🇺🇸 AMC 8 ⇄ switch contest
1996 AMC 8 Stretch

Problem 7

Problem 7 · AMC 8 Stretch Stretch
Geometry & Measurement considering-extreme-casesvisual-representation
Draw a five-pointed star (a pentagram). Add up the five sharp point angles at the tips. What is the total? (It comes out the same for every five-pointed star.)
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Answer: \(180^\circ\)
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Hint 1 of 4
The total is the same for every star, so you may pick a convenient star. But you can also find it with a fact you already know: the angles in a triangle add to \(180^\circ\), and an exterior angle of a triangle equals the sum of the two far interior angles.
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Hint 2 of 4
Each tip of the star is the top angle of a little triangle whose base is one side of the inner pentagon. Build up the five tip angles using triangle facts.
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Hint 3 of 4
Quick way: walk all the way around the star, turning at each of the \(5\) points. Going once around a star, you actually spin around twice, so the turning adds to \(2 \times 360^\circ = 720^\circ\). Each tip angle is \(180^\circ\) minus its turn.
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Approach: Considering a convenient case — total turning around the star
  1. Since every five-pointed star gives the same total, reason about a nice symmetric one. A clean method uses turning.
  2. Imagine an ant walking around the outline of the star and back to where it started, facing the same way. At each of the \(5\) sharp tips it makes a turn. For a star (unlike a normal pentagon) the ant spins around TWICE before getting home, so the turns add up to \(2 \times 360^\circ = 720^\circ\).
  3. At each tip, the turn is \(180^\circ\) minus the tip angle (the sharper the point, the bigger the turn). Adding over all \(5\) tips: \(\sum(180^\circ - \text{tip}) = 720^\circ\).
  4. That is \(5 \times 180^\circ - (\text{sum of tip angles}) = 720^\circ\), so \(900^\circ - (\text{sum of tip angles}) = 720^\circ\), giving sum of tip angles \(= 180^\circ\) for any five-pointed star.
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