem 11 · 1985 AJHSME Hard
Geometry & Measurement cube-netopposite-faces
Figure for AJHSME 1985 Problem 11
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Answer: E — Y.
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Hint 1 of 3
On a cube, opposite faces never share an edge. X touches V (above it) and Z (below it), so neither V nor Z can be the answer β€” knock those out first.
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Hint 2 of 3
Handy shortcut for nets: in any straight strip of THREE squares in a line, the two end squares fold to opposite faces. The vertical strip V–X–Z makes V and Z opposite β€” so X must pair with one of the remaining squares (U, W, or Y).
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Hint 3 of 3
Pick a front face and fold the rest into place. The only face left over after seating X's neighbors is the one directly across from X.
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Approach: fold around a chosen front face
  1. Make V the front face. Its neighbors fold in: U β†’ left, W β†’ right, X β†’ bottom, and Z (below X) wraps around to the back. The square Y sits above W, and since W became the right face, Y folds up to the top.
  2. So X is the bottom and Y is the top β€” top is opposite bottom, so the face opposite X is Y.
  3. Why this transfers: two quick rules crack most net problems β€” squares that share an edge are adjacent (never opposite), and the two ends of a straight line of three squares are always opposite. Apply those before folding anything in your head.
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