Problem 4 · 2022 Math Kangaroo
Easy
Logic & Word Problems
sum-constraintcasework
In the four squares of a row there always have to be exactly two coins. In the four squares below each other there also always have to be exactly two coins. On which square does one more coin have to be placed?
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Answer: D — square D
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Hint 1 of 2
Count the coins in each row and in each column - which one still has only one?
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Hint 2 of 2
One row and one column are each short a coin; they meet at a single empty square.
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Approach: find the row and column that are short a coin
- The third row down has only 1 coin, and the third column across also has only 1 coin.
- Both still need one more coin to reach two.
- The empty square where that row and column meet is square D, so the coin goes there.
Mark:
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