πŸ‡ΊπŸ‡Έ AMC 8 ⇄ switch contest
1999 AMC 8

Problem 13

Problem 13 · 1999 AMC 8 Medium
Arithmetic & Operations averagetotals

The average age of the 40 members of a computer science camp is 17 years. There are 20 girls, 15 boys, and 5 adults. If the average age of the girls is 15 and the average age of the boys is 16, what is the average age of the adults?

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Answer: C — 28 years.
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Hint 1 of 2
You can't average the averages β€” averages of different-sized groups don't combine directly. Convert each average back into a TOTAL (average Γ— count), because totals do add.
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Hint 2 of 2
Find the whole camp's total age, subtract the girls' and boys' totals, and what's left is the adults' total. Then divide by 5.
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Approach: averages β†’ totals (totals are what's allowed to add)
  1. Turn averages into sums: whole camp 40 Γ— 17 = 680, girls 20 Γ— 15 = 300, boys 15 Γ— 16 = 240.
  2. Adults' total age = 680 βˆ’ 300 βˆ’ 240 = 140, so their average is 140 Γ· 5 = 28.
  3. Why this transfers: the golden rule for averages is "un-average into totals first." Sums combine and split cleanly; averages don't, because they hide how many people are behind each number.
Another way — balance the deviations from 17:
  1. Measure each group against the overall average of 17. Girls are 2 below (Γ—20 = βˆ’40 total), boys are 1 below (Γ—15 = βˆ’15), so the camp is 55 'age-years' short of 17-each.
  2. The 5 adults must carry that whole +55 surplus above 17: 55 Γ· 5 = 11 above, so 17 + 11 = 28.
  3. This 'see-saw around the mean' view is fast and shows the adults pulling the average up to balance the younger campers.
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