πŸ‡ΊπŸ‡Έ AMC 8 ⇄ switch contest
1992 AJHSME

Problem 11

Problem 11 · 1992 AJHSME Medium
Fractions, Decimals & Percents read-graphpercent
Figure for AJHSME 1992 Problem 11
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Answer: B — 24%.
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Hint 1 of 3
"What percent preferred blue" is blue out of EVERYONE — not blue out of the tallest bar. What's the denominator you actually need?
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Hint 2 of 3
A percent always needs its whole: percent = part ÷ total. Here the total is every bar added together, so read them all before dividing.
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Hint 3 of 3
Line up the bar tops with the frequency scale carefully — each gridline is worth 20.
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Approach: blue's count divided by the grand total of all bars
  1. Read each bar against the scale: Red 50, Blue 60, Brown 40, Pink 60, Green 40. The total surveyed is 50 + 60 + 40 + 60 + 40 = 250.
  2. Blue's share is 60 out of 250: 60 ÷ 250 = 0.24 = 24%.
  3. Why this transfers: the most common percent-from-a-graph mistake is forgetting to total ALL the bars — the part means nothing without its whole. Always build the denominator first.
  4. Sanity check: blue is one of five bars, so a fair share would be 20%. Blue is a little above average height, so a little above 20% — 24% fits.
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