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Math Kangaroo — Ecolier

2015 Math Kangaroo — Ecolier

24 problems — read each, give it a real try, then peek at the hints.

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Problem 1 · 2015 Math Kangaroo Easy
Algebra & Patterns evaluate-formulaorder-of-operations

Start with the number in the first cloud and follow the arrows. The arrows say, in order, −0, then +1, then ×5. Which number is hidden behind the question mark?

Figure for Math Kangaroo 2015 Problem 1
Show answer
Answer: E — 15
Show hints
Hint 1 of 2
Start with the number in the first cloud and do what each arrow says, one arrow at a time.
Still stuck? Show hint 2 →
Hint 2 of 2
Taking away 0 keeps the number the same; then add 1, then make 5 copies of it.
Show solution
Approach: follow the operation chain left to right
  1. Begin with 2. The first arrow says −0, so it stays 2.
  2. The next arrow says +1, giving 3.
  3. The last arrow says ×5, giving 3 × 5 = 15.
  4. The hidden number is 15.
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Problem 2 · 2015 Math Kangaroo Easy
Spatial & Visual Reasoning spatial-reasoning

Florian has 10 identical metal strips, each with the same number of holes. He bolts them together in pairs to make the 5 long strips in the picture. Which of the long strips is the longest?

Figure for Math Kangaroo 2015 Problem 2
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Answer: A
Show hints
Hint 1 of 2
Each long strip is two short strips laid end to end, sharing a few holes where they overlap.
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Hint 2 of 2
The fewer holes the two short strips share, the further the long strip stretches.
Show solution
Approach: compare how much each pair of strips overlaps
  1. Every long strip is two equal short strips bolted so they share some holes in the overlap.
  2. Picture sharing only 1 hole versus sharing many: the less the strips overlap, the longer they reach.
  3. Strip A is the one whose two pieces overlap the least, so it stretches the furthest.
  4. The longest strip is A.
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Problem 3 · 2015 Math Kangaroo Easy
Arithmetic & Operations total-then-divide
Figure for Math Kangaroo 2015 Problem 3
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Answer: B
Show hints
Hint 1 of 2
First add up everything Lucy had in her purse.
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Hint 2 of 2
Take away the 7 Kangas she paid; match what is left to a picture.
Show solution
Approach: total the money, then subtract the price
  1. The purse holds a 10, two 2-coins and a 1-coin: 10 + 2 + 2 + 1 = 15 Kangas.
  2. Paying 7 for the ball leaves 15 − 7 = 8 Kangas.
  3. The purse that adds up to 8 is the 5 + 2 + 1 picture.
  4. That is option B.
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Problem 4 · 2015 Math Kangaroo Easy
Number Theory place-valuedigit-sum

If you multiply both digits of the number 35, you get 15. How big is the sum of both digits?

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Answer: E — 8
Show hints
Hint 1 of 2
The two digits of 35 are 3 and 5; the problem already multiplies them.
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Hint 2 of 2
The question asks for the sum of those same two digits, not the product.
Show solution
Approach: read off the digits, then add them
  1. The digits of 35 are 3 and 5 (and indeed 3 × 5 = 15).
  2. Their sum is 3 + 5 = 8.
  3. So the answer is 8.
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Problem 5 · 2015 Math Kangaroo Easy
Algebra & Patterns substitution

The two shapes below each stand for a number. The red triangle plus 4 equals 7, and the blue square plus the red triangle equals 9. Which number is hidden behind the square?

Figure for Math Kangaroo 2015 Problem 5
Show answer
Answer: E — 6
Show hints
Hint 1 of 2
The first picture-sum tells you the triangle's number all by itself.
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Hint 2 of 2
Once you know the triangle, use the second picture-sum to find the square.
Show solution
Approach: find the triangle first, then use it to find the square
  1. Triangle and 4 make 7, so the triangle must be 3 (because 3 + 4 = 7).
  2. The square and the triangle make 9, so the square and 3 make 9.
  3. The number that goes with 3 to make 9 is 6 (since 6 + 3 = 9).
  4. The hidden number is 6.
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Problem 6 · 2015 Math Kangaroo Easy
Spatial & Visual Reasoning spatial-reasoningreflection
Figure for Math Kangaroo 2015 Problem 6
Show answer
Answer: A
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Hint 1 of 2
The flat top view shows the eight letters going around in order.
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Hint 2 of 2
On a side view the letters wrap around, so neighbours keep the same order and tilt.
Show solution
Approach: match the cyclic order of letters around the umbrella
  1. Read the letters around the top of the umbrella in order: K, A, N, G, A, R, O, O.
  2. On a side view the visible panels must keep that same neighbouring order.
  3. Only picture A shows the letters in the correct order and orientation around the rim.
  4. So the umbrella is A.
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Problem 7 · 2015 Math Kangaroo Easy
Spatial & Visual Reasoning path-tracingsequence-of-figures
Figure for Math Kangaroo 2015 Problem 7
Show answer
Answer: E
Show hints
Hint 1 of 2
Every line skips one point and lands on the next-but-one point.
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Hint 2 of 2
Keep hopping by 2 and check whether you touch all nine points before you come back to 1.
Show solution
Approach: trace the step-by-2 path through all nine points
  1. Start at 1 and keep hopping over one point: 1→3→5→7→9→2→4→6→8 and then back to 1.
  2. Counting along, this hopping touches every one of the nine points exactly once before closing up.
  3. Drawing all those lines makes one continuous nine-pointed star, which is picture E.
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Problem 8 · 2015 Math Kangaroo Easy
Counting & Probability careful-counting

In the diagram you can see a very ragged island. Some of the frogs are sitting in the water. How many are sitting on the island?

Figure for Math Kangaroo 2015 Problem 8
Show answer
Answer: B — 6
Show hints
Hint 1 of 2
The wavy line is the edge of the island; some frogs are inside it on land and some outside it in the water.
Still stuck? Show hint 2 →
Hint 2 of 2
Point at each frog and ask: is it inside the wavy line or out in the water?
Show solution
Approach: count only the frogs sitting inside the island's edge
  1. The wavy line is the shore: everything inside it is the island, everything outside is water.
  2. Go frog by frog and keep only the ones inside the wavy line.
  3. Counting those, exactly 6 frogs are sitting on the island.
  4. So the answer is 6.
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Problem 9 · 2015 Math Kangaroo Medium
Algebra & Patterns work-backward

Luis has got 7 apples and 2 bananas. He gives 2 apples to his friend Jacob, who gives him bananas in return. Afterwards Luis has got the same amount of apples as bananas. How many bananas did Luis get from Jacob?

Show answer
Answer: B — 3
Show hints
Hint 1 of 2
First update the apple count after Luis gives 2 away.
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Hint 2 of 2
Set the new banana count equal to the apple count and read off how many bananas he received.
Show solution
Approach: track apples and bananas, then make them equal
  1. Luis gives away 2 of his 7 apples, leaving 5 apples.
  2. Afterwards he has as many bananas as apples, so he must have 5 bananas.
  3. He started with 2 bananas, so he received 5 − 2 = 3 bananas from Jacob.
  4. The answer is 3.
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Problem 10 · 2015 Math Kangaroo Medium
Spatial & Visual Reasoning net-foldingfolding

Julia folds the paper net pictured on the right into a cube. Which number is on the face that is opposite to the face with the number 3?

Figure for Math Kangaroo 2015 Problem 10
Show answer
Answer: E — 6
Show hints
Hint 1 of 2
Find the straight strip of three squares that contains the 3.
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Hint 2 of 2
In a strip of three faces, the two end faces fold to opposite sides.
Show solution
Approach: use the straight three-square strip of the net
  1. The faces 3, 5 and 6 lie in a straight vertical strip of the net.
  2. When a strip of three faces is folded, the two ends become opposite faces.
  3. So 3 and 6 end up on opposite faces of the cube.
  4. The face opposite 3 carries 6.
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Problem 11 · 2015 Math Kangaroo Medium
Spatial & Visual Reasoning cube-viewsspatial-reasoning

Jack makes a cube from 27 small cubes. The small cubes are either grey or white as shown in the diagram. Two small cubes with the same colour are not allowed to be placed next to each other. How many small, white cubes has Jack used?

Figure for Math Kangaroo 2015 Problem 11
Show answer
Answer: C — 13
Show hints
Hint 1 of 2
No two cubes of the same colour may touch, so the colours alternate like the dark-and-light squares on a checkerboard.
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Hint 2 of 2
The big cube is built from 27 little cubes; the corners are grey, so count up the grey cubes and the rest are white.
Show solution
Approach: colour the 27 little cubes like a checkerboard
  1. Since same-coloured cubes can't touch, the colours flip back and forth like a checkerboard going up, across and back.
  2. Start the corner as grey: then the grey cubes are the 8 corners and the 6 little cubes sitting in the middle of each face — that is 8 + 6 = 14 grey cubes.
  3. All 27 cubes minus the 14 grey ones leaves the white cubes: 27 − 14 = 13.
  4. Jack used 13 white cubes.
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Problem 12 · 2015 Math Kangaroo Medium
Logic & Word Problems work-backwardoff-by-one

10 runners start in a running race. At the finish, there are 3 more runners behind Thomas than there are in front of him. In which position did Thomas finish?

Show answer
Answer: C — 4
Show hints
Hint 1 of 2
Besides Thomas there are 9 other runners, split into a front group and a back group.
Still stuck? Show hint 2 →
Hint 2 of 2
The back group is 3 bigger than the front group; try sharing the 9 runners so the back has 3 more.
Show solution
Approach: share the other 9 runners into front and back groups
  1. Take Thomas out for a moment: the other 9 runners are split into the ones in front and the ones behind.
  2. The back group must be 3 bigger than the front group, so split 9 into 3 in front and 6 behind (6 is 3 more than 3).
  3. With 3 runners in front of him, Thomas is the next one, so he is in 4th place.
  4. The answer is 4.
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Problem 13 · 2015 Math Kangaroo Medium
Counting & Probability careful-counting

Joseph has got a toy car, a teddy bear, a ball and a ship. He wants to put them in a new order on the shelf. The ship must be next to the car, and the teddy bear should also be next to the car. In how many different orders can he put the toys on the shelf?

Show answer
Answer: B — 4
Show hints
Hint 1 of 2
The car must touch both the ship and the teddy, so the car sits between them.
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Hint 2 of 2
Treat ship-car-teddy as one block and place the ball at either end.
Show solution
Approach: form the forced block, then place the remaining toy
  1. The ship and the teddy both must be next to the car, so the car is in the middle of a block: ship–car–teddy.
  2. That block can be ordered 2 ways (ship–car–teddy or teddy–car–ship).
  3. The ball goes at the left end or the right end of the block: 2 choices.
  4. Total arrangements: 2 × 2 = 4.
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Problem 14 · 2015 Math Kangaroo Medium
Spatial & Visual Reasoning path-tracingspatial-reasoning

Peter rides his bike along a cycle path in a park. He starts at point S and rides in the direction of the arrow. At the first crossing he turns right, then at the next left, and then again to the right and then again to left. Which crossing does he not reach?

Figure for Math Kangaroo 2015 Problem 14
Show answer
Answer: D — D
Show hints
Hint 1 of 2
Put your finger on S, point it the way the arrow points, and ride along.
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Hint 2 of 2
At each crossing make the next turn in the list (right, then left, then right, then left) and see which labelled crossing your finger never lands on.
Show solution
Approach: trace the route obeying the turn sequence
  1. Start at S facing the arrow and ride to the first crossing, then turn as told: right, then left, then right, then left.
  2. Tracing this with your finger, Peter rolls through the other crossings but his turns steer him away from one of them.
  3. The crossing he never reaches is D.
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Problem 15 · 2015 Math Kangaroo Medium
Counting & Probability careful-counting

Two of the 5 ladybirds in the picture are always friends with each other if the difference between their number of dots is exactly 1. Today every ladybird has sent an SMS to each of their friends. How many SMS messages were sent?

Figure for Math Kangaroo 2015 Problem 15
Show answer
Answer: C — 6
Show hints
Hint 1 of 2
First count the spots on each ladybird, then pair up those that differ by exactly one spot.
Still stuck? Show hint 2 →
Hint 2 of 2
Each friendship means two messages, since each friend texts the other.
Show solution
Approach: find friend pairs, then count messages both ways
  1. The ladybirds carry 2, 3, 3, 5 and 6 spots.
  2. Friends differ by exactly 1 spot: the 2-spot is friends with each 3-spot, and the 5-spot is friends with the 6-spot — 3 friendships in all.
  3. In each friendship both friends send a message, so each pair accounts for 2 messages.
  4. Total messages: 3 × 2 = 6.
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Problem 16 · 2015 Math Kangaroo Medium
Arithmetic & Operations grouping

There are 10 balls, numbered 0 to 9 in a basket. John and George play a game. Each person is allowed to take three balls from the basket and calculate the total of the numbers on the balls. What is the biggest possible difference between the John and George's totals?

Figure for Math Kangaroo 2015 Problem 16
Show answer
Answer: E — 21
Show hints
Hint 1 of 2
To make the gap as large as possible, one player grabs the biggest numbers and the other the smallest.
Still stuck? Show hint 2 →
Hint 2 of 2
They draw from the same basket, so the two sets of three balls cannot overlap.
Show solution
Approach: maximise one total and minimise the other
  1. One player can take the three largest balls: 9 + 8 + 7 = 24.
  2. The other is then left to take the three smallest: 0 + 1 + 2 = 3.
  3. The biggest possible difference is 24 − 3 = 21.
  4. The answer is 21.
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Problem 17 · 2015 Math Kangaroo Stretch
Geometry & Measurement area-decompositiongrid-counting

Luca wants to cut the shape in figure 1 into equally sized small triangles (like those in figure 2). One of these triangles is already drawn on figure 1. How many of these triangles will he get?

Figure for Math Kangaroo 2015 Problem 17
Show answer
Answer: D — 15
Show hints
Hint 1 of 2
Notice that one little triangle is exactly half of a small grid square.
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Hint 2 of 2
If you know how much room the big shape covers in grid squares, two triangles fit in each square.
Show solution
Approach: fit the half-square triangles into the shape
  1. Each little triangle is half of a small grid square, so two of them fill one square.
  2. The big shape covers seven-and-a-half squares of room, and two triangles fit in every square.
  3. Doubling seven-and-a-half gives 15 little triangles.
  4. Luca gets 15 triangles.
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Problem 18 · 2015 Math Kangaroo Stretch
Spatial & Visual Reasoning compositionspatial-reasoning

Some of the small squares on each of the square transparencies have been coloured black. If you slide the three transparencies on top of each other, without lifting them from the table, a new pattern can be seen. What is the maximum number of black squares which could be seen in the new pattern?

Figure for Math Kangaroo 2015 Problem 18
Show answer
Answer: D — 8
Show hints
Hint 1 of 2
Stacking the see-through sheets makes a square black wherever any sheet is black there.
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Hint 2 of 2
Slide them so the black cells overlap as little as possible, then count the covered squares.
Show solution
Approach: overlay the transparencies and count the black cells
  1. Each sheet is transparent, so a cell looks black if it is black on at least one of the stacked sheets.
  2. Lining the three sheets up so their black cells barely overlap covers as many squares as possible.
  3. Together the black cells can cover 8 of the 9 squares, leaving just one clear.
  4. The maximum number of black squares is 8.
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Problem 19 · 2015 Math Kangaroo Stretch
Algebra & Patterns sum-constraintcasework

The numbers 1, 2, 3, 4 and 9 are written into the squares on the following figure. The sum of the three numbers in the horizontal row should be the same as the sum of the three numbers in the vertical column. Which number is written in the middle?

Figure for Math Kangaroo 2015 Problem 19
Show answer
Answer: E — 9
Show hints
Hint 1 of 2
The middle square sits in both the row and the column, so it gets used in both totals.
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Hint 2 of 2
The other four numbers must split into two equal-sized pairs, one pair for the row's ends and one for the column's ends.
Show solution
Approach: the middle is shared, so the other four split into two equal pairs
  1. The number in the middle is part of both the row total and the column total, so the other four numbers fill the two ends of the row and the two ends of the column.
  2. Those four numbers must make two pairs that add up to the same amount; from 1, 2, 3, 4 the pairs 1 + 4 = 5 and 2 + 3 = 5 match perfectly, leaving 9 for the middle.
  3. Then each line totals 9 + 5 = 14, the same both ways, so it works.
  4. The middle number is 9.
  5. A quick check for older kidsAll five numbers add to 19. The row and column together use the middle twice, giving 19 + middle, and that must split into two equal halves — so 19 + middle is even, which forces the middle to be odd, and 9 is the choice that balances.
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Problem 20 · 2015 Math Kangaroo Stretch
Spatial & Visual Reasoning tiling-tessellationspatial-reasoning
Figure for Math Kangaroo 2015 Problem 20
Show answer
Answer: A
Show hints
Hint 1 of 2
Three equal pieces means each piece has one third of the shape's squares.
Still stuck? Show hint 2 →
Hint 2 of 2
Try fitting the candidate piece into the figure three times without gaps or overlaps.
Show solution
Approach: tile the figure with three congruent pieces
  1. The shape is split into three identical pieces, so each piece covers a third of its squares.
  2. Test each option: only one piece can be placed three times to cover the whole shape exactly.
  3. That piece is option A.
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Problem 21 · 2015 Math Kangaroo Stretch
Spatial & Visual Reasoning path-tracing
Figure for Math Kangaroo 2015 Problem 21
Show answer
Answer: B
Show hints
Hint 1 of 2
Pick a point on a curve and follow it all the way around.
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Hint 2 of 2
It is a single loop only if you return to the start having traced the entire drawing.
Show solution
Approach: trace one continuous curve
  1. Start anywhere on a line and follow it, going straight through each crossing.
  2. In four of the pictures you return having drawn only part of the figure, so they are made of more than one loop.
  3. In picture B the single trace covers the whole drawing, so it is one large loop.
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Problem 22 · 2015 Math Kangaroo Stretch
Geometry & Measurement square-areacareful-counting

In this square there are 9 dots. The distance between the points is always the same. You can draw a square by joining 4 points. How many different sizes can such squares have?

Figure for Math Kangaroo 2015 Problem 22
Show answer
Answer: D — 3
Show hints
Hint 1 of 2
Squares can sit straight on the dots, but they can also be tilted like a diamond.
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Hint 2 of 2
Hunt for a tiny straight square, a big straight square, and one slanted square.
Show solution
Approach: find every square size, straight ones and the tilted one
  1. On the 3-by-3 dots you can make a tiny straight square (1 step on each side) and a big straight square (2 steps on each side).
  2. You can also make a slanted square shaped like a diamond, joining the four middle dots of the edges.
  3. That is three squares of three different sizes.
  4. The answer is 3.
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Problem 23 · 2015 Math Kangaroo Stretch
Counting & Probability careful-counting

Thomas drew a pig and a shark. He cuts each animal into three pieces. Then he takes one of the two heads, one of the two middle sections and one of the two tails and lays them together to make another animal. How many different animals can he make in this way?

Figure for Math Kangaroo 2015 Problem 23
Show answer
Answer: E — 8
Show hints
Hint 1 of 2
A new animal needs a head, a middle and a tail, and there are two choices for each part.
Still stuck? Show hint 2 →
Hint 2 of 2
Multiply the number of choices for the three parts.
Show solution
Approach: multiply the choices for each of the three parts
  1. There are 2 heads to choose from, 2 middle sections, and 2 tails.
  2. Each new animal is one choice for each part, so 2 × 2 × 2 = 8 animals can be built.
  3. The answer is 8.
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Problem 24 · 2015 Math Kangaroo Stretch
Logic & Word Problems divisibilitywork-backward

Anna, Berta, Charlie, David and Elisa baked biscuits at the weekend. Anna baked 24, Berta 25, Charlie 26, David 27 and Elisa 28 biscuits. By the end of the weekend one of the children had twice as many, one 3 times, one 4 times, one 5 times and one 6 times as many biscuits as on Saturday. Who baked the most biscuits on Saturday?

Show answer
Answer: C — Charlie
Show hints
Hint 1 of 2
Each child's weekend total is their Saturday pile shared into 2, 3, 4, 5 or 6 equal groups (each size used once).
Still stuck? Show hint 2 →
Hint 2 of 2
Find which totals can be shared evenly by 5 and by 3 first, since only one each can.
Show solution
Approach: see how each total splits evenly, then share it out to find Saturday
  1. Each total (24, 25, 26, 27, 28) is a Saturday pile copied 2, 3, 4, 5 or 6 times, with each copy-number used once.
  2. Only 25 shares evenly into 5 groups (25 ÷ 5 = 5) and only 27 shares evenly into 3 groups (27 ÷ 3 = 9).
  3. That leaves 26 as 2 copies (26 ÷ 2 = 13), 28 as 4 copies (28 ÷ 4 = 7), and 24 as 6 copies (24 ÷ 6 = 4).
  4. Saturday piles: Anna 4, Berta 5, Charlie 13, David 9, Elisa 7 — Charlie's 13 is the biggest, so the answer is Charlie.
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