๐Ÿฆ˜ Math Kangaroo Grade All Felix 1-2 Ecolier 3-4 Benjamin 5-6 Kadett 7-8 Junior 9-10 Student 11-12 โ‡„ switch contest
Focused Practice

Across all years

Tick one or more bands and topics — problems are pulled from every authored year.

Showing 20 of 485 matching
Difficulty bands: (none = all)
Topics: (none = all topics)
Order:
Problem 1 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning tiling-tessellationspatial-reasoning

Which of the pieces shown completes the pattern? (The five choices A–E are pictured below the question.)

Figure for Math Kangaroo 2025 Problem 1
Show answer
Answer: C
Show hints
Hint 1 of 2
The big design is one repeating pattern; the white window is just a square-shaped hole punched out of it.
Still stuck? Show hint 2 →
Hint 2 of 2
Look at the lines touching all four edges of the hole and ask which piece lets every one of them continue without a break.
Show solution
Approach: match the missing tile to the lines around the hole
  1. The hole sits inside a repeating pattern of overlapping squares and diamonds, so the right piece is the one that keeps every line going straight across the gap.
  2. Trace the lines that arrive at the top, bottom, left and right edges of the white square; the correct piece must connect to all of them at once.
  3. Only choice C lines up on all four sides so the pattern stays seamless with no broken lines, so the answer is (C).
Mark: · log in to save
Problem 1 · 2025 Math Kangaroo Easy
Arithmetic & Operations place-value

Nico and his little sister play with shells and marbles. Each shell is worth 6 and each marble is worth 1 (shell = 6, marble = 1). Which picture shows the value 16?

Figure for Math Kangaroo 2025 Problem 1
Show answer
Answer: E
Show hints
Hint 1 of 2
Each shell counts as 6 and each marble counts as 1 - add up each picture's total.
Still stuck? Show hint 2 →
Hint 2 of 2
You need a total of exactly 16, so look for two shells plus four marbles.
Show solution
Approach: add the shell and marble values in each option
  1. A shell is worth 6 and a marble is worth 1.
  2. Two shells give 12, and you need 4 more to reach 16, so 4 marbles.
  3. The picture with two shells and four marbles totals 12 + 4 = 16.
  4. That is option E.
Mark: · log in to save
Problem 1 · 2025 Math Kangaroo Easy
Arithmetic & Operations subtraction

Pablo has six balloons. He gives away two of his balloons. How many balloons does Pablo have now?

Show answer
Answer: C — 4
Show hints
Hint 1 of 2
You start with six and lose two of them.
Still stuck? Show hint 2 →
Hint 2 of 2
"Gives away" means take away — this is just subtraction.
Show solution
Approach: subtract what is given away
  1. Pablo begins with 6 balloons.
  2. He gives away 2, so take 2 away from 6.
  3. 6 − 2 = 4, so Pablo has 4 balloons.
Mark: · log in to save
Problem 1 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning sequence-of-figuresarea-fraction

In which of the following hexagons is exactly one third of the area black and half of the area white? (The remaining sixth is grey.)

Figure for Math Kangaroo 2025 Problem 1
Show answer
Answer: E
Show hints
Hint 1 of 2
A regular hexagon splits into six equal triangles, so each colour must cover a whole number of those triangles.
Still stuck? Show hint 2 →
Hint 2 of 2
One third of six triangles is two triangles black; half of six is three triangles white โ€” find the picture with exactly that count.
Show solution
Approach: count equal triangles by colour
  1. Divide the hexagon into its six identical triangles.
  2. One third black means 2 triangles black; one half white means 3 triangles white; the last triangle is the grey/patterned one.
  3. Only option E shows exactly 2 black and 3 white triangles.
Mark: · log in to save
Problem 1 · 2025 Math Kangaroo Easy
Number Theory place-value

Lisa can make the number 2025 out of four wooden digits. Which of these is the largest number she can make using those same four digits?

Show answer
Answer: C — 5220
Show hints
Hint 1 of 2
You have the four digits 2, 0, 2, 5 โ€” think about where the biggest digit should go.
Still stuck? Show hint 2 →
Hint 2 of 2
To make the largest number, put the digits in decreasing order from left to right.
Show solution
Approach: order the digits from largest to smallest
  1. The available digits are 2, 0, 2, 5.
  2. A number is largest when its biggest digits sit in the highest place values.
  3. Sorted from greatest to least: 5, 2, 2, 0, giving 5220, which is (C).
Mark: · log in to save
Problem 1 · 2025 Math Kangaroo Easy
Number Theory perfect-square

The number 2025 is a perfect square, because \(2025 = 45^2\). How many years will pass until the next year whose number is a perfect square?

Show answer
Answer: B — 91
Show hints
Hint 1 of 2
The current year is 45 squared—what is the very next whole number you would square?
Still stuck? Show hint 2 →
Hint 2 of 2
The gap to the next perfect square is 46² minus 45², which you can get without multiplying out either square.
Show solution
Approach: difference of consecutive squares
  1. The next perfect square after 45² is 46².
  2. The gap equals 46² − 45² = 46 + 45 = 91.
  3. So 91 years pass.
Mark: · log in to save
Problem 2 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning reflectionsymmetry

Anna builds a wall out of black and grey bricks that shows 2025. What can Bella read on the back of the wall? (The five choices A–E are pictured below the question.)

Figure for Math Kangaroo 2025 Problem 2
Show answer
Answer: E
Show hints
Hint 1 of 2
Looking at the back of a wall is like seeing it in a mirror.
Still stuck? Show hint 2 →
Hint 2 of 2
Reflect the whole ‘2025’ left-to-right; each digit flips and the order of digits reverses.
Show solution
Approach: horizontal mirror reflection
  1. Seeing the back of the wall is exactly like holding the front up to a mirror, so the whole picture flips left–right.
  2. Two things happen at once: the order of the digits reverses (so 2025 reads 5202), and each digit itself is mirrored.
  3. The choice that shows this left–right flip of the bricks is the back view, which is (E).
Mark: · log in to save
Problem 2 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning path-tracinggrid

Kenny the Kangaroo hops from his school to the zoo. He hops like this: up 2, up-left 2, down-left 1, left 4 (see picture). From the zoo, Kenny hops like this: right 3, up-right 2, up 2. Which house does Kenny land at?

Figure for Math Kangaroo 2025 Problem 2
Show answer
Answer: A
Show hints
Hint 1 of 2
Start at the Zoo dot and follow the new hops one by one on the grid.
Still stuck? Show hint 2 →
Hint 2 of 2
Track the arrows right 3, up-right 2, up 2 step by step until you land on a house.
Show solution
Approach: trace the hops on the grid from the zoo
  1. Begin at the Zoo marker and move right 3 squares.
  2. Then move diagonally up-right 2 squares, then straight up 2 squares.
  3. The landing square sits at the house labelled A.
  4. So Kenny lands at house A.
Mark: · log in to save
Problem 2 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning careful-countingspatial-reasoning

How many of these shapes are triangles?

Figure for Math Kangaroo 2025 Problem 2
Show answer
Answer: E — 6
Show hints
Hint 1 of 3
Point at each shape and ask: does it have exactly three corners?
Still stuck? Show hint 2 →
Hint 2 of 3
A triangle has three straight sides and three corners — count only those.
Still stuck? Show hint 3 →
Hint 3 of 3
Touch each three-cornered shape once and say the numbers out loud as you go.
Show solution
Approach: identify and tally the three-sided shapes
  1. Go through the shapes and keep only the ones with three straight sides.
  2. The triangles are: the purple one, the big grey one, the small brown one, the green one, the blue one, and the tan one on the right.
  3. That makes 6 triangles.
Mark: · log in to save
Problem 2 · 2025 Math Kangaroo Easy
Geometry & Measurement arearatio

The base of a triangle is extended by 50% and its height is reduced by one third. What is the ratio of the area of the new triangle to the area of the original triangle?

Show answer
Answer: B — 1:1
Show hints
Hint 1 of 2
A triangle's area is proportional to base times height.
Still stuck? Show hint 2 →
Hint 2 of 2
Multiply the two change factors together and see what happens to the product.
Show solution
Approach: multiply the two scale factors
  1. Extending the base by 50% makes it \(\tfrac{3}{2}\) of the old base; reducing the height by one third makes it \(\tfrac{2}{3}\) of the old height.
  2. Area scales by \(\tfrac{3}{2}\times\tfrac{2}{3}=1\), so the area is unchanged.
  3. The ratio of new area to old is 1:1, answer B.
Mark: · log in to save
Problem 2 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning transformationssymmetry

Isabelle plays with a hexagonal sheet of paper. With each move she rotates the hexagon by the same angle in the same direction. The illustration shows the sheet at the start and after the first move. After how many moves does the sheet look the same as it did at the beginning?

Figure for Math Kangaroo 2025 Problem 2
Show answer
Answer: A — 6
Show hints
Hint 1 of 2
The single dotted wedge acts as a marker โ€” track where it lands after one move.
Still stuck? Show hint 2 →
Hint 2 of 2
Find the rotation angle of one move, then see how many moves complete a full turn back to the start.
Show solution
Approach: track the marker wedge under repeated equal rotations
  1. The colouring has no rotational symmetry, so the sheet only looks identical after a whole turn brings every wedge home.
  2. Comparing the start and the first move, the unique dotted wedge has shifted by one position โ€” a 60ยฐ rotation.
  3. A 60ยฐ step needs \(360^\circ \div 60^\circ = 6\) moves to return to the original picture, which is (A).
Mark: · log in to save
Problem 2 · 2025 Math Kangaroo Easy
Arithmetic & Operations estimate-and-pick

Mike obtains a number x by dividing \(\sqrt{11}\) by 3. Where is the number x located on the number line?

Show answer
Answer: B — between 1 and 2
Show hints
Hint 1 of 2
First estimate √11 between two whole numbers, then divide by 3.
Still stuck? Show hint 2 →
Hint 2 of 2
√11 is a little more than 3, so dividing by 3 lands the result just above 1.
Show solution
Approach: estimate the square root, then divide
  1. √11 is between 3 and 4 (closer to 3.3).
  2. Dividing by 3 gives about 1.1.
  3. That lies between 1 and 2.
Mark: · log in to save
Problem 3 · 2025 Math Kangaroo Easy
Arithmetic & Operations total-then-dividework-backward

A bookshelf with three rows has 17 books in the top row, 15 books in the middle row and 7 books in the bottom row. Monika would like to have the same number of books in each row, but she wants to rearrange as few books as possible. How many books does she have to move from the middle row to the bottom row?

Figure for Math Kangaroo 2025 Problem 3
Show answer
Answer: B — 2
Show hints
Hint 1 of 2
First find how many books each row should hold.
Still stuck? Show hint 2 →
Hint 2 of 2
Books should only be moved into rows that are short; figure out the bottom row’s shortfall.
Show solution
Approach: even out the rows with fewest moves
  1. Total books: 17 + 15 + 7 = 39, so each row should have 39 ÷ 3 = 13.
  2. The bottom row is short by 13 − 7 = 6 books; the top row has 4 spare and the middle has 2 spare.
  3. To move as few as possible, send the top’s 4 spare and the middle’s 2 spare straight to the bottom.
  4. So only 2 books go from the middle row to the bottom row.
Mark: · log in to save
Problem 3 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning sequence-of-figurescube-views

Mia builds a large cube out of small cubes. While she is building it, she takes a photo at five different times. Which of the five photos shown is the fourth?

Figure for Math Kangaroo 2025 Problem 3
Show answer
Answer: A
Show hints
Hint 1 of 2
The photos show the cube growing, so put them in order from fewest cubes to a full cube.
Still stuck? Show hint 2 →
Hint 2 of 2
Order the five pictures by how complete the cube is, then count to the fourth one.
Show solution
Approach: order the photos by how built-up the cube is
  1. The cube is assembled over time, so the photos go from least built to fully built.
  2. Arrange the five images by increasing number of small cubes placed.
  3. The fourth picture in that order is the nearly-complete cube shown in option A.
  4. So the fourth photo is A.
Mark: · log in to save
Problem 3 · 2025 Math Kangaroo Easy
Counting & Probability careful-counting

How many pencils are in this picture?

Figure for Math Kangaroo 2025 Problem 3
Show answer
Answer: B — 8
Show hints
Hint 1 of 3
The pencils cross over each other, so counting the middles is tricky.
Still stuck? Show hint 2 →
Hint 2 of 3
Each pencil has one pointy tip and one pink eraser end — count the ends instead.
Still stuck? Show hint 3 →
Hint 3 of 3
Count just the pointy tips, or just the pink ends, and that is how many pencils there are.
Show solution
Approach: count by matching each tip to its eraser end
  1. The pencils overlap, so count the ends instead of the middles.
  2. Match each sharpened dark tip to one pink eraser end.
  3. There are 8 such pairs, so there are 8 pencils.
Mark: · log in to save
Problem 3 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning net-foldingcareful-counting

The left and right parts of a three-part brochure each contain four transparent windows. If these two parts are folded onto the middle part, some of the numbers written on the middle part are visible through the windows. What is the sum of the visible numbers when the brochure is folded?

Figure for Math Kangaroo 2025 Problem 3
Show answer
Answer: D — 14
Show hints
Hint 1 of 3
Both side panels fold over the middle, stacking on top of each other, so each panel reflects left-right as it closes.
Still stuck? Show hint 2 →
Hint 2 of 3
A middle number shows only if BOTH the left panel and the right panel have a window over that same cell.
Still stuck? Show hint 3 →
Hint 3 of 3
Find the windows each panel lands on after folding, then keep only the cells where the two sets of windows overlap.
Show solution
Approach: intersect the two panels' window positions
  1. Both flaps fold inward and cover the whole 3ร—3 middle, so a number is visible only where the left flap AND the right flap both have a window (you must see through both layers).
  2. Folding the left flap (it reflects) puts its windows over the middle's two right columns; folding the right flap puts its windows over the middle's two left columns โ€” they overlap only in the centre column.
  3. There the visible numbers are 9 (top) and 5 (middle), so the sum is \(9+5=14\), answer D.
Mark: · log in to save
Problem 3 · 2025 Math Kangaroo Easy
Counting & Probability careful-countingcasework
Figure for Math Kangaroo 2025 Problem 3
Show answer
Answer: E
Show hints
Hint 1 of 2
List the sets of three different numbers from 1โ€“6 that add up to 8.
Still stuck? Show hint 2 →
Hint 2 of 2
See which face value never appears in any of those sets.
Show solution
Approach: list all valid distinct triples summing to 8
  1. Three different dice faces totalling 8: only {1,2,5} and {1,3,4} work.
  2. Across both, the values used are 1, 2, 3, 4 and 5.
  3. The value 6 never occurs, so the face definitely not shown is the 6, which is choice (E).
Mark: · log in to save
Problem 3 · 2025 Math Kangaroo Easy
Logic & Word Problems complementary-countingsum-constraint

Vasily has 20 balls. Each ball is either yellow, green, blue or black. Of the balls, exactly 17 are not green, exactly 15 are not black, and exactly 12 are not yellow. How many of his balls are blue?

Show answer
Answer: D — 4
Show hints
Hint 1 of 2
Turn each "not" statement into a count of that colour.
Still stuck? Show hint 2 →
Hint 2 of 2
Green = 20 − 17, black = 20 − 15, yellow = 20 − 12; the rest are blue.
Show solution
Approach: complementary counting
  1. Not green = 17 means green = 3; not black = 15 means black = 5; not yellow = 12 means yellow = 8.
  2. Blue = 20 − 3 − 5 − 8 = 4.
Mark: · log in to save
Problem 4 · 2025 Math Kangaroo Easy
Spatial & Visual Reasoning cube-viewscareful-counting

Grey squares of equal size are glued onto a cube (see picture). All surfaces of the cube then look the same. How many grey squares were used in total?

Figure for Math Kangaroo 2025 Problem 4
Show answer
Answer: D — 18
Show hints
Hint 1 of 2
A cube has 6 faces, and the puzzle says every face ends up looking exactly the same.
Still stuck? Show hint 2 →
Hint 2 of 2
So count the grey squares on just one face, then multiply by 6.
Show solution
Approach: count one face, then multiply by six
  1. Because all six faces look identical, you only need to count the grey squares on a single face and then multiply.
  2. Each face carries 3 grey squares in its diamond design.
  3. With 6 matching faces that makes 3 × 6 = 18 grey squares in total, so the answer is (D) 18.
Mark: · log in to save
Problem 4 · 2025 Math Kangaroo Easy
Arithmetic & Operations order-of-operationssum-constraint

Simona writes the numbers 2, 0, 2 and 5 in the boxes, one number per box (see picture). In what order can she write them so that the calculation gives the biggest result?

Figure for Math Kangaroo 2025 Problem 4
Show answer
Answer: E — 5, 2, 0, 2
Show hints
Hint 1 of 2
The third box is the one that gets subtracted, so put the smallest number there.
Still stuck? Show hint 2 →
Hint 2 of 2
Put the 0 in the subtracted (third) box and add everything else.
Show solution
Approach: minimise what is subtracted, maximise what is added
  1. The calculation is first + second minus third + fourth.
  2. To make it biggest, subtract the smallest number, which is 0.
  3. Then the other three (5, 2, 2) are all added: 5 + 2 - 0 + 2 = 9.
  4. The order 5, 2, 0, 2 does this, which is option E.
Mark: · log in to save